如何在 Apache FOP 1.1 中真正将 fo:inline 个对象放在一起

Question

我有一个作者列表：

<titleStmt>
    <author>GivenName1 Surname1</author>
    <author>GivenName2 Surname2</author>
    <author>GivenName3 Surname3</author>
    <author>GivenName4 Surname4</author>
    <author>GivenName5 Surname5</author>
    <author>GivenName6 Surname6</author>
</titleStmt>

在初步转换为 XSL-FO 之后，我有：

<fo:block font-family="Times New Roman" text-transform="uppercase" text-align="left" font-size="8pt" line-height="11pt" margin-right="5cm">
    <fo:inline keep-together.within-line="always">GivenName1 Surname1</fo:inline>
    <fo:inline keep-together.within-line="always">GivenName2 Surname2</fo:inline>
    <fo:inline keep-together.within-line="always">GivenName3 Surname3</fo:inline>
    <fo:inline keep-together.within-line="always">GivenName4 Surname4</fo:inline>
    <fo:inline keep-together.within-line="always">GivenName5 Surname5</fo:inline>
    <fo:inline keep-together.within-line="always">GivenName6 Surname6</fo:inline>
</fo:block>

我只需要在每条记录之间换行，而不是在记录内部换行（不想拆分 GivenName 和 Surname）。使用 keep-together.within-line，我希望它应该可以工作，但没有。我得到的唯一结果是行溢出了页面边框，就像我将规则应用于整个块容器一样。我在这里遗漏了什么吗？

Answer 1

我用 FOP 1.1 测试了您的块，输出符合预期（多行，仅在姓氏后中断）。

我认为您可能在 fo:block 的祖先中有一个 keep-together.within-line="always" 或 keep-together="always" (*)，从而迫使整个块产生一行。

(*) XSL 1.1 Recommendation，第 5.11 Property Datatypes 节解释说：

keep-together="always" is equivalent to a specification of keep-together.within-line="always" keep-together.within-column="always" keep-together.within-page="always"

Answer 2

这对我来说似乎有点令人讨厌，但添加不间断空格会按预期工作：

<fo:block font-family="Times New Roman" text-transform="uppercase" text-align="left" font-size="8pt" line-height="11pt" margin-right="5cm">
    <fo:inline keep-together.within-line="always">GivenName1&#160;Surname1</fo:inline>
    <fo:inline keep-together.within-line="always">GivenName2&#160;Surname2</fo:inline>
    <fo:inline keep-together.within-line="always">GivenName3&#160;Surname3</fo:inline>
    <fo:inline keep-together.within-line="always">GivenName4&#160;Surname4</fo:inline>
    <fo:inline keep-together.within-line="always">GivenName5&#160;Surname5</fo:inline>
    <fo:inline keep-together.within-line="always">GivenName6&#160;Surname6</fo:inline>
</fo:block>

我使用 XSL 样式表生成它，所以：

<fo:inline>
    <xsl:value-of select="replace(., '\s', '&#160;')"/>
</fo:inline>

如何在 Apache FOP 1.1 中真正将 fo:inline 个对象放在一起

How to really keep together fo:inline objects in Apache FOP 1.1

xsl-fo