带有处理和音频输入的 NullPointerException
NullPointerException with Processing and audio input
我正在处理一个处理草图,我从一个音频文件中获取输入,我将其主频率映射到三个动画 "snakes" 的运动。该代码有时可以正常工作,有时则不能(NullPointerException)!我想这与一些细节有关,我 missing/don 不明白,但我感到困惑,因为我的代码不会每次都中断!!如果您能检查一下并找出问题所在,我将不胜感激!
这是主要草图:
import beads.*;
// sound variables
AudioContext ac;
Gain g;
PowerSpectrum ps;
Frequency f;
String sourceFile;
SamplePlayer player;
float inputFrequency;
float mappedFrequency;
float prevFrequency;
// visual variables
ShapeA shA1;
ShapeA shA2;
ShapeA shA3;
boolean shA1pressed, shA2pressed, shA3pressed;
void setup() {
size(900, 600);
frameRate(30); // doesn't affect sound
inputFrequency = 0;
mappedFrequency = 0;
prevFrequency = 0;
// get sound source
ac = new AudioContext();
sourceFile = sketchPath("") + "data/rite1.mp3";
try {
player = new SamplePlayer(ac, new Sample(sourceFile));
}
catch(Exception e)
{
println("Exception while attempting to load sample!");
e.printStackTrace();
exit();
}
g = new Gain(ac, 2, 0.3);
g.addInput(player);
ac.out.addInput(g);
/* prerequisites for getting main frequency */
ShortFrameSegmenter sfs = new ShortFrameSegmenter(ac);
sfs.addInput(ac.out);
FFT fft = new FFT();
sfs.addListener(fft);
ps = new PowerSpectrum();
fft.addListener(ps);
f = new Frequency(44100.0f);
ps.addListener(f);
ac.out.addDependent(sfs);
/* end of prerequistes */
ac.start();
smooth();
noStroke();
//strokeWeight(2); // affecting the size of a point
shA1 = new ShapeA(3); // random factor affecting angle
shA2 = new ShapeA(6);
shA3 = new ShapeA(8);
shA1pressed = false;
shA2pressed = false;
shA3pressed = false;
}
void draw() {
//background(255);
fill(255,10);
rect(0-10,0-10,width+20,height+20);
text(" Input Frequency: ", -100, -100); // for some reason, needed!!
inputFrequency = f.getFeatures(); // ** THIS IS THE MAIN FREQUENCY **
mappedFrequency = map(inputFrequency,20,2000,0,20); // computational power!
if (shA1pressed) {
shA1.angle();
shA1.display(shA1.angle);
}
if (shA2pressed) {
shA2.angle();
shA2.display(shA2.angle);
}
if (shA3pressed) {
shA3.angle();
shA3.display(shA3.angle);
}
prevFrequency = inputFrequency;
}
void keyPressed() {
if (key == '1') {
if (shA1pressed == false) {
shA1pressed = true;
} else {
shA1pressed = false;
}
}
if (key == '2') {
if (shA2pressed == false) {
shA2pressed = true;
} else {
shA2pressed = false;
}
}
if (key == '3') {
if (shA3pressed == false) {
shA3pressed = true;
} else {
shA3pressed = false;
}
}
}
这里是 ShapeA class:
class ShapeA {
float angleCount = 7;
float stepSize = 3.3;
int i = 0;
float angle = radians(270);
float r;
ArrayList<PVector> points = new ArrayList<PVector>();
ShapeA(float _r) {
// set position of first point
points.add(new PVector(random(width), random(height)));
r = _r;
}
float angle() {
if (prevFrequency <= inputFrequency) {
angle = angle - radians(mappedFrequency*random(r));
} else {
angle = angle + radians(mappedFrequency*random(r));
}
return angle;
}
void display(float _angle) {
PVector point = points.get(i);
fill(0);
ellipse(point.x, point.y, 3, 3);
// add a new point
PVector prevPoint = points.get(points.size()-1);
float x = prevPoint.x + cos(_angle) * stepSize;
float y = prevPoint.y + sin(_angle) * stepSize;
points.add(new PVector(x, y));
// check if shape hits display borders
float a = (floor(random(-angleCount, angleCount)) + 0.5) * 90.0/angleCount;
if (y <= 0) {
angle = a+90;
}
else if (x >= width) {
angle = a+180;
}
else if (y >= height) {
angle = a-90;
}
else if (x <= 0) {
angle = a;
}
i++;
}
}
当我收到错误消息时,这是一条 NullPointerException 消息,突出显示了这一行(在主草图中):
inputFrequency = f.getFeatures(); // ** THIS IS THE MAIN FREQUENCY **
此外,我还注意到,通过删除以下行
text(" Input Frequency: ", -100, -100);
我也收到同样类型的信息,虽然线路没用!
谁能解释一下,为什么会发生这些 "things"?
提前致谢,
- 伊利亚斯
以后,您应该尝试 post 您遇到的任何错误的全文,以及您正在使用的库的链接。
但我有一个理论:
Frequency
class has a function called getFeatures()
其中returns一个Float
。
注意 Float
中的大写字母 F。它是一个对象,而不是原始的小写 float
。 这意味着它可以为空。
然后当你将它转换为小写 float
(通过拆箱)时,你会得到一个 NullPointerException
因为它不知道如何将 null
转换为 float
.
我不知道为什么那个函数返回 null;您必须检查文档并为此进行一些调试。但是您要么必须追查原因并防止它发生,要么必须添加一个空检查,仅当该值不为空时才输入您的代码。像这样:
Float returnedFrequency = f.getFeatures();
if(returnedFrequency != null){
inputFrequency = returnedFrequency;
//rest of your code
至于为什么需要text()
这个功能,我猜是巧合吧。我想 可能 它对 Frequency
class 中需要发生的任何事情都造成了足够的延迟,但这个延迟应该只有几毫秒,所以我真的怀疑是这样的。无论如何,如果您追查 null 的原因或添加 null 检查,这将成为一个有争议的问题。
顺便说一下,您在此处 post 编写了一堆额外的代码 - 您的问题与键盘无关,因此所有这些代码只会使您的问题变得混乱。下次,尝试创建一个 MCVE- 我们可以 运行 得到相同错误的几行,而不是你的整个草图。祝你好运。
我正在处理一个处理草图,我从一个音频文件中获取输入,我将其主频率映射到三个动画 "snakes" 的运动。该代码有时可以正常工作,有时则不能(NullPointerException)!我想这与一些细节有关,我 missing/don 不明白,但我感到困惑,因为我的代码不会每次都中断!!如果您能检查一下并找出问题所在,我将不胜感激! 这是主要草图:
import beads.*;
// sound variables
AudioContext ac;
Gain g;
PowerSpectrum ps;
Frequency f;
String sourceFile;
SamplePlayer player;
float inputFrequency;
float mappedFrequency;
float prevFrequency;
// visual variables
ShapeA shA1;
ShapeA shA2;
ShapeA shA3;
boolean shA1pressed, shA2pressed, shA3pressed;
void setup() {
size(900, 600);
frameRate(30); // doesn't affect sound
inputFrequency = 0;
mappedFrequency = 0;
prevFrequency = 0;
// get sound source
ac = new AudioContext();
sourceFile = sketchPath("") + "data/rite1.mp3";
try {
player = new SamplePlayer(ac, new Sample(sourceFile));
}
catch(Exception e)
{
println("Exception while attempting to load sample!");
e.printStackTrace();
exit();
}
g = new Gain(ac, 2, 0.3);
g.addInput(player);
ac.out.addInput(g);
/* prerequisites for getting main frequency */
ShortFrameSegmenter sfs = new ShortFrameSegmenter(ac);
sfs.addInput(ac.out);
FFT fft = new FFT();
sfs.addListener(fft);
ps = new PowerSpectrum();
fft.addListener(ps);
f = new Frequency(44100.0f);
ps.addListener(f);
ac.out.addDependent(sfs);
/* end of prerequistes */
ac.start();
smooth();
noStroke();
//strokeWeight(2); // affecting the size of a point
shA1 = new ShapeA(3); // random factor affecting angle
shA2 = new ShapeA(6);
shA3 = new ShapeA(8);
shA1pressed = false;
shA2pressed = false;
shA3pressed = false;
}
void draw() {
//background(255);
fill(255,10);
rect(0-10,0-10,width+20,height+20);
text(" Input Frequency: ", -100, -100); // for some reason, needed!!
inputFrequency = f.getFeatures(); // ** THIS IS THE MAIN FREQUENCY **
mappedFrequency = map(inputFrequency,20,2000,0,20); // computational power!
if (shA1pressed) {
shA1.angle();
shA1.display(shA1.angle);
}
if (shA2pressed) {
shA2.angle();
shA2.display(shA2.angle);
}
if (shA3pressed) {
shA3.angle();
shA3.display(shA3.angle);
}
prevFrequency = inputFrequency;
}
void keyPressed() {
if (key == '1') {
if (shA1pressed == false) {
shA1pressed = true;
} else {
shA1pressed = false;
}
}
if (key == '2') {
if (shA2pressed == false) {
shA2pressed = true;
} else {
shA2pressed = false;
}
}
if (key == '3') {
if (shA3pressed == false) {
shA3pressed = true;
} else {
shA3pressed = false;
}
}
}
这里是 ShapeA class:
class ShapeA {
float angleCount = 7;
float stepSize = 3.3;
int i = 0;
float angle = radians(270);
float r;
ArrayList<PVector> points = new ArrayList<PVector>();
ShapeA(float _r) {
// set position of first point
points.add(new PVector(random(width), random(height)));
r = _r;
}
float angle() {
if (prevFrequency <= inputFrequency) {
angle = angle - radians(mappedFrequency*random(r));
} else {
angle = angle + radians(mappedFrequency*random(r));
}
return angle;
}
void display(float _angle) {
PVector point = points.get(i);
fill(0);
ellipse(point.x, point.y, 3, 3);
// add a new point
PVector prevPoint = points.get(points.size()-1);
float x = prevPoint.x + cos(_angle) * stepSize;
float y = prevPoint.y + sin(_angle) * stepSize;
points.add(new PVector(x, y));
// check if shape hits display borders
float a = (floor(random(-angleCount, angleCount)) + 0.5) * 90.0/angleCount;
if (y <= 0) {
angle = a+90;
}
else if (x >= width) {
angle = a+180;
}
else if (y >= height) {
angle = a-90;
}
else if (x <= 0) {
angle = a;
}
i++;
}
}
当我收到错误消息时,这是一条 NullPointerException 消息,突出显示了这一行(在主草图中):
inputFrequency = f.getFeatures(); // ** THIS IS THE MAIN FREQUENCY **
此外,我还注意到,通过删除以下行
text(" Input Frequency: ", -100, -100);
我也收到同样类型的信息,虽然线路没用!
谁能解释一下,为什么会发生这些 "things"?
提前致谢, - 伊利亚斯
以后,您应该尝试 post 您遇到的任何错误的全文,以及您正在使用的库的链接。
但我有一个理论:
Frequency
class has a function called getFeatures()
其中returns一个Float
。
注意 Float
中的大写字母 F。它是一个对象,而不是原始的小写 float
。 这意味着它可以为空。
然后当你将它转换为小写 float
(通过拆箱)时,你会得到一个 NullPointerException
因为它不知道如何将 null
转换为 float
.
我不知道为什么那个函数返回 null;您必须检查文档并为此进行一些调试。但是您要么必须追查原因并防止它发生,要么必须添加一个空检查,仅当该值不为空时才输入您的代码。像这样:
Float returnedFrequency = f.getFeatures();
if(returnedFrequency != null){
inputFrequency = returnedFrequency;
//rest of your code
至于为什么需要text()
这个功能,我猜是巧合吧。我想 可能 它对 Frequency
class 中需要发生的任何事情都造成了足够的延迟,但这个延迟应该只有几毫秒,所以我真的怀疑是这样的。无论如何,如果您追查 null 的原因或添加 null 检查,这将成为一个有争议的问题。
顺便说一下,您在此处 post 编写了一堆额外的代码 - 您的问题与键盘无关,因此所有这些代码只会使您的问题变得混乱。下次,尝试创建一个 MCVE- 我们可以 运行 得到相同错误的几行,而不是你的整个草图。祝你好运。