获取以 '(' - PHP 正则表达式开头的单词

Question

hy my name is mike(mike)
hi my name is julia (julia)
martin(martin) is 27 years old.
michael (michael) and joseph(joseph) are good friens

我有一行，每个名字都在括号内重复。有的括号与名称统一，有的用白色space分隔。我希望所有括号都用 just 1 whitespace 分隔。就这样。

hy my name is mike (mike)
hi my name is julia (julia)
martin (martin) is 27 years old.
michael (michael) and joseph (joseph) are good friens

我试过了

preg_replace('/\((\S*)\)/', ' ()', $string);

它很好用，但是我想问一个小问题。

它分隔已经分隔的括号名称。因此它们被两个白色spaces

分开

对我来说，这个 ^ 正则表达式 /^\((\S*)\)/ 应该可以解决问题，但是它给了我错误。感谢帮助

Answer 1

使用前导边界。

\b\((\S*)\)

演示：https://regex101.com/r/qF2kT5/1

PHP:

$string = 'hy my name is mike(mike)
hi my name is julia (julia)
martin(martin) is 27 years old.
michael (michael) and joseph(joseph) are good friens';
echo preg_replace('/\b\((\S*)\)/', ' ()', $string);

输出：

hy my name is mike (mike)
hi my name is julia (julia)
martin (martin) is 27 years old.
michael (michael) and joseph (joseph) are good friens

^ 用于字符串或行的开头（如果使用 m 修饰符）。

Answer 2

好吧，您可以使用此正则表达式轻松格式化您的字符串 /(?<!\s)[(]/si

PHP code snippet.

$subject =
    "hy my name is mike(mike)
hi my name is julia (julia)
martin(martin) is 27 years old.
michael (michael) and joseph(joseph) are good friens";

$result = preg_replace('/(?<!\s)[(]/si', ' (', $subject);
print($result);

输出：

hy my name is mike (mike)
hi my name is julia (julia)
martin (martin) is 27 years old.
michael (michael) and joseph (joseph) are good friens

获取以 '(' - PHP 正则表达式开头的单词

Get words begin with '(' - PHP regex

php

regex

preg-replace