Knex Js returns 与原始 SQL 不同的输出
Knex Js returns a different output from raw SQL
我有两个 table。一个是类别 table,另一个是带有类别外键的项目 table(一个类别可以有多个项目)
我正在尝试公开以下代码中的所有项目
router.route('/projects')
.get(function(req,res){
//knex('projects').select(['projects.id','projects.name','projects.category_id','categories.name']).innerJoin('categories','projects.category_id','categories.id')
knex.from('projects').innerJoin('categories','projects.category_id','categories.id')
.then(function(collection){
console.log(collection);
res.json({
error:false,
data: collection
})
})
.catch(function(err){
res.json({
error:true,
data:{
message:err.message
}
})
})
})
两个 knex 语句 return 几乎类似于下面的截断输出
{
"error": false,
"data": [
{
"id": 1,
"name": "Music",
"category_id": 1,
"created_at": 1458126413858
},
{
"id": 2,
"name": "Science",
"category_id": 2,
"created_at": 1458126413858
}
]
}
然而,原始 SQL 似乎是正确的
select * from "projects" inner join "categories" on "projects"."category_id" = "categories"."id"
或
select "projects"."id", "projects"."name", "projects"."category_id", "categories"."name" from "projects" inner join "categories" on "projects"."category_id" = "categories"."id"
运行 以上分别在 sqlite 上的语句似乎 return 整个 table 结果
knex 语句哪里出错了?
供参考,这是架构
项目table
var table = (table) => {
table.increments().primary();
table.string('name');
table.integer('category_id').references('categories.id');
table.timestamp('created_at').defaultTo(Date.now());
}
类别table
var table = (table) => {
table.increments().primary();
table.string('name');
table.timestamp('created_at').defaultTo(Date.now());
}
通过使用如下列名称的别名解决了这个问题
knex('projects').select(['projects.id as projectId','projects.name as projectName','projects.category_id','categories.name as categoryName']).innerJoin('categories','projects.category_id','categories.id')
我有两个 table。一个是类别 table,另一个是带有类别外键的项目 table(一个类别可以有多个项目)
我正在尝试公开以下代码中的所有项目
router.route('/projects')
.get(function(req,res){
//knex('projects').select(['projects.id','projects.name','projects.category_id','categories.name']).innerJoin('categories','projects.category_id','categories.id')
knex.from('projects').innerJoin('categories','projects.category_id','categories.id')
.then(function(collection){
console.log(collection);
res.json({
error:false,
data: collection
})
})
.catch(function(err){
res.json({
error:true,
data:{
message:err.message
}
})
})
})
两个 knex 语句 return 几乎类似于下面的截断输出
{
"error": false,
"data": [
{
"id": 1,
"name": "Music",
"category_id": 1,
"created_at": 1458126413858
},
{
"id": 2,
"name": "Science",
"category_id": 2,
"created_at": 1458126413858
}
]
}
然而,原始 SQL 似乎是正确的
select * from "projects" inner join "categories" on "projects"."category_id" = "categories"."id"
或
select "projects"."id", "projects"."name", "projects"."category_id", "categories"."name" from "projects" inner join "categories" on "projects"."category_id" = "categories"."id"
运行 以上分别在 sqlite 上的语句似乎 return 整个 table 结果
knex 语句哪里出错了?
供参考,这是架构
项目table
var table = (table) => {
table.increments().primary();
table.string('name');
table.integer('category_id').references('categories.id');
table.timestamp('created_at').defaultTo(Date.now());
}
类别table
var table = (table) => {
table.increments().primary();
table.string('name');
table.timestamp('created_at').defaultTo(Date.now());
}
通过使用如下列名称的别名解决了这个问题
knex('projects').select(['projects.id as projectId','projects.name as projectName','projects.category_id','categories.name as categoryName']).innerJoin('categories','projects.category_id','categories.id')