如何从多个列(在 sql 中)创建交叉表(在 crystal 中)

How to create a cross tab (in crystal) from multiple columns (in sql)

我在 SQL 中有 5 列需要在 Crystal 中变成交叉表。

这是我的:

 Key  | RELATIONSHIP    | DISABLED | LIMITED | RURAL | IMMIGRANT
-----------------------------------------------------------------
  1   | Other Dependent |   Yes    |   No    |  No   |   No
  2   | Victim/Survivor |   No     |   No    |  No   |   No
  3   | Victim/Survivor |   Yes    |   No    |  No   |   No
  4   | Child           |   No     |   No    |  No   |   No
  5   | Victim/Survivor |   No     |   No    |  No   |   No
  6   | Victim/Survivor |   No     |   No    |  No   |   No
  7   | Child           |   No     |   No    |  No   |   No
  8   | Victim/Survivor |   No     |   Yes   |  Yes  |   Yes
  9   | Child           |   No     |   Yes   |  Yes  |   Yes
  10  | Child           |   No     |   Yes   |  Yes  |   Yes

这就是我希望交叉表的样子(键上的不同计数):

               | Victim/Survivor | Child | Other Dependent | Total |
    --------------------------------------------------------------
   | DISABLED  |       1         |   0   |        1        |   2   |
    --------------------------------------------------------------
   | LIMITED   |       1         |   2   |        0        |   3   |
    --------------------------------------------------------------    
   | RURAL     |       1         |   2   |        0        |   3   |
    --------------------------------------------------------------    
   | IMMIGRANT |       1         |   2   |        0        |   3   |
    --------------------------------------------------------------    
   | TOTAL     |       4         |   6   |        1        |   11  |
    --------------------------------------------------------------

我在 Crystal 中使用了这个公式来合并 4 列(字段名称 = {@OTHERDEMO})...

IF {TABLE.DISABLED} = "YES" THEN "DISABLED"  ELSE
IF {TABLE.LIMITED} = "YES" THEN "LIMITED" ELSE
IF {TABLE.IMMIGRANT} = "YES" THEN "IMMIGRANT" ELSE
IF {TABLE.RURAL} = "YES" THEN "RURAL"

...然后用@OTHERDEMO 作为行,RELATIONSHIP 作为列,在 KEY 上有不同的计数:

问题是,一旦 crystal 命中第一个 "Yes",它就会停止计数,因此无法在交叉表中正确分类。所以我得到一个 table,它首先计算 DISABILITY 并给出正确的显示,然后计算 Limited 并提供一些信息,然后转储所有其他内容。

以前做过多个条件公式...

IF {TABLE.DISABLED} = "YES" AND {TABLE.RELATIONSHIP} = "Victim/Survivor" THEN {TABLE.KEY} ELSE {@NULL} 
(the @null formula is because Crystal, notoriously, gets confused with nulls.)

...然后对Key进行了不同的计数,最后在页脚中求和。

我相信还有另一种方法可以做到这一点。任何 help/ideas 将不胜感激。

如果您将那些 "DEMO" 列逆透视为行,这将使交叉表变得非常容易...

select 
  u.[Key], 
  u.[RELATIONSHIP], 
  u.[DEMO]
from 
  Table1
  unpivot (
    [b] for [DEMO] in ([DISABLED], [LIMITED], [RURAL], [IMMIGRANT])
  ) u
where
    u.[b] = 'Yes'

SqlFiddle

或者,如果您停留在 SQL2000 兼容级别,您可以手动反转 Yes 值...

select [Key], [REALTIONSHIP], [DEMO] = cast('DISABLED' as varchar(20)) 
from Table1 
where [DISABLED] = 'Yes'
union
select [Key], [REALTIONSHIP], [DEMO] = cast('LIMITED' as varchar(20)) 
from Table1 
where [LIMITED] = 'Yes'
union
select [Key], [REALTIONSHIP], [DEMO] = cast('RURAL' as varchar(20)) 
from Table1 
where [RURAL] = 'Yes'
union
select [Key], [REALTIONSHIP], [DEMO] = cast('IMMIGRANT' as varchar(20)) 
from Table1 
where [IMMIGRANT] = 'Yes'

对于交叉表,在键列上使用计数(也称为行计数),在行上使用 [DEMO],在列上使用 [RELATIONSHIP]。