是否可以使用变量动态更改代码中 class 的名称?
Is it possible to change dynamically the name of the class in the code with a variable?
我有这个功能:
- (NSString*) getId:(id)id_field withColumn:(int)test_column withTable:(NSString *) tableName //renvoyer le label
{
NSError *error = nil;
NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];
NSEntityDescription *entity = [NSEntityDescription entityForName:tableName
inManagedObjectContext:managedObjectContext];
[fetchRequest setEntity:entity];
NSArray *fetchedObjects = [managedObjectContext executeFetchRequest:fetchRequest error:&error];
for (<tableName of class> *info in fetchedObjects)
{
if (test_column == LBL2_CLMN)
{
NSLog(@"info.id :%@", info.id);
if ([info.id compare:id_field] == NSOrderedSame)
NSLog(@"info.id :%@", info.label1);
return info.label1;
}
else if (test_column == LBL1_CLMN)
{
if ([info.id compare:id_field] == NSOrderedSame)
return info.label2;
}
}
return @"";
}
如何使用变量 tableName 更改 class 的名称以实例化 *info?
可能吗?
不是直接的,而是因为 executeFetchRequest
returns NSManagedObject
在重复循环中使用它并将对象转换为 if - else
中预期的 class范围。
NSArray *fetchedObjects = [managedObjectContext executeFetchRequest:fetchRequest error:&error];
for (NSManagedObject *object in fetchedObjects)
{
if (test_column == LBL2_CLMN)
{
ClassA *info = (ClassA *)object;
NSLog(@"info.id :%@", info.id);
if ([info.id compare:id_field] == NSOrderedSame) {
NSLog(@"info.id :%@", info.label1);
return info.label1;
}
}
else if (test_column == LBL1_CLMN)
{
ClassB *info = (ClassB *)object;
if ([info.id compare:id_field] == NSOrderedSame)
return info.label2;
}
}
return @"";
而且我猜第二个 if
子句中缺少一对大括号。
你必须使用 NSClassFromString 方法,然后使用 id 关键字来获取对象:
NSError *error = nil;
NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];
NSEntityDescription *entity = [NSEntityDescription entityForName:table inManagedObjectContext:managedObjectContext];
[fetchRequest setEntity:entity];
NSArray *fetchedObjects = [managedObjectContext executeFetchRequest:fetchRequest error:&error];
Class theClass = NSClassFromString(table);
id info = [theClass new];
for (info in fetchedObjects)
{
.....
}
return @"";
我有这个功能:
- (NSString*) getId:(id)id_field withColumn:(int)test_column withTable:(NSString *) tableName //renvoyer le label
{
NSError *error = nil;
NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];
NSEntityDescription *entity = [NSEntityDescription entityForName:tableName
inManagedObjectContext:managedObjectContext];
[fetchRequest setEntity:entity];
NSArray *fetchedObjects = [managedObjectContext executeFetchRequest:fetchRequest error:&error];
for (<tableName of class> *info in fetchedObjects)
{
if (test_column == LBL2_CLMN)
{
NSLog(@"info.id :%@", info.id);
if ([info.id compare:id_field] == NSOrderedSame)
NSLog(@"info.id :%@", info.label1);
return info.label1;
}
else if (test_column == LBL1_CLMN)
{
if ([info.id compare:id_field] == NSOrderedSame)
return info.label2;
}
}
return @"";
}
如何使用变量 tableName 更改 class 的名称以实例化 *info?
可能吗?
不是直接的,而是因为 executeFetchRequest
returns NSManagedObject
在重复循环中使用它并将对象转换为 if - else
中预期的 class范围。
NSArray *fetchedObjects = [managedObjectContext executeFetchRequest:fetchRequest error:&error];
for (NSManagedObject *object in fetchedObjects)
{
if (test_column == LBL2_CLMN)
{
ClassA *info = (ClassA *)object;
NSLog(@"info.id :%@", info.id);
if ([info.id compare:id_field] == NSOrderedSame) {
NSLog(@"info.id :%@", info.label1);
return info.label1;
}
}
else if (test_column == LBL1_CLMN)
{
ClassB *info = (ClassB *)object;
if ([info.id compare:id_field] == NSOrderedSame)
return info.label2;
}
}
return @"";
而且我猜第二个 if
子句中缺少一对大括号。
你必须使用 NSClassFromString 方法,然后使用 id 关键字来获取对象:
NSError *error = nil;
NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];
NSEntityDescription *entity = [NSEntityDescription entityForName:table inManagedObjectContext:managedObjectContext];
[fetchRequest setEntity:entity];
NSArray *fetchedObjects = [managedObjectContext executeFetchRequest:fetchRequest error:&error];
Class theClass = NSClassFromString(table);
id info = [theClass new];
for (info in fetchedObjects)
{
.....
}
return @"";