PHP 以键作为文件创建日期的数组

PHP array with keys as file's creation date

所以我有一个文件夹,path/to/folder,文件夹中有文件夹,文件夹中有文件,等等——所有这些都在一个文件夹中 path/to/folder。我想将所有图像的所有名称(.gif、.png、.jpg、.jpeg 等)存储在这个文件夹中 path/to/folder 就像这样(我的尝试):

$arr = glob("path/to/folder/*.jpg");//not sure how to specify or "|" here

我还需要与图像元数据(创建日期)关联的日期,如下所示(请参阅下面的伪代码):

foreach($arr as $a){
    $date_of_a = function_getting_dates_of_a($a);//filectime?
    $newArr[$date_of_a]=function_getting_names_of_a($a);//names are filtered by a pattern
                      //^^^^^^^^^^^^^^^^^^^^^^^^^^^I've already created this.
}

这样我就可以拥有相同的名称 values 和不同的 keys,这将是日期,所以两个同名的和-相同日期对(或元组,取决于重复次数)将压缩为一个唯一的名称-日期项。例如,

2016-01-01 => path/to/folder/.../name1.jpg//*duplicate name-date pair
2016-01-02 => path/to/folder/.../name2.jpg
2016-01-01 => path/to/folder/.../name1.jpg//*duplicate name-date pair
2016-01-02 => path/to/folder/.../name1.jpg

会将数组缩减为

2016-01-01 => path/to/folder/.../name1.jpg//*only one now
2016-01-02 => path/to/folder/.../name2.jpg
2016-01-02 => path/to/folder/.../name1.jpg

这里,/.../,意思是"any number of folders within path/to/folder"。我正在处理的数据暗示 2016-01-01 => path/to/folder/.../name1.jpg2016-01-02 => path/to/folder/.../name1.jpg 是在不同时间制作的两个相同的对象。最后,我想能够使用 array_count_values.

计算每个名称的实例数量

尝试

<?php

    $myArray = glob("path/to/folder/*.jpg");
    foreach($myArray as $item){
        $date = filectime($item);//What if no date? Is that possible?
        if(preg_match('/PATTERN/',$item,$match)==1){
            $newArr[$date]=current($match);
        }
    }
    array_count_values($newArr);
    <!-- CODE TO GRAPH ITEMS BY FREQUENCY-->
?>

以下代码应创建一个日期时间键数组:

<?php

$myArray = glob("/*.jpg");
$newArr = array();
foreach($myArray as $item){
    $timestamp = filectime($item);
    if ($timestamp === false) {
        continue;
    }
    $date = new \DateTime();
    $date->setTimestamp($timestamp);
    $formattedDate = $date->format('m-d-Y');
    $newArr[$formattedDate]=$item;
}
array_count_values($newArr);
echo "<pre>";
print_r($newArr);
//<!-- CODE TO GRAPH ITEMS BY FREQUENCY-->

这是我在同一天创建多个 JPG 文件时打印出来的内容:

Array
(
    [04-12-2016] => sdfdsf.jpg
)

关于递归查找文件,你可以试试我在自己的个人项目中使用过的功能:

function findDirectories($rootPath) {
    $directories = array();
    foreach (glob($rootPath . "/*", GLOB_ONLYDIR) as $directory) {
        $directories[] = $directory;
    }
    return $directories;
}

function findFiles($rootPath, $extension) {
    $files = array();
    foreach (glob($rootPath . "/*.$extension") as $file) {
        $files[] = $file;
    }
    return $files;
}

function findFilesRecursive($rootPath,$extension) {
    $files = findFiles($rootPath,$extension);
    $directories = findDirectories($rootPath);
    if (!empty($directories)) {
        foreach ($directories as $key=>$directory) {
            $foundFiles = findFilesRecursive($directory,$extension);
            foreach ($foundFiles as $foundFile) {
                $files[] = $foundFile;
            }
        }
    }
    return $files;
}