从 Mediastore 从 audio_genres_map 获取 genre_id 和 audio_id

Question

我想在一次查询中从媒体存储中检索整个 audio_genres_map table。我有所有的音频信息和流派信息，但缺少的部分是映射。我能够在多个查询中做到这一点。我想实现一个查询

Answer 1

使用以下查询设法解决了这个问题

String[] genresProjection = {
            Audio.Genres.Members.AUDIO_ID,
            Audio.Genres.Members.GENRE_ID
    };
context.getContentResolver().query(Uri.parse("content://media/external/audio/genres/all/members"), genresProjection, null, null, null);

Answer 2

或使用 MediaStore.Audio

检索所有流派

    public Cursor getGenrecursor(Context context) {
    ContentResolver cr = context.getContentResolver();
    Uri uri = MediaStore.Audio.Genres.getContentUri("external");
    String genre = MediaStore.Audio.Genres.NAME;
    final String[] columns = { "_id", genre };
    return  cr.query(uri, columns, null, null, null);
}

Answer 3

并扩展您的问题，使用 genre_id 返回更多详细信息

        public Cursor getgenre_TrackCursor(Context context, long genreID) {
    final String track_id = MediaStore.Audio.Genres.Members._ID;
    final String track_no = MediaStore.Audio.Genres.Members.TRACK;
    final String track_name = MediaStore.Audio.Genres.Members.TITLE;
    final String artist = MediaStore.Audio.Genres.Members.ARTIST;
    final String duration = MediaStore.Audio.Genres.Members.DURATION;
    final String album = MediaStore.Audio.Genres.Members.ALBUM;
    final String composer = MediaStore.Audio.Genres.Members.COMPOSER;
    final String year = MediaStore.Audio.Genres.Members.YEAR;
    final String path = MediaStore.Audio.Genres.Members.DATA;
    final ContentResolver resolve = context.getContentResolver();
    Uri uri = MediaStore.Audio.Genres.Members.getContentUri("external",
            genreID);
    final String[] columns = { track_id, track_no, artist, track_name,
            album, duration, year };
    return resolve.query(uri, columns, null, null, null);
}

从 Mediastore 从 audio_genres_map 获取 genre_id 和 audio_id

get genre_id and audio_id from audio_genres_map from mediastore

android

mediastore