class 指针的动态数组
Dynamic array of class pointers
我正在尝试创建一个指向 class、ElectricityBill
.
实例的动态指针数组
我目前的方法是创建一个 ElectricityBills 的动态数组(目前什么都没有),然后创建一个 ElectricityBill 的单个实例,创建另一组 ElectricityBills,这次大小更大,复制旧动态的所有实例跨越数组,在末尾添加新的。
我试过的代码如下
// Define the dyn array
int EBcount = 0;
ElectricityBill **EB = new ElectricityBill*[EBcount];
// Create a temp instance and input the data
ElectricityBill *tempEB = new ElectricityBill;
std::cin >> *tempEB;
std::cout << *tempEB << std::endl;
// Create a new dyn array and copy the instances accross
EBcount++;
ElectricityBill **temp = new ElectricityBill*[EBcount];
for (int i = 0; i < EBcount-1; i++) {
temp[i] = EB[i];
}
// Append the new instance at the end and delete the old array
temp[EBcount-1] = tempEB;
delete [] EB;
EB = temp;
std::cout << temp[0] << std::endl;
std::cout << EB[0] << std::endl;
输出为
E;name;1;2;3;acc;add;1/1/2000;1/2/2000;22.721;2.2721
0x100500000
0x100500000
值得注意的是,我在 class 定义中重载了运算符 <<
和 >>
。 >>
运算符提示用户输入数据并将输入数据存储在 class 的私有变量部分,<<
运算符的构建方式如下:
std::ostream& operator<<(std::ostream &stream, ElectricityBill &printStream) {
stream << "E;"
<< printStream.billerName << ";"
<< printStream.billerCode << ";"
<< printStream.referenceNumber << ";"
<< printStream.accountNumber << ";"
<< printStream.accountName << ";"
<< printStream.address << ";"
<< printStream.periodStartDate.day << "/" << printStream.periodStartDate.month << "/" << printStream.periodStartDate.year << ";"
<< printStream.periodDueDate.day << "/" << printStream.periodDueDate.month << "/" << printStream.periodDueDate.year << ";"
<< printStream.amountDue << ";"
<< printStream.totalGST;
return stream;
}
由于某种原因,输出正在输出内存地址而不是预期的数据。为什么会发生这种情况,我该如何解决?
您的重载运算符接受对 ElectricityBill 的引用,但您似乎提供了一个指针。因此,正在使用 <<
的默认实现,它打印内存位置。尝试:
std::cout << *temp[0] << std::endl;
std::cout << *EB[0] << std::endl;
我正在尝试创建一个指向 class、ElectricityBill
.
我目前的方法是创建一个 ElectricityBills 的动态数组(目前什么都没有),然后创建一个 ElectricityBill 的单个实例,创建另一组 ElectricityBills,这次大小更大,复制旧动态的所有实例跨越数组,在末尾添加新的。
我试过的代码如下
// Define the dyn array
int EBcount = 0;
ElectricityBill **EB = new ElectricityBill*[EBcount];
// Create a temp instance and input the data
ElectricityBill *tempEB = new ElectricityBill;
std::cin >> *tempEB;
std::cout << *tempEB << std::endl;
// Create a new dyn array and copy the instances accross
EBcount++;
ElectricityBill **temp = new ElectricityBill*[EBcount];
for (int i = 0; i < EBcount-1; i++) {
temp[i] = EB[i];
}
// Append the new instance at the end and delete the old array
temp[EBcount-1] = tempEB;
delete [] EB;
EB = temp;
std::cout << temp[0] << std::endl;
std::cout << EB[0] << std::endl;
输出为
E;name;1;2;3;acc;add;1/1/2000;1/2/2000;22.721;2.2721
0x100500000
0x100500000
值得注意的是,我在 class 定义中重载了运算符 <<
和 >>
。 >>
运算符提示用户输入数据并将输入数据存储在 class 的私有变量部分,<<
运算符的构建方式如下:
std::ostream& operator<<(std::ostream &stream, ElectricityBill &printStream) {
stream << "E;"
<< printStream.billerName << ";"
<< printStream.billerCode << ";"
<< printStream.referenceNumber << ";"
<< printStream.accountNumber << ";"
<< printStream.accountName << ";"
<< printStream.address << ";"
<< printStream.periodStartDate.day << "/" << printStream.periodStartDate.month << "/" << printStream.periodStartDate.year << ";"
<< printStream.periodDueDate.day << "/" << printStream.periodDueDate.month << "/" << printStream.periodDueDate.year << ";"
<< printStream.amountDue << ";"
<< printStream.totalGST;
return stream;
}
由于某种原因,输出正在输出内存地址而不是预期的数据。为什么会发生这种情况,我该如何解决?
您的重载运算符接受对 ElectricityBill 的引用,但您似乎提供了一个指针。因此,正在使用 <<
的默认实现,它打印内存位置。尝试:
std::cout << *temp[0] << std::endl;
std::cout << *EB[0] << std::endl;