套接字不接受字符串

Question

这是我的代码：

public class EchoServer {

    ServerSocket ss;
    Socket s;
    DataInputStream din;
    DataOutputStream dout;

    public EchoServer() 
    {
        try
        {
            System.out.println("server started");
            //ss = new ServerSocket(0);
            //System.out.println("listening on port: " + ss.getLocalPort());
            ss = new ServerSocket(49731);
            s = ss.accept();
            System.out.println(s);
            System.out.println("connected");
            din = new DataInputStream(s.getInputStream());
            dout = new DataOutputStream(s.getOutputStream());
            Server_chat();
            ss.close();
        }
        catch(Exception e)
        {
            System.out.println(e);
        }
    }

    public static void main(String[] args) {
        new EchoServer();
    }

    public void Server_chat() throws IOException {

        String str;
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in ));
        do
        {
            System.out.println("enter a string");
            str = br.readLine();
            System.out.println("str " + din.readUTF());
            dout.flush();            
        }
        while(!str.equals("stop"));
    }
}

我通过端口号验证了 49731 端口。 0 更早得到这个端口。

当我在 Netbeans 上运行上面的代码时，输出显示 "server started" 然后它继续运行ning 即使它应该显示已连接和我提供的输入的其余部分。

Answer 1

And then it keeps on running even though it should show connected and rest of the input I provide.

为什么要继续打印 'connected'？

s=ss.accept();

In this line you are: listens for a connection to be made to this socket and accepts it. The method blocks until a connection is made.

accept 方法将等待连接到他的客户端。所以你需要提供一个连接到服务器的客户端。否则他会一直等下去！

有关如何在 java 中使用套接字的一些示例，请参阅 here and here。

有关 accept() 的更多信息，请阅读 here

套接字不接受字符串

Socket won't accept the strings

java

sockets

networking

serversocket