如何使用 preg_replace 将子字符串替换为数组中的字符串？ (PHP)

Question

我有一个包含这些值的数据数组：

Array
(
    [id] => 1
    [myid] => 9
    [date] => 2014-01-30
    [user] => 17
    [reason] => some text here...
)

这个字符串包含引用数据数组索引的数字：

$columns = '(0) as "id",(1) as "myid",(2) as "date",(3) as "user",(4) as "reason"';

是否可以将括号中的数字更改为数组中的适当值？

我知道如何使用 (string) preg_replace( (array) $patterns, (array) $replacements, (string) $subject) 但完全不知道如何解决这个问题。

理想情况下，结果字符串如下所示：

'1' as "id",'9'  as "myid",'2014-01-30'  as "date",'17'  as "user",'some text here...'  as "reason"

Answer 1

只需使用 str_replace 的循环。遍历数组，使用括号中的循环索引作为搜索字符串并将其替换为相应的值。

Answer 2

array_flip is your saviour

直接来自文档

<?php
$input = array("oranges", "apples", "pears");
$flipped = array_flip($input);

print_r($flipped);
?>

上面的例子会输出：

Array
(
    [oranges] => 0
    [apples] => 1
    [pears] => 2
)

Answer 3

你可以用一个简单的 foreach 循环来完成：

$info = array(
    'id' => 1,
    'myid' => 9,
    'date' => '2014-01-30',
    'user' => 17,
    'reason' => 'some text here...'
);

$columns = '(0) as "id",(1) as "myid",(2) as "date",(3) as "user",(4) as "reason"';

foreach (array_values($info) as $key => $value) {
    $columns = str_replace(
        '(' . $key . ')',
        str_pad($value, strlen($value) + 2, "'", STR_PAD_BOTH),
        $columns
    );
}

echo $columns;

Answer 4

使用preg_replace_callback和str_replace函数的解决方案：

$columns = '(0) as "id",(1) as "myid",(2) as "date",(3) as "user",(4) as "reason"';

// $arr is your initial array
$result = preg_replace_callback(
                "/(\(\d\)) as \"(\w+?)\",?/i",
                function ($maches) use($arr){
                     return str_replace([$maches[1]], "'". $arr[$maches[2]]. "'", $maches[0]);
                },
                $columns);

print_r($result);

输出：

'1' as "id",'9' as "myid",'2014-01-30' as "date",'17' as "user",'some text here...' as "reason"

Answer 5

您只需使用一些 PHP 库函数即可。

$info = array(
    'id' => 1,
    'myid' => 9,
    'date' => '2014-01-30',
    'user' => 17,
    'reason' => 'some text here...'
);

$columns = '(0) as "id",(1) as "myid",(2) as "date",(3) as "user",(4) as "reason"';

$new_Arr = array();
$column_arr = explode(",", $columns);
foreach($column_arr as $values){
    $arr = explode(" as ", $values);
    $new_Arr[] = "'".$info[trim($arr[1], '"')]."' as ".$arr[1];
}

echo implode(",", $new_Arr) //'1' as "id",'9' as "myid",'2014-01-30' as "date",'17' as "user",'some text here...' as "reason"

如何使用 preg_replace 将子字符串替换为数组中的字符串？ (PHP)

How to replace substrings with strings from array using preg_replace? (PHP)

php

arrays

string

preg-replace