使用 Mockito 调用 Retrofit 2 api 的单元测试
Unit Test of Retrofit 2 api call with Mockito
我需要一些关于如何模拟休息的建议 api。我的应用程序采用 MVP 架构。
我的 API 界面:
public interface MyAPI {
@GET("{cmd}/{userName}/{password}")
Observable<Response> login(
@Path("cmd") String cmd,
@Path("userName") String userName,
@Path("password") String password
);
我的服务:
public class MyService implements IService {
private static MyService mInstance = new MyService();
private MyAPI mApi;
public static MyService getInstance() {
return mInstance;
}
private MyService() {
OkHttpClient.Builder httpClientBuilder = new OkHttpClient.Builder();
httpClientBuilder.connectTimeout(Config.DEFAULT_TIMEOUT, TimeUnit.SECONDS);
Retrofit retrofit = new Retrofit.Builder()
.baseUrl(Config.kBaseUrl)
.addConverterFactory(GsonConverterFactory.create())
.addCallAdapterFactory(RxJavaCallAdapterFactory.create())
.client(httpClientBuilder.build())
.build();
this.mApi = retrofit.create(MyAPI.class);
}
public void login(
Subscriber<Response> subscriber,
String userName,
String password) {
mApi.login(Config.kLoginCmd,userName,password)
.subscribeOn(Schedulers.io())
.unsubscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.subscribe(subscriber);
}
我的主持人class:
public class LoginPresenter implements LoginContract.Presenter {
LoginContract.View mView;
IService mService;
ISession mSession;
public LoginPresenter(LoginContract.View loginView, IService service, ISession session) {
mView = loginView;
mService = service;
mSession = session;
}
@Override
public void login(String email, String password) {
Subscriber<Response> subscriber = new Subscriber<Response>() {
@Override
public void onCompleted() {
mView.showLoading(false);
}
@Override
public void onError(Throwable e) {
mView.showError(e.getLocalizedMessage());
}
@Override
public void onNext(Response response) {
if (response.getResults().getStatus().equalsIgnoreCase(Config.kResultCodeOK)) {
mView.loginSuccess();
} else {
mView.showError(response.getResults().getStatus().getErrmsg());
}
}
};
mView.showLoading(true);
mService.login(
subscriber,
email,
password);
}
还有另一种方法可以通过编写 Mock 服务来测试我的演示者。但我不太喜欢那样,我认为 Mockito 可以提供帮助。
这是我的测试class:
public class LoginPresenterMockTest {
private LoginPresenter mLoginPresenter;
@Mock
LoginContract.View view;
@Mock
IService service;
@Mock
ISession session;
@Before
public void setup() throws Exception {
MockitoAnnotations.initMocks(this);
mLoginPresenter = new LoginPresenter(view, service, session);
}
@Test
public void testLoginWithCorrectUserNameAndPassword() throws Exception {
mLoginPresenter.login("user@email.com","password");
verify(view).loginSuccess();
}
}
我想做的是在响应正确时模拟响应数据调用 loginSuccess()。
当然我现在的测试不行。我需要一些关于如何模拟这个的建议?任何的想法?谢谢。
您可以通过以下方式进行:
@Test
public void testLoginWithCorrectUserNameAndPassword() throws Exception {
// create or mock response object
when(service.login(anyString(), anyString(), anyString).thenReturn(Observable.just(response));
mLoginPresenter.login("user@email.com","password");
verify(view).loginSuccess();
}
@Test
public void testLoginWithIncorrectUserNameAndPassword() throws Exception {
// create or mock response object
when(service.login(anyString(), anyString(), anyString).thenReturn(Observable.<Response>error(new IOException()));
mLoginPresenter.login("user@email.com","password");
verify(view).showError(anyString);
}
感谢 @Ilya Tretyakov,我得出了这个解决方案:
private ArgumentCaptor<Subscriber<Response>> subscriberArgumentCaptor;
@Test
public void testLoginWithCorrectUserNameAndPassword() throws Exception {
mLoginPresenter.login("user@email.com","password");
// create the mock Response object
Response response = ......
verify(service, times(1)).login(
subscriberArgumentCaptor.capture(),
stringUserNameCaptor.capture(),
stringPasswordCaptor.capture()
);
subscriberArgumentCaptor.getValue().onNext(response);
verify(view).loginSuccess();
}
我需要一些关于如何模拟休息的建议 api。我的应用程序采用 MVP 架构。
我的 API 界面:
public interface MyAPI {
@GET("{cmd}/{userName}/{password}")
Observable<Response> login(
@Path("cmd") String cmd,
@Path("userName") String userName,
@Path("password") String password
);
我的服务:
public class MyService implements IService {
private static MyService mInstance = new MyService();
private MyAPI mApi;
public static MyService getInstance() {
return mInstance;
}
private MyService() {
OkHttpClient.Builder httpClientBuilder = new OkHttpClient.Builder();
httpClientBuilder.connectTimeout(Config.DEFAULT_TIMEOUT, TimeUnit.SECONDS);
Retrofit retrofit = new Retrofit.Builder()
.baseUrl(Config.kBaseUrl)
.addConverterFactory(GsonConverterFactory.create())
.addCallAdapterFactory(RxJavaCallAdapterFactory.create())
.client(httpClientBuilder.build())
.build();
this.mApi = retrofit.create(MyAPI.class);
}
public void login(
Subscriber<Response> subscriber,
String userName,
String password) {
mApi.login(Config.kLoginCmd,userName,password)
.subscribeOn(Schedulers.io())
.unsubscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.subscribe(subscriber);
}
我的主持人class:
public class LoginPresenter implements LoginContract.Presenter {
LoginContract.View mView;
IService mService;
ISession mSession;
public LoginPresenter(LoginContract.View loginView, IService service, ISession session) {
mView = loginView;
mService = service;
mSession = session;
}
@Override
public void login(String email, String password) {
Subscriber<Response> subscriber = new Subscriber<Response>() {
@Override
public void onCompleted() {
mView.showLoading(false);
}
@Override
public void onError(Throwable e) {
mView.showError(e.getLocalizedMessage());
}
@Override
public void onNext(Response response) {
if (response.getResults().getStatus().equalsIgnoreCase(Config.kResultCodeOK)) {
mView.loginSuccess();
} else {
mView.showError(response.getResults().getStatus().getErrmsg());
}
}
};
mView.showLoading(true);
mService.login(
subscriber,
email,
password);
}
还有另一种方法可以通过编写 Mock 服务来测试我的演示者。但我不太喜欢那样,我认为 Mockito 可以提供帮助。
这是我的测试class:
public class LoginPresenterMockTest {
private LoginPresenter mLoginPresenter;
@Mock
LoginContract.View view;
@Mock
IService service;
@Mock
ISession session;
@Before
public void setup() throws Exception {
MockitoAnnotations.initMocks(this);
mLoginPresenter = new LoginPresenter(view, service, session);
}
@Test
public void testLoginWithCorrectUserNameAndPassword() throws Exception {
mLoginPresenter.login("user@email.com","password");
verify(view).loginSuccess();
}
}
我想做的是在响应正确时模拟响应数据调用 loginSuccess()。
当然我现在的测试不行。我需要一些关于如何模拟这个的建议?任何的想法?谢谢。
您可以通过以下方式进行:
@Test
public void testLoginWithCorrectUserNameAndPassword() throws Exception {
// create or mock response object
when(service.login(anyString(), anyString(), anyString).thenReturn(Observable.just(response));
mLoginPresenter.login("user@email.com","password");
verify(view).loginSuccess();
}
@Test
public void testLoginWithIncorrectUserNameAndPassword() throws Exception {
// create or mock response object
when(service.login(anyString(), anyString(), anyString).thenReturn(Observable.<Response>error(new IOException()));
mLoginPresenter.login("user@email.com","password");
verify(view).showError(anyString);
}
感谢 @Ilya Tretyakov,我得出了这个解决方案:
private ArgumentCaptor<Subscriber<Response>> subscriberArgumentCaptor;
@Test
public void testLoginWithCorrectUserNameAndPassword() throws Exception {
mLoginPresenter.login("user@email.com","password");
// create the mock Response object
Response response = ......
verify(service, times(1)).login(
subscriberArgumentCaptor.capture(),
stringUserNameCaptor.capture(),
stringPasswordCaptor.capture()
);
subscriberArgumentCaptor.getValue().onNext(response);
verify(view).loginSuccess();
}