MYSQL 使用 PHP 准备好的语句插入
MYSQL insertion using PHP prepared Statement
我正在尝试使用下面的 php 准备语句在 mysql table 中插入一行,但是代码总是通过该语句并移动到 echo "failed" .以下代码中缺少什么?
(我的数据库有额外的列,但我没有添加它,因为我不想在其中插入值(其中一列是自动递增的))
<?php
$ActivityDate = $_POST["ActivitytDate"];
$CoreSite = $_POST["CoreSite"];
$ActionAuditor = $_POST["ActionAuditor"];
$DCOSPOC = $_POST["DCOSPOC"];
if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC) Where (ActivityDate=? AND CoreSite=? AND ActionAuditor=? AND DCOSPOC=?)"))
{
$stmt->bind_param("ssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();
}
?>
我已经编辑了代码以改为使用值,它不是回显失败而是回显成功..但仍然没有向数据库添加值
<?php
$ActivityDate = $_POST["ActivitytDate"];
$CoreSite = $_POST["CoreSite"];
$ActionAuditor = $_POST["ActionAuditor"];
$DCOSPOC = $_POST["DCOSPOC"];
$AreaOwner = $_POST["AreaOwner"];
$ActionImplementer = $_POST["ActionImplementer"];
$ActionOwner = $_POST["ActionOwner"];
$MailSubject = $_POST["MailSubject"];
$ActionType = $_POST["ActionType"];
$RequestType = $_POST["RequestType"];
$RequestNumber = $_POST["RequestNumber"];
$OpenTime = $_POST["OpenTime"];
$CloseTime = $_POST["CloseTime"];
$ActionResult = $_POST["ActionResult"];
$Violation = $_POST["Violation"];
$ActionDetails = $_POST["ActionDetails"];
$Snags = $_POST["Snags"];
$SnagDesc = $_POST["SnagDesc"];
$Layout = $_POST["Layout"];
$LayoutDesc = $_POST["LayoutDesc"];
$CabinetLocation = $_POST["CabinetLocation"];
$Mapping = $_POST["Mapping"];
$MappingDesc = $_POST["MappingDesc"];
$Notes = $_POST["Notes"];
if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC, AreaOwner, ActionImplementer, ActionOwner, MailSubject, ActionType, RequestType, RequestNumber, OpenTime, CloseTime, ActionResult, Violation, ActionDetails, Snags, SnagDesc, Layout, LayoutDesc, CabinetLocation, Mapping, MappingDesc, Notes) values (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?)"))
{
$stmt->bind_param("ssssssssssssssssssssssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC, $AreaOwner, $ActionImplementer, $ActionOwner, $MailSubject, $ActionType, $RequestType, $RequestNumber, $OpenTime, $CloseTime, $ActionResult, $Violation, $ActionDetails, $Snags, $SnagDesc, $Layout, $LayoutDesc, $CabinetLocation, $Mapping, $MappingDesc, $Notes);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();
}
echo ("Successful");
?>
你必须使用
values
在您的查询中。并删除
AND
也来自查询。请检查以下代码。
if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC) values (?,?,?,?)"))
{
$stmt->bind_param("ssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();
}
请注意,where 用于更新。所以要插入使用查询如下:
INSERT INTO table_name (column1,column2,column3,...) VALUES (value1,value2,value3,...);
//认为你应该这样做,insert语句只允许where子句使用select语句,
<?php
$ActivityDate = $_POST["ActivitytDate"];
$CoreSite = $_POST["CoreSite"];
$ActionAuditor = $_POST["ActionAuditor"];
$DCOSPOC = $_POST["DCOSPOC"];
if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC) values (?,?,?,?)");
{
$stmt->bind_param("ssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();
}
?>
使用值代替其中
<?php
$ActivityDate = $_POST["ActivitytDate"];
$CoreSite = $_POST["CoreSite"];
$ActionAuditor = $_POST["ActionAuditor"];
$DCOSPOC = $_POST["DCOSPOC"];
if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC) values(?,?,?,?)"))
{
$stmt->bind_param("ssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();
}
?>
我正在尝试使用下面的 php 准备语句在 mysql table 中插入一行,但是代码总是通过该语句并移动到 echo "failed" .以下代码中缺少什么?
(我的数据库有额外的列,但我没有添加它,因为我不想在其中插入值(其中一列是自动递增的))
<?php
$ActivityDate = $_POST["ActivitytDate"];
$CoreSite = $_POST["CoreSite"];
$ActionAuditor = $_POST["ActionAuditor"];
$DCOSPOC = $_POST["DCOSPOC"];
if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC) Where (ActivityDate=? AND CoreSite=? AND ActionAuditor=? AND DCOSPOC=?)"))
{
$stmt->bind_param("ssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();
}
?>
我已经编辑了代码以改为使用值,它不是回显失败而是回显成功..但仍然没有向数据库添加值
<?php
$ActivityDate = $_POST["ActivitytDate"];
$CoreSite = $_POST["CoreSite"];
$ActionAuditor = $_POST["ActionAuditor"];
$DCOSPOC = $_POST["DCOSPOC"];
$AreaOwner = $_POST["AreaOwner"];
$ActionImplementer = $_POST["ActionImplementer"];
$ActionOwner = $_POST["ActionOwner"];
$MailSubject = $_POST["MailSubject"];
$ActionType = $_POST["ActionType"];
$RequestType = $_POST["RequestType"];
$RequestNumber = $_POST["RequestNumber"];
$OpenTime = $_POST["OpenTime"];
$CloseTime = $_POST["CloseTime"];
$ActionResult = $_POST["ActionResult"];
$Violation = $_POST["Violation"];
$ActionDetails = $_POST["ActionDetails"];
$Snags = $_POST["Snags"];
$SnagDesc = $_POST["SnagDesc"];
$Layout = $_POST["Layout"];
$LayoutDesc = $_POST["LayoutDesc"];
$CabinetLocation = $_POST["CabinetLocation"];
$Mapping = $_POST["Mapping"];
$MappingDesc = $_POST["MappingDesc"];
$Notes = $_POST["Notes"];
if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC, AreaOwner, ActionImplementer, ActionOwner, MailSubject, ActionType, RequestType, RequestNumber, OpenTime, CloseTime, ActionResult, Violation, ActionDetails, Snags, SnagDesc, Layout, LayoutDesc, CabinetLocation, Mapping, MappingDesc, Notes) values (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?)"))
{
$stmt->bind_param("ssssssssssssssssssssssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC, $AreaOwner, $ActionImplementer, $ActionOwner, $MailSubject, $ActionType, $RequestType, $RequestNumber, $OpenTime, $CloseTime, $ActionResult, $Violation, $ActionDetails, $Snags, $SnagDesc, $Layout, $LayoutDesc, $CabinetLocation, $Mapping, $MappingDesc, $Notes);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();
}
echo ("Successful");
?>
你必须使用
values
在您的查询中。并删除
AND
也来自查询。请检查以下代码。
if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC) values (?,?,?,?)"))
{
$stmt->bind_param("ssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();
}
请注意,where 用于更新。所以要插入使用查询如下:
INSERT INTO table_name (column1,column2,column3,...) VALUES (value1,value2,value3,...);
//认为你应该这样做,insert语句只允许where子句使用select语句,
<?php
$ActivityDate = $_POST["ActivitytDate"];
$CoreSite = $_POST["CoreSite"];
$ActionAuditor = $_POST["ActionAuditor"];
$DCOSPOC = $_POST["DCOSPOC"];
if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC) values (?,?,?,?)");
{
$stmt->bind_param("ssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();
}
?>
使用值代替其中
<?php
$ActivityDate = $_POST["ActivitytDate"];
$CoreSite = $_POST["CoreSite"];
$ActionAuditor = $_POST["ActionAuditor"];
$DCOSPOC = $_POST["DCOSPOC"];
if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC) values(?,?,?,?)"))
{
$stmt->bind_param("ssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();
}
?>