如何从 Pandas 中的 OLS 摘要中提取特定值？

Question

是否可以从pandas中的线性回归总结中得到其他值（目前我只知道一种获取beta和截距的方法）？我需要得到 R 平方。以下是手册摘录：

In [244]: model = ols(y=rets['AAPL'], x=rets.ix[:, ['GOOG']])

In [245]: model
Out[245]: 
-------------------------Summary of Regression Analysis---------------------   ----
Formula: Y ~ <GOOG> + <intercept>
Number of Observations:         756
Number of Degrees of Freedom:   2
R-squared:         0.2814
Adj R-squared:     0.2805
Rmse:              0.0147
F-stat (1, 754):   295.2873, p-value:     0.0000
Degrees of Freedom: model 1, resid 754
-----------------------Summary of Estimated Coefficients------------------------
      Variable       Coef    Std Err     t-stat    p-value    CI 2.5%   CI 97.5%
--------------------------------------------------------------------------------
      GOOG     0.5442     0.0317      17.18     0.0000     0.4822     0.6063
 intercept     0.0011     0.0005       2.14     0.0327     0.0001     0.0022
---------------------------------End of Summary---------------------------------

谢谢

Answer 1

尝试：

print model.r2

例如：

import pandas as pd
from pandas import Panel
from pandas.io.data import DataReader
import scikits.statsmodels.api as sm

symbols = ['MSFT', 'GOOG', 'AAPL']

data = dict((sym, DataReader(sym, "yahoo")) for sym in symbols)

panel = Panel(data).swapaxes('items', 'minor')

close_px = panel['Close']

# convert closing prices to returns
rets = close_px / close_px.shift(1) - 1
model = pd.ols(y=rets['AAPL'], x=rets.ix[:, ['GOOG']])
print model.r2

文档：http://statsmodels.sourceforge.net/stable/index.html

Answer 2

Docs handling the results of the regression - 这将允许您从回归结果中提取一些值：

# Given
model = ols(y=rets['AAPL'], x=rets.ix[:, ['GOOG']]).fit()

在r-squared的情况下使用：

# retrieving model's r-squared value
model.rsquared

并且在 p-values 的情况下使用：

# return p-values and corresponding coefficients in model
model.pvalues

更多参数(fvalues ess)请参考doc

如何从 Pandas 中的 OLS 摘要中提取特定值？

How to extract a particular value from the OLS-summary in Pandas?

linear-regression

pandas