如何在 PHP 中显示循环结果

Question

我有一个数组：

Array
(
    [0] => Array
        (
            [phappointment_id] => 69
            [phc_id] => 49
            [valuator] => 91140961
            [valuated] => 87101133
        )

    [1] => Array
        (
            [phappointment_id] => 70
            [phc_id] => 49
            [valuator] => 98160588
            [valuated] => 87101133
        )

    [2] => Array
        (
            [phappointment_id] => 71
            [phc_id] => 49
            [valuator] => 91140961
            [valuated] => 89140962
        )

    [3] => Array
        (
            [phappointment_id] => 72
            [phc_id] => 49
            [valuator] => 98160588
            [valuated] => 94160284
        )
)

我将数组循环到这段代码中：

for ($i = 0; $i < $length; $i++) {
    $dataValuated=$perf->loadValuated($post['valuate'][$i]['valuated']);
    $dataValuator=$perf->loadValuator($post['valuate'][$i]['valuator']);
}
$arrValuated=array();
$arrValuator=array();
foreach($dataValuator as $val){
   array_push($arrValuator, $val);
}
foreach($dataValuated as $val){
   array_push($arrValuated, $val);
}

但是当我得出结果时，我只找到1个结果，必须是4个结果。

echo json_encode(数组('valuator'=>$arrValuator,'valuated'=>$arrValuated));

结果：

{"valuator":[{"valuator_name":"asad"}],"valuated":[{"valuated_name":"desan"}]}

如何解决？谢谢

Answer 1

可能是因为 for 循环中 $dataValuated 和 $dataValuator 后面缺少 [] :

for ($i = 0; $i < $length; $i++) {
    $dataValuated[]=$perf->loadValuated($post['valuate'][$i]['valuated']);
    $dataValuator[]=$perf->loadValuator($post['valuate'][$i]['valuator']);
}

如果没有[]，则用新值替换旧值将始终是一个结果。

Answer 2

试试这个，您可以直接从 $post['valuate']

创建数组 $arrValuated 和 $arrValuator

<?php 
$arrValuated=array();
$arrValuator=array();

foreach($post['valuate'] as $valuate )
{
    $arrValuated[] = $perf->loadValuated($valuate['valuated']);
    $arrValuator[] = $perf->loadValuator($valuate['valuator']);
}
?>

如何在 PHP 中显示循环结果

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