Python sendemail() MIMEMultipart 不工作

Question

我一直在尝试逐步创建一个 python (v3.4) 脚本来发送带附件的电子邮件。我已经使用 smtplib 库成功发送了一个没有附件的邮件。但是，要添加附件，我似乎需要创建一个 MIMEMultipart 对象。到这里为止没什么奇怪的。

基于我创建的例子

import smtplib
from email.mime.multipart import MIMEMultipart

try:
fromaddr = 'from@email.com'
toaddrs  = ['to@email.com']

# Create the container (outer) email message.
msg = MIMEMultipart()
msg['Subject'] = 'Our family reunion'
# me == the sender's email address
# family = the list of all recipients' email addresses
msg['From'] = fromaddr
msg['To'] = toaddrs
msg.preamble = 'Our family reunion'




password = 'ExamplePassword88'

# The actual mail send
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.ehlo()
server.login(fromaddr,password)


text = msg.as_string()
server.sendmail(fromaddr, toaddrs, text)
print("Successfully sent email")

除了 SMTPException: 打印（"Error: unable to send email"）最后： server.quit()

但是行 " text = msg.as_string()"" 抛出以下错误

Traceback (most recent call last): File "C:/Users/user/upload_file.py", line 37, in text = msg.as_string() File "C:\Python34\lib\email\message.py", line 159, in as_string g.flatten(self, unixfrom=unixfrom) File "C:\Python34\lib\email\generator.py", line 112, in flatten self._write(msg) File "C:\Python34\lib\email\generator.py", line 192, in _write self._write_headers(msg) File "C:\Python34\lib\email\generator.py", line 219, in _write_headers self.write(self.policy.fold(h, v)) File "C:\Python34\lib\email_policybase.py", line 314, in fold return self._fold(name, value, sanitize=True) File "C:\Python34\lib\email_policybase.py", line 352, in _fold parts.append(h.encode(linesep=self.linesep, AttributeError: 'list' object has no attribute 'encode'

我能做什么？

Answer 1

问题是您的变量 toaddrs 是一个列表。

您需要将地址列表作为字符串，地址以逗号分隔，例如

msg['To'] = ",".join(toaddrs)

在那之后一切都应该正常工作。有关更多详细信息，请参见此处： How to send email to multiple recipients using python smtplib?

Python sendemail() MIMEMultipart 不工作

Python sendemail() MIMEMultipart not working

python

email

python-3.4