当客户名称或代理名称 = Null 时出现错误
i got error When Customer Name or Agent Name = Null
当客户名称或代理名称 = Null 时出现错误
var results = db.Users.ToDataSourceResult(request, o => new
{
Id= o.Id,
UserName = o.UserName,
Email = o.Email,
PhoneNumber = o.PhoneNumber,
AgentName = o.Agent.FullName,
CustomrName = o.Customer.Name
});
return Json(results, JsonRequestBehavior.AllowGet);
如果你的意思是你得到引用错误是因为代理和客户没有在用户 class 的构造函数中加载,你必须使用延迟加载
Public class user{
public user
(
agent=new Agent();
customer=new Customer();
)
}
您收到一个错误,因为您试图访问一个 Null 对象的 属性。本例中的 Agent 和 Customer 属性。在尝试使用它们之前,您需要测试空值。
var results = db.Users.ToDataSourceResult(request, o => new
{
Id = o.Id,
UserName = o.UserName,
Email = o.Email,
PhoneNumber = o.PhoneNumber,
AgentName = o.Agent == null ? null : o.Agent.FullName,
CustomrName = o.Customer == null ? null : o.Customer.Name
});
return Json(results, JsonRequestBehavior.AllowGet);
或者,如果您使用的是 C# 6,则可以使用新的 shorthand
var results = db.Users.ToDataSourceResult(request, o => new
{
Id = o.Id,
UserName = o.UserName,
Email = o.Email,
PhoneNumber = o.PhoneNumber,
AgentName = o.Agent?.FullName,
CustomrName = o.Customer?.Name
});
return Json(results, JsonRequestBehavior.AllowGet);
我使用了这个代码并且成功了
谢谢
var results = db.Users.Include("Customer").Include("Agent").ToDataSourceResult(request, o => new
{
Id = o.Id,
UserName = o.UserName,
Email = o.Email,
PhoneNumber = o.PhoneNumber,
AgentName = o.Agent?.FullName,
CustomrName = o.Customer?.Name
});
return Json(results, JsonRequestBehavior.AllowGet);
当客户名称或代理名称 = Null 时出现错误
var results = db.Users.ToDataSourceResult(request, o => new
{
Id= o.Id,
UserName = o.UserName,
Email = o.Email,
PhoneNumber = o.PhoneNumber,
AgentName = o.Agent.FullName,
CustomrName = o.Customer.Name
});
return Json(results, JsonRequestBehavior.AllowGet);
如果你的意思是你得到引用错误是因为代理和客户没有在用户 class 的构造函数中加载,你必须使用延迟加载
Public class user{
public user
(
agent=new Agent();
customer=new Customer();
)
}
您收到一个错误,因为您试图访问一个 Null 对象的 属性。本例中的 Agent 和 Customer 属性。在尝试使用它们之前,您需要测试空值。
var results = db.Users.ToDataSourceResult(request, o => new
{
Id = o.Id,
UserName = o.UserName,
Email = o.Email,
PhoneNumber = o.PhoneNumber,
AgentName = o.Agent == null ? null : o.Agent.FullName,
CustomrName = o.Customer == null ? null : o.Customer.Name
});
return Json(results, JsonRequestBehavior.AllowGet);
或者,如果您使用的是 C# 6,则可以使用新的 shorthand
var results = db.Users.ToDataSourceResult(request, o => new
{
Id = o.Id,
UserName = o.UserName,
Email = o.Email,
PhoneNumber = o.PhoneNumber,
AgentName = o.Agent?.FullName,
CustomrName = o.Customer?.Name
});
return Json(results, JsonRequestBehavior.AllowGet);
我使用了这个代码并且成功了 谢谢
var results = db.Users.Include("Customer").Include("Agent").ToDataSourceResult(request, o => new
{
Id = o.Id,
UserName = o.UserName,
Email = o.Email,
PhoneNumber = o.PhoneNumber,
AgentName = o.Agent?.FullName,
CustomrName = o.Customer?.Name
});
return Json(results, JsonRequestBehavior.AllowGet);