php preg_match_all 条件为 if/else

Question

我正在使用以下 'badword filter' 并且它有效 -

    $question = Trim(stripslashes($_POST['Message']));     
    $badwords = array("caca","poopoo","pipi");
    $matches = array();
    $matchFound = preg_match_all("/\b(" . implode($badwords,"|") . ")\b/i", $question, $matches);
    if ($matchFound){
        $words = array_unique($matches[0]);
        foreach($words as $word){
            echo '<span class="word">'.$word.'</span>'; //outputs <span class="word">caca</span> <span class="word">poopoo</span> <span class="word">pipi</span>
        }
    }

我的问题是，我想添加一个 if/else 条件，如果找到 3 个以上的坏词，就这样做，如果没有，就这样做。伪代码：

    if ($severalMatchesFound > 2){
        echo '3 or more badwords found';
    } else {
        echo 'less than 3 badwords found';
    }

Answer 1

$question = Trim(stripslashes($_POST['Message']));     
$badwords = array("caca","poopoo","pipi");
preg_match_all("/\b(" . implode($badwords,"|") . ")\b/i", $question, $matches);
if (count($matches[1]) >= 3){
    // three words or more than three words

    $words = array_unique($matches[1]);
    foreach($words as $word){
        echo '<span class="word">'.$word.'</span>'; //outputs <span class="word">caca</span> <span class="word">poopoo</span> <span class="word">pipi</span>
    }
}elseif(count($matches[1])>=1){
  //more than one but less than three
}else{
  // no words found
}

抱歉，忘记了 [1]。我认为 elseif 会像我写的那样工作，但 isset 可能更好

php preg_match_all 条件为 if/else

php preg_match_all with if/else condition

php

preg-match-all