Url.routeUrl returns null（我试过同样的问题）

Question

大家好我想url喜欢{Controller}/{action}/{postid}-{address} 但是 routUrl returns null 请帮我解决它。（我是 MVC 的新手）

我的路线配置是

routes.MapRoute(
            name: "Post",
            url: "Posts/Show/{postid}-{address}",
            defaults: new { controller = "Posts", action = "Index", postid = "", address = "" }
           );

和index.cshtml

<a href="@Url.RouteUrl("Post",new {item.PostId,item.Address })">@item.PostTitle</a>

生成的url是 http://localhost:59066/Posts/Show/1-Post-with-Featured-Image

但在 PostsController 中

public ActionResult Show(string add)
    { return View();} 

"string add" 为空！

Answer 1

我不会改变路线...

试试这个...

<a href="@Url.Action("Action","Controller",new {PostId = item.PostId, Address = item.Address })">@item.PostTitle</a>

这会将 PostId 和地址作为参数发送，因此您可以像这样在控制器中获取它们：

public ActionResult AwesomeThings(int PostId, String Address)
{
         var foo = PostId;
         var bar = Address;
        return View(model);
}

Answer 2

路由没有变化，

Index.cshtml:

<a href="@Url.RouteUrl("Post",new {@postid = item.PostId, @address = item.Address },null)">@item.PostTitle</a>

控制器：

public ActionResult Show(string postid, string address)
{ return View();} 

Answer 3

我把路线改成了

routes.MapRoute("Post", "post/{postid}-{address}", new { controller = "Posts", action = "Show" ,postid="",address=""}, namespaces);

并添加了具有相同控制器和操作的路由

routes.MapRoute("PostAddress", "post/{IdAndAdd}", new { controller = "Posts", action = "Show" }, namespaces);
routes.MapRoute("Post", "post/{postid}-{address}", new { controller = "Posts", action = "Show" ,postid="",address=""}, namespaces);

然后 "idAndAdd" 正确接收到操作

public ActionResult Show(string idAndAdd)
    {
        var parts = SeperateAddress(idAndAdd);
        if (parts == null)
            return HttpNotFound();

        var post = db.Posts.Find(parts.Item1);
        if (post == null)
            return HttpNotFound();

        if (!post.Address.Equals(parts.Item2, StringComparison.CurrentCultureIgnoreCase))
            return RedirectToRoutePermanent("Post", new { postid = parts.Item1, address = post.Address });

        return View(post);
    }

    and it's worked .