symfony2 forms 根据用户数据动态生成表单

Question

我是 symfony2 的新手，我想创建一个表单。字段值应基于用户数据。

我的项目和用户具有 n:m 关系，现在我想在 twig 中嵌入一个表单，我可以在其中分配用户（单击多个）和项目。我的 class 用户看起来像：

// src/Pso/LogBundle/Entity/User.php
namespace Pso\LogBundle\Entity;

use Doctrine\ORM\Mapping as ORM;
use Symfony\Component\Security\Core\User\AdvancedUserInterface;
use Doctrine\Common\Collections\ArrayCollection;
/**
 * @ORM\Table(name="users", options={"collate"="utf8_general_ci", "charset"="utf8", "engine"="InnoDB"})
 * @ORM\Entity(repositoryClass="Pso\LogBundle\Entity\UserRepository")
 */
class User implements AdvancedUserInterface, \Serializable
{
/**
 * @ORM\Column(type="integer")
 * @ORM\Id
 * @ORM\GeneratedValue(strategy="AUTO")
 */
private $id;

/**
 * @ORM\Column(type="string", length=25, unique=true)
 */
private $username;

/**
 * @ORM\Column(type="string", length=32)
 */
private $salt;

/**
 * @ORM\Column(type="string", length=250)
 */
private $password;

/**
 * @ORM\Column(type="string", length=60, unique=true)
 */
private $email;



/**
 * @ORM\Column(name="is_active", type="boolean")
 */
private $isActive;

 /**
 * @ORM\ManyToMany(targetEntity="Role", inversedBy="users")
 * @ORM\JoinTable(name="user_role",
 *      joinColumns={@ORM\JoinColumn(name="user_id", referencedColumnName="id")},
 *      inverseJoinColumns={@ORM\JoinColumn(name="role_id", referencedColumnName="id")}
 *      )
 *
 */
private $roles;

项目的 class 看起来像：

// src/Pso/ProjectBundle/Entity/Project.php
namespace Pso\ProjectBundle\Entity;

use Doctrine\ORM\Mapping as ORM;
use Doctrine\Common\Collections\ArrayCollection;

/**
 * @ORM\Table(name="project", options={"collate"="utf8_general_ci", "charset"="utf8", "engine"="InnoDB"})
 * @ORM\Entity(repositoryClass="Pso\ProjectBundle\Entity\ProjectRepository")
 */
class Project
{ 
/**
 * @ORM\Column(name="id", type="integer")
 * @ORM\Id()
 * @ORM\GeneratedValue(strategy="AUTO")
 */
 private $id;

 /**
 * @ORM\Column(type="string", length=255, unique=true, nullable=false)
 */
 private $project_nr;

 /**
 * @ORM\ManyToOne(targetEntity="Pso\ProjectBundle\Entity\Mandator", inversedBy="projects")
 * @ORM\JoinColumn(name="mandator_id", referencedColumnName="id")
 */
 private $mandator;

 /**
 * @ORM\Column(type="string", length=80, nullable=false)
 */
 private $project_name;

 /**
 * @ORM\Column(type="string", length=50)
 */
 private $customer;

 /**
 * @ORM\Column(type="string", length=50)
 */
 private $label;

 /**
 * @ORM\Column(type="date")
 */
 private $shipping_date;

/**
 * @ORM\Column(type="float")
 */ 
 private $advance_payment;

 /**
 * @ORM\Column(type="integer", length=1)
 */
 private $probability;

 /**
 * @ORM\Column(type="blob")
 */
 private $special_demand;

/**
 * @ORM\Column(type="string", length=4)
 */ 
 private $currency;

/**
 * @ORM\Column(type="integer", length=1, nullable=false)
 */ 
 private $status;

/**
 * @ORM\Column(type="string", length=100)
 */  
 private $contract_nr;

/**
 * @ORM\Column(type="datetime", nullable=false)
 */   
 private $dbinsert;

 /**
 * @ORM\Column(type="datetime", nullable=false)
 */ 
 private $dbupdate;

/**
 * @ORM\ManyToMany(targetEntity="Pso\LogBundle\Entity\User", cascade={"persist", "remove"})
 */
private $users;

 public function __construct() {
    $this->user = new \Doctrine\Common\Collections\ArrayCollection();
}

我的 ProjectuserType 看起来像：

namespace Pso\ProjectBundle\Form;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\Form\FormEvents;
use Symfony\Component\Form\FormEvent;
use Doctrine\ORM\EntityRepository;

class ProjectuserType extends AbstractType
{

public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder
            ->add('project','text')
    ;


$builder->addEventListener(
        FormEvents::PRE_SET_DATA,
        function (FormEvent $event) {
            $form = $event->getForm();

            $formOptions = array(
                'class' => 'Pso\LogBundle\Entity\User',
                'property' => 'username',
                'query_builder' => function (EntityRepository $er) {
                     return $er->createQueryBuilder('x')->FROM('PsoLogBundle:user', 'u')
                                                        ->WHERE('u.id = :id')
                                                        ->setParameter('id',5)
                                                        ;
                    // or call a method on your repository that returns the query builder
                    // the $er is an instance of your UserRepository
                    // return $er->findnotsignedusers();
                },
            );
                    // or call a method on your repository that returns the query builder
                    // the $er is an instance of your UserRepository
                    // return $er->createOrderByFullNameQueryBuilder();
                },
            );

            // create the field, this is similar the $builder->add()
            // field name, field type, data, options
            $form->add('user', 'entity', $formOptions);
        }
    );
}

public function getName()
{
    return 'Projectuser';
}

public function setDefaultOptions(OptionsResolverInterface $resolver)
{
    $resolver->setDefaults(array(
        'data_class'  => null,
    ));
}

}

类型 I 面向 post and on documentation about chapter "How to dynamically Generate Forms Based on user Data"

使用我的代码，我总是得到错误 "Class Pso\ProjectBundle\Form\EntityRepository does not exist"。我想我没有得到正确的文档。我不想从我的 ProjectRepository 中获取数据。这存在，但名称空间是 Pso\ProjectBundle\Form。但我的目的是在我的 EventListener 中使用查询生成器获取数据。我们将不胜感激。

Answer 1

在您的 ProjectuserType class 中添加此行：use Doctrine\ORM\EntityRepository

希望对您有所帮助。最好的问候。

symfony2 forms 根据用户数据动态生成表单

symfony2 forms dynamically Generate Forms Based on user Data

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