通过选择 combobox1 wxpython 动态更新 combobox 2

dynamically update combobox 2 with selection of combobox1 wxpython

我是 python 的新手,正在尝试学习一些基本代码。我正在做一些项目,下面有演示代码。

我无法在此代码中更改的唯一内容是 __init__def update() 部分,因为它们也链接到其他一些代码。

问题是当我在 combobox-1 上 select 值为 '2' 时,我在 combobox-2 中得到的值为 'B100,B200,B300' 但如果我 select 值为 '1'在 combobox-1 上 selecting 值“2”后,我的 combobox-2 上没有任何更新列表。如果需要,复制并粘贴到 IDE 代码。

#!/usr/bin/python
#20_combobox.py

import wx
import wx.lib.inspection

class MyFrame(wx.Frame):
    def __init__(self, *args, **kwargs):
    wx.Frame.__init__(self, *args, **kwargs)

        self.p1 = wx.Panel(self)
        lst = ['1','2','3']
        self.st = wx.ComboBox(self.p1, -1, choices = self.lst1(), style=wx.TE_PROCESS_ENTER)
        self.st2 = wx.ComboBox(self.p1, -1, choices = self.lst2(), style=wx.TE_PROCESS_ENTER)

        self.st.Bind(wx.EVT_COMBOBOX, self.update)
        self.st2.Bind(wx.EVT_COMBOBOX, self.update)


    def lst1(self):
        lst=['1','2','3']
        return lst

    def lst2(self):
        lst =['A100','A200','A300','B100','B200','B300','C100','C200','C300','D100','D200','D300']
        dummyvar=[]
        dummyvar1=[]

        if self.st.GetStringSelection() == '1':
            self.st2.Clear()
            for number in lst:
                if number.startswith('A'):
                # if number.startswith('A'):
                    self.st2.Append(number)
                    self.st.Hide()

        elif self.st.GetStringSelection() == '2':
            self.st2.Clear()
            for number in lst:
                if number.startswith('B'):
                    self.st2.Append(number)



        return lst


    def update(self, event):
        self.lst1a=self.lst1()
        self.lst2a=self.lst2()


class MyApp(wx.App):
    def OnInit(self):
        frame = MyFrame(None, -1, '20_combobox.py')
        frame.Show()
        self.SetTopWindow(frame)
        return 1

if __name__ == "__main__":
    app = MyApp(0)
#    wx.lib.inspection.InspectionTool().Show()
    app.MainLoop()

不要混淆对象属性和方法。 self.list1 != self.list1(),一个事实 Python 试图通过在第二次调用 self.update 时引发错误来告诉您。查看关注点分离更清晰的示例:

class MyFrame(wx.Frame):
    def __init__(self, *args, **kwargs):
        wx.Frame.__init__(self, *args, **kwargs)

        self.p1 = wx.Panel(self)
        self.lst1 = ['1','2','3']
        self.lst2 = self.get_lst2()

        self.st = wx.ComboBox(self.p1, -1, choices = self.lst1, style=wx.TE_PROCESS_ENTER)
        self.st2 = wx.ComboBox(self.p1, -1, choices = self.lst2, style=wx.TE_PROCESS_ENTER, pos=(-1,100), size=(100,-1))

        self.st.Bind(wx.EVT_COMBOBOX, self.update)

    def get_lst2(self, selectn=None):
        lst =['A100','A200','A300','B100','B200','B300','C100','C200','C300','D100','D200','D300']

        ret =  []
        if selectn == '1':
            for entry in lst:
                if entry.startswith('A'):
                    ret.append(entry)
        elif selectn == '2':
            for entry in lst:
                if entry.startswith('B'):
                    ret.append(entry)
        else:
            ret = lst
        return ret

    def update(self, event):
        selectn = self.st.GetStringSelection()
        self.lst2 = self.get_lst2(selectn)
        self.st2.Clear()
        for number in self.lst2:
            self.st2.Append(number)
        if selectn == '1':
            self.st.Hide()