游戏连续输入检查

Question

我一直在开发一款刽子手游戏，几乎完成了所有繁重的编码工作。但是，我在测试连续输入时遇到问题。如果用户输入 "yes" 或 "no" 以外的内容连续三次 如果他们想玩刽子手，我想关闭程序。如果用户输入了三个 total 错误输入，我只能想出一种关闭程序的方法。下面是我的代码。任何帮助深表感谢！

#include <iostream>
#include <string>
#include "MyFuncts.h"
#include "randword.h"
using namespace std;

void drawHangman(int incorrectCount);
int askToPlay();
int response = 0;
int incorrectCount = 0;
void gameSequence();

int main()
{
string reply = " ";
int consecutiveErrors = 0;
getWords("hangman.dat");
do
{
    askToPlay();
    if (response == PLAY)
    {
        gameSequence();
    }
    else if (response == STOP)
    {
        cout << "Goodbye\n";
        break;
    }
    else
    {
        consecutiveErrors++;
        cout << "ERROR\n";
    }
} while (getNextWord() != "" && consecutiveErrors < 3);
system("pause");
}

void drawHangman(int incorrectCount)
{
if (incorrectCount == 0)
    cout << " -------|\n"
    " |      |\n"
    "        |\n"
    "        |\n"
    "        |\n"
    "        |\n"
    "      -----\n\n";
else if (incorrectCount == 1)
    cout << " -------|\n"
    " |      |\n"
    " O      |\n"
    "        |\n"
    "        |\n"
    "        |\n"
    "      -----\n\n";
else if (incorrectCount == 2)
    cout << " -------|\n"
    " |      |\n"
    " O      |\n"
    " |      |\n"
    "        |\n"
    "        |\n"
    "      -----\n\n";
else if (incorrectCount == 3)
    cout << " -------|\n"
    " |      |\n"
    " O      |\n"
    "-|      |\n"
    "        |\n"
    "        |\n"
    "      -----\n\n";
else if (incorrectCount == 4)
    cout << " -------|\n"
    " |      |\n"
    " O      |\n"
    "-|-     |\n"
    "        |\n"
    "        |\n"
    "      -----\n\n";
else if (incorrectCount == 5)
    cout << " -------|\n"
    " |      |\n"
    " O      |\n"
    "-|-     |\n"
    "/       |\n"
    "        |\n"
    "      -----\n\n";
else
    cout << " -------|\n"
    " |      |\n"
    " O      |\n"
    "-|-     |\n"
    "/ \     |\n"
    "        |\n"
    "      -----\n\n";
}

int askToPlay()
{
string reply = " ";
cout << "\nDo you want to play hangman? (y or n): ";
cin >> reply;
response = promptYN(reply);
return response;
}

void gameSequence()
{
string guessWord = " ";
char guessLetter = ' ';
cout << "Let's PLAY\n\n";
guessWord = strToUpper(getNextWord());
cout << "Word to Guess: " << guessWord << endl << endl;

while (incorrectCount < 6)
{
    drawHangman(incorrectCount);
    cout << "Enter a letter to guess: ";
    cin >> guessLetter;
    guessLetter = toupper(guessLetter);
    cout << "You entered: " << guessLetter << endl << endl;
    if (guessWord.find(guessLetter) != string::npos)
        cout << guessLetter << " is in the word to guess.\n\n";
    else
    {
        cout << guessLetter << " is NOT in the word to guess.\n\n";
        incorrectCount++;
        if (incorrectCount == 6)
        {
            drawHangman(incorrectCount);
            cout << "Sorry you lose - the word was: " << guessWord << endl << endl;
        }
    }
}
incorrectCount = 0;
}

Answer 1

每当 response 等于 PLAY 时，只需将 consecutiveErrors 重置为 0。

while 循环中的 if 语句类似于以下内容：

if (response == PLAY) {
    consecutiveErrors = 0; // add this line
    gameSequence();
} else if (response == STOP) {
    cout << "Goodbye\n";
    break;
} else {
    consecutiveErrors++;
    cout << "ERROR\n";
}

Answer 2

在您的主循环中，您会在每个错误上递增 consecutiveErrors 计数器，但您不会在收到可接受的响应后将其清除。当您得到可接受的响应时，只需将 consecutiveErrors 设置为 0。

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