C++复数Valarray中的最高元素(最高实部)
The highest element (highest real part ) in Valarray of complex numbers in C++
如何在 C++ 中打印出复数 Valarray 的最高元素?
我已尝试使用此代码,但它返回错误消息
#include <iostream> // std::cout
#include <valarray>
#include <complex>// std::valarray
typedef std::complex<double> Complex;
typedef std::valarray <Complex > CArray;
int main ()
{
CArray y[5]={{1, 2},{3, 4},{2,0},{7,0},{9,0}};
std::cout << "The max is " << y.max() << '\n';
return 0;
}
输出:
main.cpp: In function 'int main()':
main.cpp:15:35: error: request for member 'max' in 'y', which is of non-class type 'CArray [5] {aka std::valarray<std::complex<double> > [5]}'
std::cout << "The max is " << y.max() << '\n';
^
我做错了什么?
第二版代码
我修改了一点代码,现在我想得到所有索引对应于我的 Valarray 的最高元素在我的情况下所有索引对应于元素 {9,0}
注意:"Highest element" 我的意思是具有最高实部的元素
新代码:
#include <iostream>
#include <valarray>
#include <complex>
#include <algorithm>
#include <numeric>
typedef std::complex<double> Complex;
typedef std::valarray <Complex > CArray;
int main ()
{
CArray y={{1, 2},{3, 4},{2,0},{9,0},{7,0},{9,0}};
auto max_val = std::accumulate (std::begin(y), std::end(y), *std::begin(y),
[](const Complex& a ,const Complex& b)
{
auto abs_a = abs(a);
auto abs_b = abs(b);
//if(abs_a == abs_b)
// return std::max(arg(a), arg(b));
return std::max(abs_a, abs_b);
}
);
for (std::size_t i =std::begin(y) ; i != std::end(y) ; i++) {
std::cout << "The max is found on index ["<< i <<"]" << max_val<< '\n';
}
return 0;
}
我收到以下错误:
输出:
main.cpp: In function 'int main()':
main.cpp:22:35: error: invalid conversion from 'std::complex<double>*' to 'std::size_t {aka long unsigned int}' [-fpermissive]
for (std::size_t i =std::begin(y) ; i != std::end(y) ; i++) {
^
main.cpp:22:54: error: ISO C++ forbids comparison between pointer and integer [-fpermissive]
for (std::size_t i =std::begin(y) ; i != std::end(y) ; i++) {
^
y
是 valarray
的数组,因此您需要对该数组中的每个元素调用 max
,而不是数组本身(当然没有成员函数)。
std::complex
不是可比较的类型,那么有一个 "highest" 元素是什么意思?
更新:关于你的编辑,我想我明白你在追求什么......
对于max(by real()
)元素的最高索引:
std::size_t max_index(CArray const& y) {
struct acc_t {
double max_value;
std::size_t max_idx, current_idx;
constexpr acc_t next() const { return {max_value, max_idx, current_idx + 1}; }
constexpr acc_t next_with(Complex const c) const {
return {c.real(), current_idx, current_idx + 1};
}
};
return std::accumulate(
std::begin(y), std::end(y), acc_t{},
[](acc_t const acc, Complex const c) {
return c.real() < acc.max_value
? acc.next()
: acc.next_with(c);
}
).max_idx;
}
或者对于最大元素的所有索引:
std::vector<std::size_t> max_indices(CArray const& y) {
struct acc_t {
std::vector<std::size_t> max_idcs;
double max_value;
std::size_t current_idx;
constexpr acc_t&& next() {
++current_idx;
return std::move(*this);
}
acc_t&& next_with_current() {
max_idcs.push_back(current_idx++);
return std::move(*this);
}
acc_t&& next_with(Complex const c) {
max_value = c.real();
max_idcs.clear();
return next_with_current();
}
};
return std::accumulate(
std::begin(y), std::end(y), acc_t{},
[](acc_t& acc, Complex const c) {
return c.real() < acc.max_value ? acc.next()
: c.real() > acc.max_value ? acc.next_with(c)
: acc.next_with_current();
}
).max_idcs;
}
N.b。您的代码涉及 abs
,但我不确定为什么因为您说您只想基于 std::complex<>::real()
进行比较,所以我省略了...
使用std::accumulate可以得到复数的最大值,类似于Matlab的max函数:
#include <iostream>
#include <valarray>
#include <complex>
#include <algorithm>
#include <numeric>
typedef std::complex<double> Complex;
typedef std::valarray <Complex > CArray;
int main ()
{
CArray y={{1, 2},{3, 4},{2,0},{7,0},{9,0}};
auto max_val = std::accumulate (std::begin(y), std::end(y), *std::begin(y),
[](const Complex& a ,const Complex& b)
{
auto abs_a = abs(a);
auto abs_b = abs(b);
if(abs_a == abs_b)
return std::max(arg(a), arg(b));
return std::max(abs_a, abs_b);
}
);
std::cout << "The max is " << max_val<< '\n';
return 0;
}
编辑:问题已编辑,OP 想要获取复数实部最大值的索引,因此您的答案:
#include <iostream>
#include <valarray>
#include <complex>
#include <algorithm>
#include <numeric>
typedef std::complex<double> Complex;
typedef std::valarray <Complex > CArray;
int main ()
{
CArray y={{1, 2},{3, 4},{2,0},{7,0},{9,0}};
std::vector<int> index(y.size());
std::iota( index.begin(), index.end(), 0 );
auto max_index = std::accumulate (std::begin(index), std::end(index), *std::begin(index),
[&](int a ,int b)
{
return y[a].real() > y[b].real() ? a: b;
}
);
std::cout << "index of max is " << max_index<< '\n';
return 0;
}
编辑 2:正如@ildjarn 提到的,修改后的问题想要获得对应于最高元素的所有索引,因此修改后的答案:
#include <iostream>
#include <valarray>
#include <complex>
#include <algorithm>
#include <numeric>
typedef std::complex<double> Complex;
typedef std::valarray <Complex > CArray;
int main ()
{
CArray y={{1, 2},{3, 4},{2,0},{7,0},{9,0}};
std::vector<int> index(y.size());
std::iota( index.begin(), index.end(), 0 );
auto max_index = std::accumulate (std::begin(index), std::end(index), *std::begin(index),
[&](int a ,int b)
{
return y[a].real() > y[b].real() ? a: b;
}
);
std::vector<int> indices;
std::copy_if(std::begin(index), std::end(index), std::back_inserter(indices),
[&](int a)
{
return y[a] == y[max_index];
}
);
for (auto i: indices)
std::cout << "index of max is " << i << '\n';
return 0;
}
编辑 3:使用 std::max_element 我们拥有的最简单的解决方案:
#include <iostream>
#include <valarray>
#include <complex>
#include <algorithm>
#include <numeric>
#include <vector>
typedef std::complex<double> Complex;
typedef std::valarray <Complex > CArray;
int main ()
{
CArray y={{1, 2},{3, 4},{2,0},{9,0},{7,0},{9,0}};
auto max_index = std::max_element (std::begin(y), std::end(y),
[](const Complex& a ,const Complex& b)
{
return a.real() < b.real() ;
}
);
std::cout << "index of first max element is " << max_index-std::begin(y) << '\n';
std::cout << "indices of all matches of max element is: " << "[";
for (auto it= std::begin(y), end = std::end(y); it != end; ++it){
if(it->real() == max_index->real()) {
std::cout << it - std::begin(y) << ' ' ;
}
}
std::cout << "]";
return 0;
}
您的原始代码的更大问题是(正如 Ildjarn 所指出的)复杂缺少 operator<
。
我想你的 Complex
应该更复杂一点(如果你允许我玩文字游戏的话)。
我提出以下解决方案 Complex
来自 std::complex<double>
并声明一个朋友 operator< ()
。许多 operator< ()
可能之一。
#include <iostream>
#include <valarray>
#include <complex>
struct Complex: public std::complex<double>
{
template <typename ... Args>
Complex (const Args & ... args) : std::complex<double>{args...}
{ }
friend bool operator< (const Complex & c1, const Complex & c2)
{
return (c1.real() < c2.real())
|| ((c1.real() == c2.real()) && (c1.imag() < c2.imag()));
}
};
typedef std::valarray <Complex > CArray;
int main ()
{
CArray y { {1.0,2.0}, {3.0,4.0}, {2.0,0.0}, {7.0,0.0}, {9.0,0.0} };
std::cout << "The max is " << y.max() << '\n';
return 0;
}
如果您接受 Complex
可以是模板化的 class(使用 Class<double>
而不是 Complex
,您可以用这种方式编写更通用的解决方案(即也可以与基于 float
和 long double
)
的复数一起使用
#include <iostream>
#include <valarray>
#include <complex>
template <typename T>
struct Complex: public std::complex<T>
{
template <typename ... Args>
Complex (const Args & ... args) : std::complex<T>{args...}
{ }
friend bool operator< (const Complex & c1, const Complex & c2)
{
return (c1.real() < c2.real())
|| ((c1.real() == c2.real()) && (c1.imag() < c2.imag()));
}
};
typedef std::valarray <Complex<double>> CArray;
int main ()
{
CArray y { {1.0,2.0}, {3.0,4.0}, {2.0,0.0}, {7.0,0.0}, {9.0,0.0} };
std::cout << "The max is " << y.max() << '\n';
return 0;
}
p.s.: 应该也适用于 C++11。
p.s.2: 抱歉我的英语不好。
---编辑得到最大元素的索引---
#include <iostream>
#include <valarray>
#include <complex>
template <typename T>
struct Complex: public std::complex<T>
{
template <typename ... Args>
Complex (const Args & ... args) : std::complex<T>{args...}
{ }
friend bool operator< (const Complex & c1, const Complex & c2)
{
return (c1.real() < c2.real())
|| ((c1.real() == c2.real()) && (c1.imag() < c2.imag()));
}
};
typedef std::valarray <Complex<double>> CArray;
int main ()
{
CArray y { {1.0,2.0}, {3.0,4.0}, {2.0,0.0}, {7.0,0.0}, {9.0,0.0} };
auto m = 0U;
for ( auto i = 1U ; i < y.size() ; ++i)
if ( y[m] < y[i] )
m = i;
std::cout << "The max is found on index ["<< m <<"] and is " << y[m]
<< std::endl;
return 0;
}
如何在 C++ 中打印出复数 Valarray 的最高元素?
我已尝试使用此代码,但它返回错误消息
#include <iostream> // std::cout
#include <valarray>
#include <complex>// std::valarray
typedef std::complex<double> Complex;
typedef std::valarray <Complex > CArray;
int main ()
{
CArray y[5]={{1, 2},{3, 4},{2,0},{7,0},{9,0}};
std::cout << "The max is " << y.max() << '\n';
return 0;
}
输出:
main.cpp: In function 'int main()':
main.cpp:15:35: error: request for member 'max' in 'y', which is of non-class type 'CArray [5] {aka std::valarray<std::complex<double> > [5]}'
std::cout << "The max is " << y.max() << '\n';
^
我做错了什么?
第二版代码 我修改了一点代码,现在我想得到所有索引对应于我的 Valarray 的最高元素在我的情况下所有索引对应于元素 {9,0}
注意:"Highest element" 我的意思是具有最高实部的元素
新代码:
#include <iostream>
#include <valarray>
#include <complex>
#include <algorithm>
#include <numeric>
typedef std::complex<double> Complex;
typedef std::valarray <Complex > CArray;
int main ()
{
CArray y={{1, 2},{3, 4},{2,0},{9,0},{7,0},{9,0}};
auto max_val = std::accumulate (std::begin(y), std::end(y), *std::begin(y),
[](const Complex& a ,const Complex& b)
{
auto abs_a = abs(a);
auto abs_b = abs(b);
//if(abs_a == abs_b)
// return std::max(arg(a), arg(b));
return std::max(abs_a, abs_b);
}
);
for (std::size_t i =std::begin(y) ; i != std::end(y) ; i++) {
std::cout << "The max is found on index ["<< i <<"]" << max_val<< '\n';
}
return 0;
}
我收到以下错误: 输出:
main.cpp: In function 'int main()':
main.cpp:22:35: error: invalid conversion from 'std::complex<double>*' to 'std::size_t {aka long unsigned int}' [-fpermissive]
for (std::size_t i =std::begin(y) ; i != std::end(y) ; i++) {
^
main.cpp:22:54: error: ISO C++ forbids comparison between pointer and integer [-fpermissive]
for (std::size_t i =std::begin(y) ; i != std::end(y) ; i++) {
^
y
是valarray
的数组,因此您需要对该数组中的每个元素调用max
,而不是数组本身(当然没有成员函数)。std::complex
不是可比较的类型,那么有一个 "highest" 元素是什么意思?
更新:关于你的编辑,我想我明白你在追求什么......
对于max(by real()
)元素的最高索引:
std::size_t max_index(CArray const& y) {
struct acc_t {
double max_value;
std::size_t max_idx, current_idx;
constexpr acc_t next() const { return {max_value, max_idx, current_idx + 1}; }
constexpr acc_t next_with(Complex const c) const {
return {c.real(), current_idx, current_idx + 1};
}
};
return std::accumulate(
std::begin(y), std::end(y), acc_t{},
[](acc_t const acc, Complex const c) {
return c.real() < acc.max_value
? acc.next()
: acc.next_with(c);
}
).max_idx;
}
或者对于最大元素的所有索引:
std::vector<std::size_t> max_indices(CArray const& y) {
struct acc_t {
std::vector<std::size_t> max_idcs;
double max_value;
std::size_t current_idx;
constexpr acc_t&& next() {
++current_idx;
return std::move(*this);
}
acc_t&& next_with_current() {
max_idcs.push_back(current_idx++);
return std::move(*this);
}
acc_t&& next_with(Complex const c) {
max_value = c.real();
max_idcs.clear();
return next_with_current();
}
};
return std::accumulate(
std::begin(y), std::end(y), acc_t{},
[](acc_t& acc, Complex const c) {
return c.real() < acc.max_value ? acc.next()
: c.real() > acc.max_value ? acc.next_with(c)
: acc.next_with_current();
}
).max_idcs;
}
N.b。您的代码涉及 abs
,但我不确定为什么因为您说您只想基于 std::complex<>::real()
进行比较,所以我省略了...
使用std::accumulate可以得到复数的最大值,类似于Matlab的max函数:
#include <iostream>
#include <valarray>
#include <complex>
#include <algorithm>
#include <numeric>
typedef std::complex<double> Complex;
typedef std::valarray <Complex > CArray;
int main ()
{
CArray y={{1, 2},{3, 4},{2,0},{7,0},{9,0}};
auto max_val = std::accumulate (std::begin(y), std::end(y), *std::begin(y),
[](const Complex& a ,const Complex& b)
{
auto abs_a = abs(a);
auto abs_b = abs(b);
if(abs_a == abs_b)
return std::max(arg(a), arg(b));
return std::max(abs_a, abs_b);
}
);
std::cout << "The max is " << max_val<< '\n';
return 0;
}
编辑:问题已编辑,OP 想要获取复数实部最大值的索引,因此您的答案:
#include <iostream>
#include <valarray>
#include <complex>
#include <algorithm>
#include <numeric>
typedef std::complex<double> Complex;
typedef std::valarray <Complex > CArray;
int main ()
{
CArray y={{1, 2},{3, 4},{2,0},{7,0},{9,0}};
std::vector<int> index(y.size());
std::iota( index.begin(), index.end(), 0 );
auto max_index = std::accumulate (std::begin(index), std::end(index), *std::begin(index),
[&](int a ,int b)
{
return y[a].real() > y[b].real() ? a: b;
}
);
std::cout << "index of max is " << max_index<< '\n';
return 0;
}
编辑 2:正如@ildjarn 提到的,修改后的问题想要获得对应于最高元素的所有索引,因此修改后的答案:
#include <iostream>
#include <valarray>
#include <complex>
#include <algorithm>
#include <numeric>
typedef std::complex<double> Complex;
typedef std::valarray <Complex > CArray;
int main ()
{
CArray y={{1, 2},{3, 4},{2,0},{7,0},{9,0}};
std::vector<int> index(y.size());
std::iota( index.begin(), index.end(), 0 );
auto max_index = std::accumulate (std::begin(index), std::end(index), *std::begin(index),
[&](int a ,int b)
{
return y[a].real() > y[b].real() ? a: b;
}
);
std::vector<int> indices;
std::copy_if(std::begin(index), std::end(index), std::back_inserter(indices),
[&](int a)
{
return y[a] == y[max_index];
}
);
for (auto i: indices)
std::cout << "index of max is " << i << '\n';
return 0;
}
编辑 3:使用 std::max_element 我们拥有的最简单的解决方案:
#include <iostream>
#include <valarray>
#include <complex>
#include <algorithm>
#include <numeric>
#include <vector>
typedef std::complex<double> Complex;
typedef std::valarray <Complex > CArray;
int main ()
{
CArray y={{1, 2},{3, 4},{2,0},{9,0},{7,0},{9,0}};
auto max_index = std::max_element (std::begin(y), std::end(y),
[](const Complex& a ,const Complex& b)
{
return a.real() < b.real() ;
}
);
std::cout << "index of first max element is " << max_index-std::begin(y) << '\n';
std::cout << "indices of all matches of max element is: " << "[";
for (auto it= std::begin(y), end = std::end(y); it != end; ++it){
if(it->real() == max_index->real()) {
std::cout << it - std::begin(y) << ' ' ;
}
}
std::cout << "]";
return 0;
}
您的原始代码的更大问题是(正如 Ildjarn 所指出的)复杂缺少 operator<
。
我想你的 Complex
应该更复杂一点(如果你允许我玩文字游戏的话)。
我提出以下解决方案 Complex
来自 std::complex<double>
并声明一个朋友 operator< ()
。许多 operator< ()
可能之一。
#include <iostream>
#include <valarray>
#include <complex>
struct Complex: public std::complex<double>
{
template <typename ... Args>
Complex (const Args & ... args) : std::complex<double>{args...}
{ }
friend bool operator< (const Complex & c1, const Complex & c2)
{
return (c1.real() < c2.real())
|| ((c1.real() == c2.real()) && (c1.imag() < c2.imag()));
}
};
typedef std::valarray <Complex > CArray;
int main ()
{
CArray y { {1.0,2.0}, {3.0,4.0}, {2.0,0.0}, {7.0,0.0}, {9.0,0.0} };
std::cout << "The max is " << y.max() << '\n';
return 0;
}
如果您接受 Complex
可以是模板化的 class(使用 Class<double>
而不是 Complex
,您可以用这种方式编写更通用的解决方案(即也可以与基于 float
和 long double
)
#include <iostream>
#include <valarray>
#include <complex>
template <typename T>
struct Complex: public std::complex<T>
{
template <typename ... Args>
Complex (const Args & ... args) : std::complex<T>{args...}
{ }
friend bool operator< (const Complex & c1, const Complex & c2)
{
return (c1.real() < c2.real())
|| ((c1.real() == c2.real()) && (c1.imag() < c2.imag()));
}
};
typedef std::valarray <Complex<double>> CArray;
int main ()
{
CArray y { {1.0,2.0}, {3.0,4.0}, {2.0,0.0}, {7.0,0.0}, {9.0,0.0} };
std::cout << "The max is " << y.max() << '\n';
return 0;
}
p.s.: 应该也适用于 C++11。
p.s.2: 抱歉我的英语不好。
---编辑得到最大元素的索引---
#include <iostream>
#include <valarray>
#include <complex>
template <typename T>
struct Complex: public std::complex<T>
{
template <typename ... Args>
Complex (const Args & ... args) : std::complex<T>{args...}
{ }
friend bool operator< (const Complex & c1, const Complex & c2)
{
return (c1.real() < c2.real())
|| ((c1.real() == c2.real()) && (c1.imag() < c2.imag()));
}
};
typedef std::valarray <Complex<double>> CArray;
int main ()
{
CArray y { {1.0,2.0}, {3.0,4.0}, {2.0,0.0}, {7.0,0.0}, {9.0,0.0} };
auto m = 0U;
for ( auto i = 1U ; i < y.size() ; ++i)
if ( y[m] < y[i] )
m = i;
std::cout << "The max is found on index ["<< m <<"] and is " << y[m]
<< std::endl;
return 0;
}