SQL满足2个条件只返回1条记录的查询

SQL Query for returning only 1 record with 2 conditions satisfied

 WHERE (ADDR1 = '1500 Valley Rd' AND CUST_FLAG = 'P')     -- 1
    OR (ADDR1 = '1500 Valley Rd' AND CUST_FLAG = 'J')     -- 2

请帮我解决这个问题。我只需要显示 CUST_FLAG = 'P' 的记录。使用上面的 Where 子句,如果两个条件都满足,我将获得两个记录。 我的要求是:

  1. 如果只有第一个条件满足,则return记录CUST_FLAG = 'P'
  2. 如果只有第2个条件满足,则return记录CUST_FLAG = 'J'
  3. 如果两个条件都满足,则return只记录CUST_FLAG = 'P'.

尝试玩转case/when

case 
  when ADDR1 = '1500 Valley Rd' AND CUST_FLAG = 'P' then 'P'
  when ADDR1 = '1500 Valley Rd' AND CUST_FLAG = 'J' then 'J'
  else 'P' end

这是一个优先查询。要在单个 where 子句中执行此操作,您可以执行以下操作:

WHERE ADDR1 = '1500 Valley Rd' AND
      (CUST_FLAG = 'P' OR
       (CUST_FLAG = 'J' AND
        NOT EXISTS (SELECT 1 FROM t WHERE t.ADDR1 = outer.ADDR1 AND t.CUST_FLAG = 'J'
       ))

或者更典型的方法是使用ROW_NUMBER():

select t.*
from (select t.*, row_number() over (partition by addr1 order by cust_flag desc) as seqnum
      from (<your query here>) t
     ) t
where seqnum = 1;

您可以通过对记录进行排序并只取第一个来实现此目的。 (但请注意,ROWNUM 可能是 Oracle 特定的语法。)

SELECT * FROM (
SELECT <column_list> 
FROM <table>
WHERE ((ADDR1 = '1500 Valley Rd' AND CUST_FLAG = 'P')     -- 1
    OR (ADDR1 = '1500 Valley Rd' AND CUST_FLAG = 'J'))     -- 2
ORDER BY CUST_FLAG DESC
) WHERE ROWNUM = 1

从 Oracle 12c 开始,也可以使用以下语法:

SELECT <column_list> 
FROM <table>
WHERE ((ADDR1 = '1500 Valley Rd' AND CUST_FLAG = 'P')     -- 1
    OR (ADDR1 = '1500 Valley Rd' AND CUST_FLAG = 'J'))     -- 2
ORDER BY CUST_FLAG DESC
FETCH FIRST 1 ROWS ONLY;

另请参阅: - On ROWNUM and Limiting Results - How do I limit the number of rows returned by an Oracle query after ordering?