如何将复杂的 mysql 查询放入 zf2

Question

我无法将我的查询适合 zf2 查询，我可以适合简单的连接查询，但我无法编写更复杂的子查询。请帮我做这个。

SELECT `created_date` FROM `salesmodule_discussed_topic` dt WHERE dt.`meeting_id` IN( 
SELECT ma.`meeting_id` FROM `salesmodule_meeting_agent` ma WHERE ma.`agent_id`=30547
)



public function getLastmeetingdate() {
        $select = new Select();
        $select->from(array('dt' => 'salesmodule_discussed_topic'));
        $select->columns(array('created_date'));
        $select->where(array('ma.`agent_id` => 30547));
        $resultSet = $this->tableGateway->selectWith($select);
        return $resultSet->buffer();
    }

Answer 1

public function fetchAllSubQuery($id = '') {
    $columns = array("*");
    $where = "main_booking_id IN (SELECT 
            b1.`main_booking_id` 
            FROM
            `booking_sector` b1 
            WHERE b1.`connected_booking_id` = '$id' OR b1.`main_booking_id` = '$id') ";
     $resultSet = $this->tableGateway->select(function (Select $select) use ($where,$columns) {
            $select->where($where);
            $select->columns($columns);
        });
    $resultSet->buffer();
    // $resultSet->next();
    return $resultSet;
}

Answer 2

前面的例子不好，因为有一个 sql injections。您需要使用 Select.

进行子查询

public function getLastmeetingdate() {
    $subQuery = new Select();
    $subQuery->from(array('ma' => 'salesmodule_meeting_agent'));
    $subQuery->columns(array('meeting_id'));
    $subQuery->where(array('ma.agent_id' => 30547));

    $select = new Select();
    $select->from(array('dt' => 'salesmodule_discussed_topic'));
    $select->columns(array('created_date'));
    $select->where->in('dt.meeting_id', $subQuery);

    return $this->tableGateway->selectWith($select);
}

如何将复杂的 mysql 查询放入 zf2

how to fit complex mysql query into zf2

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