将文件读入struct c++数组

Question

我正在尝试将 .txt 文件读入此程序中的结构数组并显示内容。
该文件如下所示：

Smith   Jack    60    45    98  
Harry   Hisk    45    40    78  
Kay     Jacob   35.5  23    45  
Dos      hed    23    20    35  
Noa      Tom    55    12    32  
Joe      Peni   57    49    78  
Vin      San    25.6  23    65.5  
Jes      Dan    24.3  12    78  
Zi       Lee    56    49    99  
Angi     Dev    57    48    97  
Donald   David  60    50    96  
Davis    Lal    47    47    80  
Alvis   Sen     56    46    85  
Jack    Jill    45    45    75  
Messy   Lionel  60    49    100

我的代码是运行：

#include <iostream>
#include <string>
#include <fstream>
using namespace std;
int main(){
    const int SIZE=50;
    int i;
    struct Records {
        string firstname;
        string secondname;
        float test1mark;
        float midtestmark;
        float annualmark;
    }record[SIZE];

    ifstream in("Data.txt");

    if (!in){
    cerr << "File can't be opened! " << endl;
    system("PAUSE");
    exit(1);
    }
    for (int i=0; i < SIZE; i++){
    in >> record[i].firstname >> record[i].secondname 
    >>record[i].test1mark >> record[i].midtestmark >> record[i].annualmark ;
    }
    for (int i=0;i< SIZE;i++) {
        cout << record[i].firstname<<"  ";
        cout << record[i].secondname<<" ";
        cout << record[i].test1mark<<"  ";
        cout << record[i].midtestmark << "  ";
        cout << record[i].annualmark << "   ";
    }   
return 0;
}

我得到的输出：

Smith   Jack    60      45      98  
Harry   Hisk    45      40      78  
Kay     Jacob   35.5    23      45  
Dos     hed     23      20      35    
Noa     Tom     55      12      32  
Joe     Peni    57      49      78  
Vin     San     25.6    23      65.5  
Jes     Dan     24.3    12      78  
Zi      Lee     56      49      99  
Angi    Dev     57      48      97  
Donald  David   60      50      96  
Davis   Lal     47      47      80  
Alvis   Sen     56      46      85  
Jack    Jill    45      45      75  
Messy   Lionel  60      49      100  
                nan     0       8.94237e-039  
                4.36192e-039    0       -2.3511e-038  
                0       0       -2.3511e-038  
                0       0       0  
                1.32253e-038    0       1.32251e-038  
                4.2039e-045     0       -2.11122e+037  
                1.32251e-038    0       3.21276e-039  
                1.4013e-045     0       -2.3511e-038  
                1.4013e-045     0       3.76158e-037  
                0       0       3.76158e-037  
                0       0       1.12104e-044  
                4.36195e-039    0       4.36194e-039  
                3.57331e-043    0       6.0615e-039  
                0       0       3.21276e-039  
                4.2039e-045     0       6.41272e-039  
                1.12104e-044    0       6.63812e-039  
                4.36205e-039    0       -2.75237e+038  
                0       0       6.59812e-039  
                6.63426e-039    0       1.4013e-045  
                0       0       6.47961e-039  
                3.21319e-039    0       3.21319e-039  
                6.59812e-039    0       3.21299e-039  
                8.40779e-045    2.24208e-044    6.01433e-039  
                6.6045e-039     0       2.54408e-029  
                0       0       6.6045e-039  
                0       0       6.43946e-039  
                5.88656e-039    0       -4.12495e+011  
                0       0       0
                5.88656e-039    0       2.54408e-029  
                nan     nan     6.43029e-039  
                0       0       0
                5.93823e-039    0       -4.12495e+011  
                0       0       0
                5.93823e-039    0       5.74532e-044  
                nan     nan     5.93837e-039

进程在 0.05447 秒后退出，return 值为 0
按任意键继续。 . .

有人能告诉我它有什么问题吗？我试过使用指针，但情况变得更糟。 -初学者

Answer 1

您的文件有 15 行，因此您只能读取 15 行数据。您正在使用变量 SIZE 来控制应该读取多少行。

问题是SIZE是50！是不是15。当您尝试读取超过文件末尾时，输入将 not 读取超过第 16^th 行。所以，索引15之后的变量将是未初始化的，即undefined.

将文件中的行数增加到 50，或将 SIZE 更改为 15。

Answer 2

正如@Rackete1111 的另一个回答所述，您指定了太多项目，并且让读取数据的循环遍历了文件中的实际项目数。

话虽如此，只要您正确编写读取循环，夸大您拥有的记录数确实没有任何问题（除了浪费 space 如果您将数组的大小设置得太大）。以下是编写循环的方法，即使您使用 "mistake" 表示 50 项而不是 15 项：

#include <iostream>
#include <string>
#include <iostream>

using namespace std;

int main(){
    const int SIZE=50;
    int i;
    struct Records {
        string firstname;
        string secondname;
        float test1mark;
        float midtestmark;
        float annualmark;
    };

    Records record[SIZE];

    ifstream in("Data.txt");

    int recCount = 0;  // keep track of actual number of records

    // loop until we reach the end of file, or until we hit SIZE records,
    // whichever comes first
    while (!in.eof() && recCount < SIZE)
    {
        in >> record[recCount].firstname >> record[recCount].secondname 
        >>record[recCount].test1mark >> record[recCount].midtestmark >> record[recCount].annualmark ;
        ++recCount;
    }

    // now recCount == 15 if you have 15 items.

Live Example

请注意，我们有一个 while 循环，该循环将一直读取直到达到限制 (50)，或者到达文件末尾。

Answer 3

而且我相信我们不需要那个

int i;

开头

#include <iostream>
#include <string>
#include <fstream>
using namespace std;



ifstream in("Data.txt");
const int SIZE = 15;
void debugPrint();
void loadData();

struct Records {
    string firstname;
    string secondname;
    float test1mark;
    float midtestmark;
    float annualmark;   
}record[SIZE];

int main()
    {
    loadData();
    debugPrint();
    }

void debugPrint()
{
    for (int i = 0; i < SIZE; i++) 
    {
        cout << record[i].firstname << "  ";
        cout << record[i].secondname << " ";
        cout << record[i].test1mark << "  ";
        cout << record[i].midtestmark << "  ";
        cout << record[i].annualmark << "  " <<endl;        
    }
    system("PAUSE");
}

void loadData()
{   
    for (int i = 0; i < SIZE; i++)
    {
        if (!in)
        {                                               
            cerr << "File can't be opened! " << endl;
            system("PAUSE");
        }

        in >> record[i].firstname >> record[i].secondname
        >> record[i].test1mark >> record[i].midtestmark >> record[i].annualmark;
    }
}

将文件读入struct c++数组

Reading file into array of struct c++

c++

arrays

struct

fstream