"A loop" 如何在一个时钟内完成

Question

我试着找了很多代码来参考。

但是我找不到我需要的解决方案。

谁能帮我找到问题和解决方案？

非常感谢。

问题是我需要这个代码可以变量。

ero_check_t <= erosion_buf(0)(0)+erosion_buf(0)(1)+erosion_buf(0)(2)+
               erosion_buf(1)(0)+erosion_buf(1)(1)+erosion_buf(1)(2)+
               erosion_buf(2)(0)+erosion_buf(2)(1)+erosion_buf(2)(2);

像上码(3*3)可以变下码(2*2)。

ero_check_t <= erosion_buf(0)(0)+erosion_buf(0)(1)+
               erosion_buf(1)(0)+erosion_buf(1)(1);

我该怎么写？可以使用循环来编码吗？

process(rst)
begin
    if rst = '0' then
        ero_check   <= "0000000000";
        ero_check_t <= "0000000000";
    else
        for i in 0 to array_x loop
            for j in 0 to (array_y - 1) loop
                if i = array_x then
                    if j= 0 then
                        ero_check_t  <= ero_check;
                        ero_check    <= "0000000000";
                        exit;
                    end if;
                else
                    ero_check := ero_check + erosion_buf(i)(j);
                end if;
            end loop;
        end loop;
    end if;
end process;

Answer 1

简短的回答是肯定的。更长的答案是您可能想要检查您的代码是否完全符合您的要求（并且它也存在一些问题）。如果您想要执行此操作的组合逻辑：

ero_check_t <= erosion_buf(0)(0)+erosion_buf(0)(1)+erosion_buf(0)(2) + ...
               erosion_buf(1)(0)+erosion_buf(1)(1)+erosion_buf(1)(2) + ...
               erosion_buf(2)(0)+erosion_buf(2)(1)+erosion_buf(2)(2) + ...
               ...

那么像这样的东西就可以了：

process(erosion_buf)              -- erosion_buf is the only input
  variable e :                    -- the same type as ero_check_t
begin
  e :=                            -- zero (I don't know what type ero_check_t is)
  for i in 0 to array_x-1 loop    -- assuming array_x is the LENGTH of the x dimension
    for j in 0 to array_y-1 loop  -- assuming array_y is the LENGTH of the y dimension
       e := e + erosion_buf(i)(j);                     
    end loop;
  end loop;
  ero_check_t <= e;               -- drive the output signal
end process;

ero_chek 是一个变量。这被初始化为零，然后嵌套循环执行所有添加。最后，用变量 ero_check.

的内容驱动信号 ero_check_t

"A loop" 如何在一个时钟内完成

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vhdl