Laravel Socialite Google 注册并登录

Question

我正在尝试将 Socialite 包实施到我的项目中。这是我的代码，工作正常。但是，如果用户注销尝试重新登录，它会在数据库中重复输入。我也无法通过 $userData->name 获取用户的 public 名称。它 returns 无效。

这是我的控制器；

namespace App\Http\Controllers;

use App\AuthenticateUser;
use App\AuthenticateUserListener;
use App\Http\Requests;
use Illuminate\Http\Request;

class SocialLoginsController extends Controller implements 
AuthenticateUserListener
{
/**
 * @param AuthenticateUser $authenticateUser
 * @param Request $request
 * @return \Symfony\Component\HttpFoundation\RedirectResponse
 */
public function socialLogin(AuthenticateUser $authenticateUser, Request $request)
{
    $hasCode = $request->has('code');
    return $authenticateUser->execute($hasCode, $this);
}


/**
 * When a user has successfully been logged in...
 *
 * @param $user
 * @return \Illuminate\Routing\Redirector
 */
public function userHasLoggedIn($user)
{
    return redirect('student');
}

我的用户资料库；

namespace App\Repositories;
use App\User;


class UserRepository {


public function findByUsernameOrCreate($userData)
{

    return User::firstOrCreate([
        'username'  =>  $userData->name,
        'email' =>  $userData->email,

    ]);

}
}

验证用户 Class;

<?php namespace App;
use Illuminate\Contracts\Auth\Guard;
use App\Repositories\UserRepository;
use Laravel\Socialite\Contracts\Factory as Socialite;
class AuthenticateUser {
/**
 * @var UserRepository
 */
private $users;
/**
 * @var Socialite
 */
private $socialite;
/**
 * @var Guard
 */
private $auth;
/**
 * @param UserRepository $users
 * @param Socialite $socialite
 * @param Guard $auth
 */
public function __construct(UserRepository $users, Socialite $socialite, Guard $auth)
{
    $this->users = $users;
    $this->socialite = $socialite;
    $this->auth = $auth;
}
/**
 * @param boolean $hasCode
 * @param AuthenticateUserListener $listener
 * @return \Symfony\Component\HttpFoundation\RedirectResponse
 */
public function execute($hasCode, AuthenticateUserListener $listener)
{
    if ( ! $hasCode) return $this->getAuthorizationFirst();

    elseif($hasCode) {
        $user = $this->users->findByUsernameOrCreate($this->getGoogleUser());
        $this->auth->login($user, true);
        return $listener->userHasLoggedIn($user);
    }
}



/**
 * @return \Symfony\Component\HttpFoundation\RedirectResponse
 */
private function getAuthorizationFirst()
{
    return $this->socialite->driver('google')->redirect();
}


/**
 * @return \Laravel\Socialite\Contracts\User
 */
private function getGoogleUser()
{
    return $this->socialite->driver('google')->user();

}



}

Answer 1

除了我修改了 UserRepository 中的 findByUsernameOrCreate 方法外，我已经能够通过使用与您此处所用代码非常相似的代码来实现此功能。我创建了一个 syncUserDetails 方法，如下所示：

public function syncUserDetails($userData)
{
    if ( $user = $this->userRecordExists($userData) )
    {
        $user->token = $userData->token;
        $user->google_id = $userData->id;
        $user->name = $userData->name;
        $user->avatar = $userData->avatar;
        $user->first_name = $userData->user['name']['givenName'];
        $user->last_name = $userData->user['name']['familyName'];
        $user->save();

        return $user;
    }

    return $this->user->firstOrCreate([
        'email'      => $userData->email,
        'token'      => $userData->token,
        'google_id'  => $userData->id,
        'name'       => $userData->name,
        'avatar'     => $userData->avatar,
        'first_name' => $userData->user['name']['givenName'],
        'last_name'  => $userData->user['name']['familyName']
    ]);
}

它会检查数据库中是否已经存在具有匹配电子邮件的用户：

private function userRecordExists($userData)
{
    return $this->user->where('email', $userData->email)->first();
}

如果是，则将其与新数据和 returns 用户匹配。

希望对您有所帮助！

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