测试功能时出现未知解析错误

Question

我有下面的函数，它似乎可以正常工作，但是当运行程序通过测试程序时，我得到了错误：解析错误：[int xSwapped = ((255 << nShift) | (255 << mShift));] 和未声明的变量“xSwapped”：[return (~xSwapped & x) | n掩码 | mMask;]

int dl15(int x, int n, int m){
        // calculates shifts, create mask to shift, combine result
        // get number of bytes needed to shift, multiplying by 8
        // get Masks by shifting 0xff and shift amount
        // shift bits to required position
        // combine results

        int nShift = n<< 3;
        int mShift = m<< 3;

        int nMask = x & (255 << nShift);
        int mMask = x & (255 << mShift);
        nMask = 255 & (nMask >> nShift);
        mMask = 255 & (mMask >> mShift);
        nMask = nMask << mShift;
        mMask = mMask << nShift;

        int xSwapped = ((255 << nShift) | (255 << mShift));

        return (~xSwapped & x) | nMask | mMask;

}

不确定我缺少什么，谢谢。

Answer 1

您似乎正在使用设置为旧 C 标准的 C 编译器。在 C99 之前，您不能在声明之前放置可执行语句。

您可以通过将 xSwapped 的声明移动到顶部来解决此问题：

int nShift = n<< 3;
int mShift = m<< 3;

int nMask = x & (255 << nShift);
int mMask = x & (255 << mShift);
int xSwapped;                                   // Declaration
nMask = 255 & (nMask >> nShift);
mMask = 255 & (mMask >> mShift);
nMask = nMask << mShift;
mMask = mMask << nShift;

xSwapped = ((255 << nShift) | (255 << mShift)); // Assignment

return (~xSwapped & x) | nMask | mMask;

测试功能时出现未知解析错误

unknown parse error when testing function

c

parsing

parse-error