从 jquery 提交表单并在 jquery 中捕获表单提交事件

Question

我正在尝试从 jquery 调用表单提交并且我想在单击表单 submit.But 后禁用该按钮，出于某种原因它甚至没有调用 alert.If按下取消或支付按钮我想收到警报 hello.But 它没有调用 alert.Please 帮助。

$(document).ready(function() {
    var table  = $('#myTransactionitems').dataTable();  //Initialize the datatable
    var user = $(this).attr('id');
    if(user != '') 
    { 
        $.ajax({
            url: 'transactions',
            dataType: 'json',
            cache:false,
            success: function(s){
                console.log(s);
                table.fnClearTable();
                for(var i = 0; i < s.length; i++) {
                    var disp1 = '';
                    if (s[i][4] != 'Reserved') {
                        disp1 = 'display:none;'
                    }
                    table.fnAddData([
                        "<form method='post' action='reservesplit'><input name = 'transactionID' type='hidden'\
                    value='"+s[i][0]+"'></input><input type='submit' id = 'btn-bank' name='btn-bank' value = '"+s[i][0]+"' class='btn btn-link'>\
                   </input></form>",
                        s[i][1],
                        s[i][2],
                        s[i][3],
                        s[i][4],
                        s[i][5],
                        "<form method='post'><input name = 'transactionID' type='hidden'\
                    value='"+s[i][0]+"'><input name = 'donationID' type='hidden'\
                    value='"+s[i][2]+"'><input name = 'splitAmount' type='hidden'\
                    value='"+s[i][3]+"'></input></input><input type='submit' id = 'btn-paid' name='btn-paid' value = 'Paid'   style='" + disp1 +"' class='btn btn-success btn-sm pull-left '>\
                   </input></form><form method='post'><input name = 'transactionID' type='hidden'\
                    value='"+s[i][0]+"'><input name = 'donationID' type='hidden' \
                    value='"+s[i][2]+"'><input name = 'splitAmount' type='hidden'\
                    value='"+s[i][3]+"'></input><input type='submit' id = 'btn-cancel' name='btn-cancel' value = 'Cancel'  style='" + disp1 +"' class='btn btn-danger btn-sm pull-right'>\
                   </input></form>"
                        ]);                             
                } // End For

            },
            error: function(e){
                console.log(e.responseText);    
            }
        });
    }

    $('form').submit(function(){
        alert("hello");
        $(this).find(':submit').attr('disabled','disabled');
        $(this).parent("form").submit();
    });
});

Answer 1

您正在使用 AJAX 将表单动态添加到 DOM，这是异步的。因此，当您调用 $('form').submit() 来绑定您的处理程序时，表单尚未在 DOM 中。您需要在添加表单后调用它，方法是在 success: 函数中执行。

此外，$(this).parent("form").submit() 应该只是 $(this).submit()。 $(this) 是表格，你不需要去它的父级。并且您应该使用 event.preventDefault() 来防止正常的表单提交发生。

$(document).ready(function() {
    var table  = $('#myTransactionitems').dataTable();  //Initialize the datatable
    var user = $(this).attr('id');
    if(user != '') 
    { 
        $.ajax({
            url: 'transactions',
            dataType: 'json',
            cache:false,
            success: function(s){
                console.log(s);
                table.fnClearTable();
                for(var i = 0; i < s.length; i++) {
                    var disp1 = '';
                    if (s[i][4] != 'Reserved') {
                        disp1 = 'display:none;'
                    }
                    table.fnAddData([
                        "<form method='post' action='reservesplit'><input name = 'transactionID' type='hidden'\
                    value='"+s[i][0]+"'></input><input type='submit' id = 'btn-bank' name='btn-bank' value = '"+s[i][0]+"' class='btn btn-link'>\
                   </input></form>",
                        s[i][1],
                        s[i][2],
                        s[i][3],
                        s[i][4],
                        s[i][5],
                        "<form method='post'><input name = 'transactionID' type='hidden'\
                    value='"+s[i][0]+"'><input name = 'donationID' type='hidden'\
                    value='"+s[i][2]+"'><input name = 'splitAmount' type='hidden'\
                    value='"+s[i][3]+"'></input></input><input type='submit' id = 'btn-paid' name='btn-paid' value = 'Paid'   style='" + disp1 +"' class='btn btn-success btn-sm pull-left '>\
                   </input></form><form method='post'><input name = 'transactionID' type='hidden'\
                    value='"+s[i][0]+"'><input name = 'donationID' type='hidden' \
                    value='"+s[i][2]+"'><input name = 'splitAmount' type='hidden'\
                    value='"+s[i][3]+"'></input><input type='submit' id = 'btn-cancel' name='btn-cancel' value = 'Cancel'  style='" + disp1 +"' class='btn btn-danger btn-sm pull-right'>\
                   </input></form>"
                        ]);                             
                } // End For

                $('form').submit(function(e){
                    alert("hello");
                    e.preventDefault();
                    $(this).find(':submit').attr('disabled','disabled');
                    $(this).submit();
                });
            },
            error: function(e){
                console.log(e.responseText);    
            }
        });
    }
});

或者您可以使用事件委托，如 Event binding on dynamically created elements?

中所述

从 jquery 提交表单并在 jquery 中捕获表单提交事件

Submit a form from jquery and catch the form submitted event inside jquery

forms

jquery

submit