为什么 *S Slice 可以由文字 S 开头？

Question

我在 the go programming language 的第 187 页看到了这个语法。

var tracks = []*Track{
    {"Go", "Delilah", "From the Roots Up", 2012, length("3m38s")},
    {"Go", "Moby", "Moby", 1992, length("3m37s")},
    {"Go Ahead", "Alicia Keys", "As I Am", 2007, length("4m36s")},
    {"Ready 2 Go", "Martin Solveig", "Smash", 2011, length("4m24s")},
}

难道只是

的语法糖

var tracks = []*Track{
    &Track{"Go", "Delilah", "From the Roots Up", 2012, length("3m38s")},
    &Track{"Go", "Moby", "Moby", 1992, length("3m37s")},
    &Track{"Go Ahead", "Alicia Keys", "As I Am", 2007, length("4m36s")},
    &Track{"Ready 2 Go", "Martin Solveig", "Smash", 2011, length("4m24s")},
}

我没有用谷歌搜索它的规格，如果有请给我link。

Answer 1

来自ref spec

Within a composite literal of array, slice, or map type T, elements or map keys that are themselves composite literals may elide the respective literal type if it is identical to the element or key type of T. Similarly, elements or keys that are addresses of composite literals may elide the &T when the element or key type is *T.

[...]*Point{{1.5, -3.5}, {0, 0}}    // same as [...]*Point{&Point{1.5, -3.5}, &Point{0, 0}}

为什么 *S Slice 可以由文字 S 开头？

Why can a *S Slice be initialed by literal S?

arrays

go

slice