将此 jekyll 代码转换为 PHP 的最有效方法是什么？

Question

{% for post in site.posts limit: 12 %}
    <a href="{{post.url}}" style="background-image: url(assets/img/posts/thumbnails/{{post.thumbnail}})" class="academic-thumb">
        <div class="academic-meta">
            <div class="name">
                {{post.title}}
            </div>
        </div>
    </a>
{% endfor %}

Answer 1

<?php
  foreach ($site->getPosts() as $post) {
    echo '
      <a href="'. $post->getUrl() .'" style="background-image: url(assets/img/posts/thumbnails/'. $post->getThumbnail() .')" class="academic-thumb">
    <div class="academic-meta">
        <div class="name">
            '. $post->getTitle() .'
        </div>
    </div>
        </a>';
  }

这当然只有在 $post 对象可用且变量已收集时才有效。

您还应该听听@borracciaBlu：先学习 ruby 语法，然后再学习 php 语法

将此 jekyll 代码转换为 PHP 的最有效方法是什么？

What is the most efficient way to convert this jekyll code to PHP?

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