如何添加排名列？

Question

我想select记录并确定每个相似数据的排名。

我的数据如下

MEMBER ID | LOAN AMOUNT 
1         | 2,000.00 
2         | 1,000.00 
3         | 4,000.00
4         | 1,000.00

我想要的结果如下图。

RANK|MEMBER ID|LOAN AMOUNT 
1   |3        |4,000.00
2   |1        |2,000.00
3   |2        |1,000.00
3   |4        |1,000.00

RANK 是一个新列。我正在使用 MS SQL server 2008 并创建了一个视图 table，如下所示，但它没有达到我想要的效果。

  select rank=count(*), s1.MemberID, s1.Loan_Amount 
   from (select MemberID, Loan_Amount from vwPrintTop20Borrowers) s1
   group by s1.MemberID, s1.LOAN_AMOUNT
     order by rank, s1.Loan_amount DESC

请帮忙。谢谢！ :)

Answer 1

只需使用 RANK() :

SELECT RANK() OVER(ORDER BY t.loan_amount DESC) as [rank],
       t.memeber_id,t.loan_amount
FROM YourTable t

虽然这会导致空隙 E.G.

RANK | AMOUNT
 1        10
 2         9
 3         8
 3         8
 5         7

为避免这种情况，对于 SQL-Server 2008+，请使用 DENSE_RANK()

DENSE_RANK() OVER(ORDER BY t.loan_amount DESC) as [rank]

Answer 2

使用以下查询：

Select Dense_Rank() OVER(ORDER BY [LOAN AMOUNT] DESC) as [Rank],[MEMBER ID],[LOAN AMOUNT]  
from YourTable

Answer 3

SELECT ROW_NUMBER() 
        OVER (ORDER BY Loan_Amount DESC) AS Rank, 
    MemberID, LOAN_AMOUNT,
FROM vwPrintTop20Borrowers

Answer 4

   select * into #P from (
   select      1  as [MEMBER ID]        , 2000.00 as  [LOAN AMOUNT]  union   all
   select     2                      , 1000.00  union all
   select     3                         , 4000.00   union all
   select     4                         , 1000.00 
 )P


 select rank()over(  order by [LOAN AMOUNT] desc) as srno,[MEMBER ID],[LOAN AMOUNT] from #P

输出：

        srno    MEMBER ID   LOAN AMOUNT
           1          3     4000.00
           2          1     2000.00
           3          2     1000.00
           3          4     1000.00

如何添加排名列？

How to add rank column?

sql

sql-server

rank