Umbraco路由定义-ajax形式

Umbraco route definition-ajax form

您好 :) 我遇到了错误 "Cannot find the Umbraco route definition in the route values, the request must be made in the context of an Umbraco request" 和 return 这个错误的代码 - "return RedirectToCurrentUmbracoPage();"。 seding ajax 形式后。

这是我的控制器:

public class ContactController : Umbraco.Web.Mvc.SurfaceController
{
    private string GMAIL_SERVER = "smtp.gmail.com";
    private int PORT = 587;

    [ChildActionOnly]
    public ActionResult ContactForm()
    {
        var model = new ContactFormModel()
        {
           Email = "",
           Name = "",
           Subject = "",
           Message = ""
        };

        return PartialView("ContactForm", model);
    }

    [NotChildAction]
    [HttpPost]
    public ActionResult ContactForm(ContactFormModel model)
    {
        var fromAddress = new MailAddress("xxx@gmail.com", model.Name);
        var toAddress = new MailAddress("xxx@gmail.com", "To Name");
        string fromPassword = "xxx";
        string subject = model.Subject;
        string body = model.Message;

        var smtp = new SmtpClient
        {
            Host = "smtp.gmail.com",
            Port = 587,
            EnableSsl = true,
            DeliveryMethod = SmtpDeliveryMethod.Network,
            Credentials = new NetworkCredential(fromAddress.Address, fromPassword),
            Timeout = 20000
        };

        if (!ModelState.IsValid)
        {        
            return CurrentUmbracoPage();
        }

        var message = new MailMessage(fromAddress, toAddress)
        {
            Subject = model.Subject,
            Body = "test"
        };
        smtp.Send(message);

        return RedirectToCurrentUmbracoPage();
    }
}

和此表单代码:

@using (Ajax.BeginForm("ContactForm" ,"Contact", new AjaxOptions { HttpMethod = "POST", InsertionMode = InsertionMode.Replace }))
{
    @Html.TextBoxFor(m => m.Name, null, new { name = "name", id = "name", placeholder = "Name" })
    @Html.ValidationMessageFor(m => m.Name)
    @Html.TextBoxFor(m => m.Email, null, new { name = "email", id = "email", placeholder = "Email address" })
    @Html.ValidationMessageFor(m => m.Email)
    @Html.TextBoxFor(m => m.Subject, null, new { name = "subject", id = "subject", placeholder = "Subject" })
    @Html.ValidationMessageFor(m => m.Subject)
    @Html.TextAreaFor(m => m.Message, new { rows = "", cols = "", name = "message", id = "message", placeholder = "Your message" })
    @Html.ValidationMessageFor(m => m.Message)
    <input type="submit" id="contact-submit" value="SEND MESSAGE">
}

首先,我们要明白这次投稿我们想要达到什么目的。 Ajax 请求不是典型页面请求的一部分,在此期间未传递/填充 Umbraco 上下文。如果我们想重新加载/刷新同一页面,我们可以使用操作的 Javascript 结果并执行简单的重新加载,例如

return JavaScript("location.reload(true)");

如果我们想使用 Umbraco 上下文(Url 或其他任何东西),我们可以手动启动 UmbracoHelper 并用它做任何我们想做的事情:

var umbracoHelper = new UmbracoHelper(UmbracoContext.Current);
var node = umbracoHelper.TypedContent(nodeId);
//...

或者只使用带有 Umbraco 实现/包装器的 WebAPI 控制器,您可以在此处阅读更多信息:https://our.umbraco.org/documentation/reference/routing/webapi/

如果这是典型的 SurfaceController 操作(不是 Ajax 调用),我们可以使用 Umbraco 包装器中可用的所有可能的重定向和方法(检查:https://our.umbraco.org/documentation/reference/templating/mvc/forms)。

我们还可以 return 任何 PartialView、Content 甚至 JSON 如果在积极提交表单后需要的话。在我看来,这是这种情况下的最佳解决方案。你的情况:

[NotChildAction]
[HttpPost]
public ActionResult ContactForm(ContactFormModel model)
{
    var fromAddress = new MailAddress("xxx@gmail.com", model.Name);
    var toAddress = new MailAddress("xxx@gmail.com", "To Name");
    string fromPassword = "xxx";
    string subject = model.Subject;
    string body = model.Message;

    var smtp = new SmtpClient
    {
        Host = "smtp.gmail.com",
        Port = 587,
        EnableSsl = true,
        DeliveryMethod = SmtpDeliveryMethod.Network,
        Credentials = new NetworkCredential(fromAddress.Address, fromPassword),
        Timeout = 20000
    };

    if (!ModelState.IsValid)
    {        
        return PartialView("_Error");
    }

    var message = new MailMessage(fromAddress, toAddress)
    {
        Subject = model.Subject,
        Body = "test"
    };
    smtp.Send(message);

    return PartialView("_Success");
}

希望对您有所帮助!