将数组的散列与数组进行比较以找到相似之处
Comparing a hash of arrays to an array to find similarities
我正在尝试将 selected animal_id 数组与 owners_to_animals 数组中的 "animal_id" 对象进行比较,这样我就可以得到一个仅包含相关项的列表owner_id 的。我尝试遍历哈希,然后仅 select animal_id 对象在 animal_id 数组中匹配,但它打印出 animal_id=20 不属于 animal_id数组。
animal_id = [23, 53, 63]
owners_to_animals = [
{ "owner_id" => 73, "animal_id" => 53 },
{ "owner_id" => 73, "animal_id" => 23 },
{ "owner_id" => 73, "animal_id" => 63 },
{ "owner_id" => 73, "animal_id" => 20 },
{ "owner_id" => 83, "animal_id" => 23 },
{ "owner_id" => 83, "animal_id" => 63 }
]
owners_to_animals.each do |x|
# puts x
# x.each do |y|
for i in animal_id do
# puts i
if x.select { |a| a["animal_id"] == i }
puts x
else
puts "no"
end
end
# end
end
我很困惑为什么 x returns:
{"owner_id"=>73, "animal_id"=>53}
{"owner_id"=>73, "animal_id"=>53}
{"owner_id"=>73, "animal_id"=>53}
{"owner_id"=>73, "animal_id"=>23}
{"owner_id"=>73, "animal_id"=>23}
{"owner_id"=>73, "animal_id"=>23}
{"owner_id"=>73, "animal_id"=>63}
{"owner_id"=>73, "animal_id"=>63}
{"owner_id"=>73, "animal_id"=>63}
{"owner_id"=>73, "animal_id"=>20}
{"owner_id"=>73, "animal_id"=>20}
{"owner_id"=>73, "animal_id"=>20}
{"owner_id"=>83, "animal_id"=>23}
{"owner_id"=>83, "animal_id"=>23}
{"owner_id"=>83, "animal_id"=>23}
{"owner_id"=>83, "animal_id"=>63}
{"owner_id"=>83, "animal_id"=>63}
{"owner_id"=>83, "animal_id"=>63}
如果没有匹配项,select
将 return 一个空数组,在 Ruby 中是一个 "truthy" 值,因此代码的 else
分支永远不会被执行。
if []
puts "true"
else
puts "false"
end
# Outputs "true"
你想实现的可以一行完成:
puts owners_to_animals.select { |x| animal_id.include?(x["animal_id"]) }
# Output:
{"owner_id"=>73, "animal_id"=>53}
{"owner_id"=>73, "animal_id"=>23}
{"owner_id"=>73, "animal_id"=>63}
{"owner_id"=>83, "animal_id"=>23}
{"owner_id"=>83, "animal_id"=>63}
我正在尝试将 selected animal_id 数组与 owners_to_animals 数组中的 "animal_id" 对象进行比较,这样我就可以得到一个仅包含相关项的列表owner_id 的。我尝试遍历哈希,然后仅 select animal_id 对象在 animal_id 数组中匹配,但它打印出 animal_id=20 不属于 animal_id数组。
animal_id = [23, 53, 63]
owners_to_animals = [
{ "owner_id" => 73, "animal_id" => 53 },
{ "owner_id" => 73, "animal_id" => 23 },
{ "owner_id" => 73, "animal_id" => 63 },
{ "owner_id" => 73, "animal_id" => 20 },
{ "owner_id" => 83, "animal_id" => 23 },
{ "owner_id" => 83, "animal_id" => 63 }
]
owners_to_animals.each do |x|
# puts x
# x.each do |y|
for i in animal_id do
# puts i
if x.select { |a| a["animal_id"] == i }
puts x
else
puts "no"
end
end
# end
end
我很困惑为什么 x returns:
{"owner_id"=>73, "animal_id"=>53}
{"owner_id"=>73, "animal_id"=>53}
{"owner_id"=>73, "animal_id"=>53}
{"owner_id"=>73, "animal_id"=>23}
{"owner_id"=>73, "animal_id"=>23}
{"owner_id"=>73, "animal_id"=>23}
{"owner_id"=>73, "animal_id"=>63}
{"owner_id"=>73, "animal_id"=>63}
{"owner_id"=>73, "animal_id"=>63}
{"owner_id"=>73, "animal_id"=>20}
{"owner_id"=>73, "animal_id"=>20}
{"owner_id"=>73, "animal_id"=>20}
{"owner_id"=>83, "animal_id"=>23}
{"owner_id"=>83, "animal_id"=>23}
{"owner_id"=>83, "animal_id"=>23}
{"owner_id"=>83, "animal_id"=>63}
{"owner_id"=>83, "animal_id"=>63}
{"owner_id"=>83, "animal_id"=>63}
select
将 return 一个空数组,在 Ruby 中是一个 "truthy" 值,因此代码的 else
分支永远不会被执行。
if []
puts "true"
else
puts "false"
end
# Outputs "true"
你想实现的可以一行完成:
puts owners_to_animals.select { |x| animal_id.include?(x["animal_id"]) }
# Output:
{"owner_id"=>73, "animal_id"=>53}
{"owner_id"=>73, "animal_id"=>23}
{"owner_id"=>73, "animal_id"=>63}
{"owner_id"=>83, "animal_id"=>23}
{"owner_id"=>83, "animal_id"=>63}