Python mock call_args_list 解包元组以断言参数
Python mock call_args_list unpacking tuples for assertion on arguments
我在处理 Mock.call_args_list
returns.
的嵌套元组时遇到了一些问题
def test_foo(self):
def foo(fn):
fn('PASS and some other stuff')
f = Mock()
foo(f)
foo(f)
foo(f)
for call in f.call_args_list:
for args in call:
for arg in args:
self.assertTrue(arg.startswith('PASS'))
我想知道是否有更好的方法来解压缩模拟对象上的 call_args_list 以做出我的断言。这个循环有效,但感觉必须有更直接的方法。
更好的方法可能是自己建立预期调用,然后使用直接断言:
>>> from mock import call, Mock
>>> f = Mock()
>>> f('first call')
<Mock name='mock()' id='31270416'>
>>> f('second call')
<Mock name='mock()' id='31270416'>
>>> expected_calls = [call(s + ' call') for s in ('first', 'second')]
>>> f.assert_has_calls(expected_calls)
请注意,调用必须是连续的,如果您不希望这样,则覆盖断言的 any_order
kwarg。
另请注意,允许在
指定的调用。如果你不想那样,你需要添加另一个断言:
>>> assert f.call_count == len(expected_calls)
针对 mgilson 的评论,这里有一个创建可用于通配符相等性比较的虚拟对象的示例:
>>> class AnySuffix(object):
... def __eq__(self, other):
... try:
... return other.startswith('PASS')
... except Exception:
... return False
...
>>> f = Mock()
>>> f('PASS and some other stuff')
<Mock name='mock()' id='28717456'>
>>> f('PASS more stuff')
<Mock name='mock()' id='28717456'>
>>> f("PASS blah blah don't care")
<Mock name='mock()' id='28717456'>
>>> expected_calls = [call(AnySuffix())]*3
>>> f.assert_has_calls(expected_calls)
及故障模式示例:
>>> Mock().assert_has_calls(expected_calls)
AssertionError: Calls not found.
Expected: [call(<__main__.AnySuffix object at 0x1f6d750>),
call(<__main__.AnySuffix object at 0x1f6d750>),
call(<__main__.AnySuffix object at 0x1f6d750>)]
Actual: []
我认为这里的许多困难都集中在 "call" 对象的处理上。它可以被认为是一个有 2 个成员 (args, kwargs)
的元组,所以解压它通常很好:
args, kwargs = call
解压后,您可以分别对 args 和 kwargs 进行断言(因为一个是元组,另一个是字典)
def test_foo(self):
def foo(fn):
fn('PASS and some other stuff')
f = Mock()
foo(f)
foo(f)
foo(f)
for call in f.call_args_list:
args, kwargs = call
self.assertTrue(all(a.startswith('PASS') for a in args))
请注意,有时简洁并无帮助(例如,如果出现错误):
for call in f.call_args_list:
args, kwargs = call
for a in args:
self.assertTrue(a.startswith('PASS'), msg="%s doesn't start with PASS" % a)
我在处理 Mock.call_args_list
returns.
def test_foo(self):
def foo(fn):
fn('PASS and some other stuff')
f = Mock()
foo(f)
foo(f)
foo(f)
for call in f.call_args_list:
for args in call:
for arg in args:
self.assertTrue(arg.startswith('PASS'))
我想知道是否有更好的方法来解压缩模拟对象上的 call_args_list 以做出我的断言。这个循环有效,但感觉必须有更直接的方法。
更好的方法可能是自己建立预期调用,然后使用直接断言:
>>> from mock import call, Mock
>>> f = Mock()
>>> f('first call')
<Mock name='mock()' id='31270416'>
>>> f('second call')
<Mock name='mock()' id='31270416'>
>>> expected_calls = [call(s + ' call') for s in ('first', 'second')]
>>> f.assert_has_calls(expected_calls)
请注意,调用必须是连续的,如果您不希望这样,则覆盖断言的 any_order
kwarg。
另请注意,允许在 指定的调用。如果你不想那样,你需要添加另一个断言:
>>> assert f.call_count == len(expected_calls)
针对 mgilson 的评论,这里有一个创建可用于通配符相等性比较的虚拟对象的示例:
>>> class AnySuffix(object):
... def __eq__(self, other):
... try:
... return other.startswith('PASS')
... except Exception:
... return False
...
>>> f = Mock()
>>> f('PASS and some other stuff')
<Mock name='mock()' id='28717456'>
>>> f('PASS more stuff')
<Mock name='mock()' id='28717456'>
>>> f("PASS blah blah don't care")
<Mock name='mock()' id='28717456'>
>>> expected_calls = [call(AnySuffix())]*3
>>> f.assert_has_calls(expected_calls)
及故障模式示例:
>>> Mock().assert_has_calls(expected_calls)
AssertionError: Calls not found.
Expected: [call(<__main__.AnySuffix object at 0x1f6d750>),
call(<__main__.AnySuffix object at 0x1f6d750>),
call(<__main__.AnySuffix object at 0x1f6d750>)]
Actual: []
我认为这里的许多困难都集中在 "call" 对象的处理上。它可以被认为是一个有 2 个成员 (args, kwargs)
的元组,所以解压它通常很好:
args, kwargs = call
解压后,您可以分别对 args 和 kwargs 进行断言(因为一个是元组,另一个是字典)
def test_foo(self):
def foo(fn):
fn('PASS and some other stuff')
f = Mock()
foo(f)
foo(f)
foo(f)
for call in f.call_args_list:
args, kwargs = call
self.assertTrue(all(a.startswith('PASS') for a in args))
请注意,有时简洁并无帮助(例如,如果出现错误):
for call in f.call_args_list:
args, kwargs = call
for a in args:
self.assertTrue(a.startswith('PASS'), msg="%s doesn't start with PASS" % a)