在 SQL 中的多个值中查找多个值

Question

这是一个比较特殊的问题：

 id |   column_num   |
 ---|----------------|
   1|  5,12,64,7,78  |
   2|  5,53,7,6      |
   3|  94,78,32,27   |

我需要找到具有以下值的行：12、7、78

我需要查找对应于单元格 SQL 的多个值。我使用 MySQL。你有想法吗？

谢谢

Answer 1

好的，我已经得出解决方案，希望对您有所帮助。

Note: You may normalize the query by yourself as I just share my concept on this problem.

查询如下:-

CREATE TABLE table1
(
    id int,
    column_num varchar (max)
) 

INSERT INTO table1 (id, column_num) VALUES
(1, '5,12,64,7,78'),
(2, '5,53,7,6'),
(3, '94,78,32,27'),
(4, '1,74,32,12,78')

CREATE VIEW vSeperate_Num AS
WITH tmp(id, num, column_num) AS
(
    SELECT id, LEFT(column_num, CHARINDEX(',',column_num+',')-1), STUFF(column_num, 1, CHARINDEX(',',column_num+','), '')
    FROM table1
    UNION ALL
    SELECT id, LEFT(column_num, CHARINDEX(',',column_num+',')-1), STUFF(column_num, 1, CHARINDEX(',',column_num+','), '')
    FROM tmp
    WHERE column_num > ''
)
SELECT id, num
FROM tmp

;WITH Contain_Selected_Num AS
(
    SELECT *
    FROM
    (
        SELECT id, num
        FROM vSeperate_Num
    ) AS pvt
    PIVOT
    (
        COUNT(num)
        FOR num IN ( [12], [7], [78] )
    ) AS pvt
)
SELECT *
FROM table1
WHERE id IN
(
    SELECT id
    FROM Contain_Selected_Num
    WHERE [12] > 0 AND [7] > 0 AND [78] > 0
)

谢谢。 :)

Answer 2

至少匹配一个，试试：

select * From table_name where 
column_num = '12' or column_num like '%,12,%' or column_num like '%,12' or column_num like '12,%'
union 
select * From table_name where 
column_num = '7' or column_num like '%,7,%' or column_num like '%,7' or column_num like '7,%'
union 
select * From table_name where 
column_num = '78' or column_num like '%,78,%' or column_num like '%,78' or column_num like '78,%'

拥有所有三个值，试试这个 SQL:

select * From table_name where (column_num = '12' or column_num like '%,12,%' or column_num like '%,12' or column_num like '12,%')
and (column_num = '7' or column_num like '%,7,%' or column_num like '%,7' or column_num like '7,%')
and (column_num = '78' or column_num like '%,78,%' or column_num like '%,78' or column_num like '78,%')

Answer 3

您可以尝试以下方法：

在每个字符串的开头和结尾添加一个 ,，即 5,12,64,7,78 -> ,5,12,64,7,78,

然后你可以对每个数字应用MySQL的locate()函数。

select id, column_num from (
select id, column_num,
       locate(',12,', column_num) as m12, 
       locate(',7,', column_num) as m7, 
       locate(',78,', column_num) as m78 
from your_table
) a
where m12 > 0 and m7 > 0 and m78 > 0;

如果某个数字不在字符串中，则locate的结果为0，否则为字符串中的位置。在外部查询中，您可以在 where 语句中进行检查。

where语句可以很容易地根据您的需要进行调整，例如如果您需要匹配所有三个数字或至少一个数字。

Answer 4

感谢您的回答。我必须通过函数 FIND_IN_SET 通过 PHP.

卷曲来找到解决方案

$_POST['test_ids'] = [12,7,78];

if (!empty($_POST['test_ids'])) {
    $filter .= ' AND (';
    $i = 0;
    foreach ($_POST['test_ids'] as $id) {
        $filter .= ($i > 0) ? ' OR ' : '';
        $filter .= ' FIND_IN_SET(\'' . $id . '\', column_num) ';
        $i++;
    }
    $filter .= ') ';
}

在 SQL 中的多个值中查找多个值

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