batch - 当前批量处理的文件目录

Question

我正在尝试使用解包器来提取多个文件。我的脚本是这样的

for /R %%i in (*.ext) DO quickbms.exe -o script.bms "%%i" "%%~ni"

问题是当我从 C:\archives 删除文件时，它会将所有文件提取到该目录，包括 C:\archives\dir1、C:\archives\dir2、etc.[= 中的档案15=]

如何将所有存档提取到它们自己的文件夹中，而不必在每个文件夹中手动启动脚本？

Answer 1

for /R %%i in (*.ext) DO quickbms.exe -o script.bms "%%~i" "%%~dpni"

请阅读for /?：修饰符可以组合以获得复合结果。

来自 Command Line arguments (Parameters):

…

%~f1 Expand %1 to a Fully qualified path name - C:\utils\MyFile.txt

%~d1 Expand %1 to a Drive letter only - C:

%~p1 Expand %1 to a Path only e.g. \utils\ this includes a trailing \ which will be interpreted as an escape character by some commands.

%~n1 Expand %1 to a file Name without file extension C:\utils\MyFile or if only a path is present (with no trailing backslash) - the last folder in that path.

…

您的 "%%~pi\%%~ni" 将导致（根据上述示例）\utils\MyFile.txt（注意两个连续的 \ reverse solidi）。
幸运的是，批处理解释器将路径中的双重 \（甚至多重）反斜杠视为单个 \ reverse solidus…

batch - 当前批量处理的文件目录

batch - Directory of the currently processed file in batch

batch-file

batch-processing