基于指针的代码在代码块中给出分段错误

Question

这是我的代码。我一直在代码末尾遇到分段错误。所有事情运行都很好，但分段错误出现在最后。

我正在尝试准备西洋跳棋游戏，第一步是用符号初始化每个棋子。此代码尝试执行相同的操作。

代码块版本：13.12 Windows 7

#include <stdio.h>
#include <stdlib.h>

#define boardheight 8
#define boardwidth 8
struct Player_symbols{
    char symbol;
    char king_symbol;
};

struct Checker_piece{
    char king;
    int on_board;
    int num_moves;
    int player;
    struct Player_symbols* symbols;
};

int pieces_count[2] = {12,12};
struct Checker_piece* player_1_pieces;
struct Checker_piece* player_2_pieces;

void initialize_player_pieces(struct Checker_piece* player_pieces, struct Player_symbols* player_symbols, int player_num);
void initialize_board(struct Checker_piece* checker_board[boardheight][boardwidth],struct Checker_piece* player1,struct Checker_piece* player2);
void print_board(struct Checker_piece* checker_board[boardheight][boardwidth]);
int move_piece(struct Checker_piece* checker_board[boardheight][boardwidth], int x,int y,int player);
void continue_jumping(struct Checker_piece* checker_board[boardheight][boardwidth],int* y,int* x,int player);
int generate_destination(int x, int *dest_x, int *dest_y, int *dest_y_jump,int dest_y2,int dest_y2_jump,int move_flags,int player);

int main()
{

    struct Checker_piece* checker_board[boardheight][boardwidth];
    struct Checker_piece* dummy;
    struct Player_symbols* dummy_symbol;
    //declare and initialize the Checker_piece structures by allocating memory dynamically using a dummy structure to determine its size
    player_1_pieces = malloc(12*sizeof dummy);
    player_2_pieces = malloc(12*sizeof dummy);
    struct Player_symbols *player_1_symbols,*player_2_symbols;

    player_1_symbols = malloc(sizeof dummy_symbol);
    player_2_symbols = malloc(sizeof dummy_symbol);

    //initialize the player symbols
    player_1_symbols->symbol = 'o';
    player_1_symbols->king_symbol = 'O';
    player_2_symbols->symbol = 'x';
    player_2_symbols->king_symbol = 'X';

    initialize_player_pieces(player_1_pieces,player_1_symbols,1);
    initialize_player_pieces(player_2_pieces,player_2_symbols,2);

    printf("Done");
    return 0;
}

void initialize_player_pieces(struct Checker_piece* player_pieces, struct Player_symbols* player_symbols, int player_num){
    int i;
    for (i=0; i<12; i++, player_pieces++ ) {
        player_pieces->king='N';
        player_pieces->num_moves=0;
        player_pieces->on_board=1;
        player_pieces->player=player_num;
        player_pieces->symbols= player_symbols;
    }
}

Answer 1

你的 check_board 被声明为 指针数组 而它应该是 struct 数组. dummy 和 dummy_symbol 也是如此（顺便说一句，你甚至不需要）。

如果你想malloc一个符号，那么malloc一个符号，而不是指向一个符号的指针。但是您甚至不需要 malloc 那些：只需声明基于堆栈的变量：

struct Player_symbols player_1_symbols; // no pointer, no malloc needed

Answer 2

我建议您对代码稍作改动。当您使用结构时，然后将内存动态分配给结构而不是指向变量的指针。

struct Checker_piece* checker_board[boardheight][boardwidth];



 struct Checker_piece* dummy;
    struct Player_symbols* dummy_symbol;

    player_1_pieces = (Checker_piece *)malloc(12*sizeof(Checker_piece));
    player_2_pieces = (Checker_piece *)malloc(12*sizeof(Checker_piece));
    struct Player_symbols *player_1_symbols,*player_2_symbols;

    player_1_symbols = (Player_symbols *)malloc(sizeof(Player_symbols));
    player_2_symbols = (Player_symbols *)malloc(sizeof(Player_symbols));

PS-如果您在 C 中编程，则无需键入 cast malloc。

基于指针的代码在代码块中给出分段错误

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