使用 python 3.4 而不是 python 3.5

Question

我在互联网上找到了一个脚本，它在 Python 3.4 中有效，但在 Python 3.5 中无效。我对 python 不太熟悉，但它有

#!/usr/bin/env python3

schlebang 在文件的顶部。当我尝试 运行 它时它也会抛出这个异常：

追溯（最近调用最后）：

File "/home/username/folder/script.py", line 18, in

doc = opener.open(url)

File "/usr/lib/python3.5/urllib/request.py", line 472, in open

response = meth(req, response)

File "/usr/lib/python3.5/urllib/request.py", line 582, in http_response 'http', request, response, code, msg, hdrs)

File "/usr/lib/python3.5/urllib/request.py", line 504, in error

result = self._call_chain(*args)

File "/usr/lib/python3.5/urllib/request.py", line 444, in _call_chain

result = func(*args)

File "/usr/lib/python3.5/urllib/request.py", line 968, in http_error_401 url, req, headers)

File "/usr/lib/python3.5/urllib/request.py", line 921, in http_error_auth_reqed

return self.retry_http_basic_auth(host, req, realm)

File "/usr/lib/python3.5/urllib/request.py", line 931, in retry_http_basic_auth

return self.parent.open(req, timeout=req.timeout)

File "/usr/lib/python3.5/urllib/request.py", line 472, in open

response = meth(req, response)

File "/usr/lib/python3.5/urllib/request.py", line 582, in http_response 'http', request, response, code, msg, hdrs)

File "/usr/lib/python3.5/urllib/request.py", line 510, in error return self._call_chain(*args)

File "/usr/lib/python3.5/urllib/request.py", line 444, in _call_chain result = func(*args)

File "/usr/lib/python3.5/urllib/request.py", line 590, in http_error_default

raise HTTPError(req.full_url, code, msg, hdrs, fp)

Python 不是我喜欢的语言，所以我不知道该怎么做。这是一个应该访问我的 Gmail 帐户并从中提取新邮件的脚本。你们有什么建议吗？我正在使用 Arch Linux，如果有帮助的话。

Answer 1

变体 A：
运行 此脚本为 python3.4 /path/to/script

变体 B：
将 schebang 更改为 #!/usr/bin/python3.4