php 下载脚本错误

Question

我用这个功能来下载link:

    <?php    
function downloadFile($fileLocation,$fileName,$maxSpeed = 13,$doStream =
false){
    if (connection_status()!=0) return(false);
    $extension = strtolower(end(explode('.',$fileName)));

    /* List of File Types */
    $fileTypes['swf'] = 'application/x-shockwave-flash';
    $fileTypes['pdf'] = 'application/pdf';
    $fileTypes['exe'] = 'application/octet-stream';
    $fileTypes['zip'] = 'application/zip';
    $fileTypes['doc'] = 'application/msword';
    $fileTypes['xls'] = 'application/vnd.ms-excel';
    $fileTypes['ppt'] = 'application/vnd.ms-powerpoint';
    $fileTypes['gif'] = 'image/gif';
    $fileTypes['png'] = 'image/png';
    $fileTypes['jpeg'] = 'image/jpg';
    $fileTypes['jpg'] = 'image/jpg';
    $fileTypes['rar'] = 'application/rar';    

    $fileTypes['ra'] = 'audio/x-pn-realaudio';
    $fileTypes['ram'] = 'audio/x-pn-realaudio';
    $fileTypes['ogg'] = 'audio/x-pn-realaudio';

    $fileTypes['wav'] = 'video/x-msvideo';
    $fileTypes['wmv'] = 'video/x-msvideo';
    $fileTypes['avi'] = 'video/x-msvideo';
    $fileTypes['asf'] = 'video/x-msvideo';
    $fileTypes['divx'] = 'video/x-msvideo';

    $fileTypes['mp3'] = 'audio/mpeg';
    $fileTypes['mp4'] = 'audio/mpeg';
    $fileTypes['mpeg'] = 'video/mpeg';
    $fileTypes['mpg'] = 'video/mpeg';
    $fileTypes['mpe'] = 'video/mpeg';
    $fileTypes['mov'] = 'video/quicktime';
    $fileTypes['swf'] = 'video/quicktime';
    $fileTypes['3gp'] = 'video/quicktime';
    $fileTypes['m4a'] = 'video/quicktime';
    $fileTypes['aac'] = 'video/quicktime';
    $fileTypes['m3u'] = 'video/quicktime';

    $contentType = $fileTypes[$extension];


    header("Cache-Control: public");
    header("Content-Transfer-Encoding: binary\n");
    header("Content-Type: $contentType");

    $contentDisposition = 'attachment';

    if($doStream == true){
        /* extensions to stream */
        $array_listen = array('mp3','m3u','m4a','mid','ogg','ra','ram','wm',
        'wav','wma','aac','3gp','avi','mov','mp4','mpeg','mpg','swf','wmv','divx','asf');
        if(in_array($extension,$array_listen)){ 
            $contentDisposition = 'inline';
        }
    }

    if (strstr($_SERVER['HTTP_USER_AGENT'], "MSIE")) {
        $fileName= preg_replace('/\./', '%2e', $fileName,
substr_count($fileName, '.') - 1);
        header("Content-Disposition: $contentDisposition; filename=".$fileName);
    } else {
        header("Content-Disposition: $contentDisposition; filename=".$fileName);
    }

    header("Accept-Ranges: bytes");   
    $range = 0;
    $size = filesize($fileLocation);

    if(isset($_SERVER['HTTP_RANGE'])) {
        list($a, $range)=explode("=",$_SERVER['HTTP_RANGE']);
        str_replace($range, "-", $range);
        $size2=$size-1;
        $new_length=$size-$range;
        header("HTTP/1.1 206 Partial Content");
        header("Content-Length: $new_length");
        header("Content-Range: bytes $range$size2/$size");
    } else {
        $size2=$size-1;
        header("Content-Range: bytes 0-$size2/$size");
        header("Content-Length: ".$size);
    }

    if ($size == 0 ) { die('Zero byte file! Aborting download');}
    set_magic_quotes_runtime(0); 
    $fp=fopen("$fileLocation","rb");

    fseek($fp,$range);

    while(!feof($fp) and (connection_status()==0))
    {
        set_time_limit(0);
        print(fread($fp,1024*$maxSpeed));
        flush();
        ob_flush();
        sleep(1);
    }
    fclose($fp);

    return((connection_status()==0) and !connection_aborted());
} 

/* Implementation */
$filename="shopfile.zip";
$location="file/";
downloadFile($location,$filename,900,false); 

?>

但是当运行时出现此错误：严格标准：在第 16

行的 /home/behzadfar/public_html/shopfile/download.php 中，仅应通过引用传递变量

警告：无法修改 header 信息 - headers 已经在 /home/behzadfar/public_html/shopfile/download 中发送（输出开始于 /home/behzadfar/public_html/shopfile/download。php:16）。 php 第 57 行

我该如何解决？

Answer 1

解决问题：您必须将实际变量传递给 end()，而不是返回数组的函数。所以：

$pieces = explode('.',$fileName);
$extension = strtolower(end($pieces));

这在 end 的 PHP's manual 中有解释。

节选

This array is passed by reference because it is modified by the function. This means you must pass it a real variable and not a function returning an array because only actual variables may be passed by reference.

没有中间变量的解

如果您不想使用中间变量，请使用 array_pop 而不是 end:

$extension = strtolower(array_pop(explode('.',$fileName)));

出现与 headers 相关的错误已经发送，因为 PHP 已经必须在页面（已交付的内容）上向您显示错误，因此它阻止了自己修改headers（一旦开始传送内容，您就无法修改 HTTP headers）。修复 strict standards 错误将修复 header 错误。

Answer 2

错误来自这一行：

$extension = strtolower(end(explode('.',$fileName)));

end()的参数通过引用传递（参见manual：mixed end ( array &$array )

因此您必须将代码更改为：

$array = explode('.',$fileName);
$extension = strtolower(end($array));

另请查看 pathinfo()，这将是一个更简洁的解决方案：

$extension = pathinfo($fileName, PATHINFO_EXTENSION);

如果它已经是标准 php 函数的一部分，为什么要自己实现这个函数。

Answer 3

你为什么不用 http://php.net/manual/en/function.finfo-file.php 替换那个数组：

$finfo = new finfo(FILEINFO_MIME_TYPE); // return mime type ala mimetype extension

$contentType =  $finfo->file($fileLocation.$filename) ;

您的脚本是以 4 开头还是以任何空格开头？？

php 下载脚本错误

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