Google 地方无法找到地图 API 可以找到的位置

Question

以下 link（地图 API）将肯辛顿圣地亚哥视为一个街区。 https://maps.googleapis.com/maps/api/geocode/json?address=kensington,%20san%20diego

{
   "results" : [
      {
         "address_components" : [
            {
               "long_name" : "Kensington",
               "short_name" : "Kensington",
               "types" : [ "neighborhood", "political" ]
            },
            {
               "long_name" : "San Diego",
               "short_name" : "San Diego",
               "types" : [ "locality", "political" ]
            },
            {
               "long_name" : "San Diego County",
               "short_name" : "San Diego County",
               "types" : [ "administrative_area_level_2", "political" ]
            },
            {
               "long_name" : "California",
               "short_name" : "CA",
               "types" : [ "administrative_area_level_1", "political" ]
            },
            {
               "long_name" : "United States",
               "short_name" : "US",
               "types" : [ "country", "political" ]
            }
         ],
         "formatted_address" : "Kensington, San Diego, CA, USA",
         "geometry" : {
            "bounds" : {
               "northeast" : {
                  "lat" : 32.777394,
                  "lng" : -117.0968502
               },
               "southwest" : {
                  "lat" : 32.755116,
                  "lng" : -117.1127622
               }
            },
            "location" : {
               "lat" : 32.7668062,
               "lng" : -117.1058848
            },
            "location_type" : "APPROXIMATE",
            "viewport" : {
               "northeast" : {
                  "lat" : 32.777394,
                  "lng" : -117.0968502
               },
               "southwest" : {
                  "lat" : 32.755116,
                  "lng" : -117.1127622
               }
            }
         },
         "place_id" : "ChIJQXneX0pU2YARsIgYMQOsyks",
         "types" : [ "neighborhood", "political" ]
      }
   ],
   "status" : "OK"
}

下面的link（地方API）找不到 https://maps.googleapis.com/maps/api/place/nearbysearch/json?location=36.26361161176487,-115.12227065576182&keyword=kensignton,%20san%20diego&rankby=distance（当然，如果没有 API 键，这个将无法工作，但即使有键，它也会以 ZERO_RESULTS 响应）

{
   "html_attributions" : [],
   "results" : [],
   "status" : "ZERO_RESULTS"
}

但是我不能使用地图 api 找到我附近的星巴克（我试过了，它把我送到了加拿大）。那么...我怎样才能搜索星巴克、街区或地址并获得合理的结果

Answer 1

我不确定你所说的 "as a neighborhood" 是什么意思，但是下面的 link 将 return 圣地亚哥肯辛顿（一定要使用你的 API 密钥). returned 的细节与地图搜索明显不同。

https://maps.googleapis.com/maps/api/place/textsearch/json?location=36.26361161176487,-115.12227065576182&query=kensignton,%20san%20diego&key=your-api-key

对于此类搜索，请尝试使用文本搜索而不是附近搜索，并将 'keyword, or name' 替换为 'query'。

转到此页面并滚动到标题为 'Text Search Requests' 的部分以了解更多信息。 https://developers.google.com/places/web-service/search

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