基于循环内加减一的计算器思维练习

Question

因此，作为一个思维练习，我一直在尝试编写一个非常简单的计算器，它可以通过加减 1 到for循环和嵌套for循环的使用。

但是我需要有关幂函数的帮助（下面代码中的最后一个方法）。由于乘法需要一个嵌套的 for 循环（下面显示的第三种方法），我认为幂函数只是再深一两层。但要么不是这种情况，要么我没有正确编码，我认为这是两者中更有可能的。

import java.util.*;

public class Main {

public static Scanner scan = new Scanner(System.in);


public static void main(String[] args) {
    Power();


}

public static void addition() {

    System.out.println("Type first number to add: ");
    int num1 = scan.nextInt();
    System.out.println("Type second number to add");
    int num2 = scan.nextInt();
    int result = num1;
    while(num2 > 0){
        num2--;
        result++;
    }

    System.out.println("The result is: " + result);

}

public static void subtraction() {

    System.out.println("Type first number to subtract: ");
    int num1 = scan.nextInt();
    System.out.println("Type second number to subtract: ");
    int num2 = scan.nextInt();
    int result = num1;
    while(num2 > 0){
        num2--;
        result--;
    }

    System.out.println("The result is: " + result);

}

public static void multiplication() {

    System.out.println("Type first number to multiply: ");
    int num1 = scan.nextInt();
    System.out.println("Type second number to multiply: ");
    int num2 = scan.nextInt();
    int result = 0;


    for(int i = num1;i>0;i--){
        for(int x = num2;x>0;x--){
            result++;
        }

    }

    System.out.println("The result is: " + result);

}

public static void division() {

    System.out.println("Type first number to divide: ");
    int num1 = scan.nextInt();
    System.out.println("Type second number to divide: ");
    int num2 = scan.nextInt();
    int result = 0;

    for(;num2>0 && num1 > num2;num2--){
        result++;
        for(;num1 > num2;num1--){

        }
    }

    System.out.println("The result is: " + result);

}

public static void Power() {

System.out.println("Type Base Number: ");
int num1 = scan.nextInt();
System.out.println("Type Exponent: ");
int num2 = scan.nextInt();
int result = 0;

for(int i = num1;i>0;i--){
    for(int x = num1;x>0;x--){
        for(int y = num2; y>0; y--){
            for(int z = num2; z>0;z--){
                result++;
            }
        }
    }

}



System.out.println("The result is: " + result);

}


}

Answer 1

你可以这样做。这有点模块化，但如果你想在一个完整的循环中使用它，你可以将乘法函数中的代码放入幂函数中。

public int mulitply(int x, int y) {
    int product = 0;
    for (int i = 0; i < y; i++) {
       for (int j = 0; j < x; j++) {
          product++;
       }
    }
    return product;
}

public int power(int x, int exponent) {
    int result = 1;
    for (int i = 0; i < exponent; i++) {
        result = multiply(result, x);
    }
    return result;
}

合并：

public int power(int x, int exponent) {
    int result = 1;
    for (int i = 0; i < exponent; i++) {            
        int product = 0;
        for (int j = 0; j < x; j++) {
            for (int k = 0; k < result; k++) {
                product++;
            }
        }
        result = product;
    }
    return result;
}

基于循环内加减一的计算器思维练习

Thought exercise on calculator based on adding or subtracting one within loops

java

calculator

exponent