Android:如何使用自定义 http header 和内容类型创建 post xml-rpc 请求

Android: how to create post xml-rpc request with custom http header & content type

我想创建 xml-rpc POST 请求,并传递 2 个参数 "application_name" & "key",并像我的代码一样将内容类型更改为 "application/x-www-form-urlencoded"下面。

try {
        XMLRPCClient oneTimeKeyClient = new XMLRPCClient(new URL(URL_REQUEST_SAMPLE), XMLRPCClient.FLAGS_DEFAULT_TYPE_STRING);
        oneTimeKeyClient.setCustomHttpHeader("X-HTTP-METHOD-OVERRIDE", "POST");

// oneTimeKeyClient.setCustomHttpHeader("Content-Type", "application/x-www-form-urlencoded");

        HashMap<String, String> oneTimeKeyParam = new HashMap<>();
        oneTimeKeyParam.put("application_name", "hello_app");
        oneTimeKeyParam.put("key", "bb5eb953d3b41dcf59f4669d98f8e14782ed83133be772956b");
        Vector<Object> params = new Vector<Object>();
        params.add(oneTimeKeyParam);

        oneTimeKeyClient.callAsync(new XMLRPCCallback() {
            @Override
            public void onResponse(long id, Object response) {
                try {
                    result = ((Map) response).get(NAME_ONE_TIME_KEY).toString();
                } catch (Exception e) {
                    Timber.e("onParseError %s", e.getMessage());
                    DialogUtil.showLoginErrorDialog(getSupportFragmentManager());
                }
            }

            @Override
            public void onError(long id, XMLRPCException error) {
                Timber.e("onError %s", error.getMessage());
                DialogUtil.showLoginErrorDialog(getSupportFragmentManager());
            }

            @Override
            public void onServerError(long id, XMLRPCServerException error) {
                Timber.e("onServerError %s", error.getMessage());
                DialogUtil.showLoginErrorDialog(getSupportFragmentManager());
            }
        }, "", params);
    } catch (Exception e) {
        Timber.e("onError %s", e.getMessage());
        DialogUtil.showLoginErrorDialog(getSupportFragmentManager());
    }

我收到错误消息“onServerError APPLICATION_NAME 必须记录不存在。”
我使用 XMLRPC 库 https://github.com/gturri/aXMLRPC .
你推荐哪个图书馆?
我可以使用 Retrofit 发出 xml-rpc 请求吗?
感谢您的帮助

你只需像这样使用改造:

@FormUrlEncoded
@POST("onetime_key")
Observable<OneTimeKeyRes> requestOneTimeKey(@Field("application_name") String applicationName, @Field("key") String key);

您必须添加 SimpleXmlConverter:

Retrofit retrofit = new Retrofit.Builder()
            .client(builder.build())
            .baseUrl(YOUR_BASE_URL)
            .addConverterFactory(SimpleXmlConverterFactory.create())
            .build();