python pypyodbc 中的“(u'24000', u'[24000] [Microsoft][ODBC SQL 服务器驱动程序]无效光标状态)”

"(u'24000', u'[24000] [Microsoft][ODBC SQL Server Driver]Invalid Cursor State)" in python pypyodbc

我要执行程序并获取输出参数

import pypyodbc

command = "DECLARE @l_Stat INT \r\n" \
                  "DECLARE @s_Ms VARCHAR(200) \r\n" \
                  "EXEC p_Log_InsertParam_2011v1 " \
                  "@l_TesterId=?, " \
                  "@l_ObiektId=?, " \
                  "@l_RejPId=?, " \
                  "@s_ParamName=?, " \
                  "@f_ParamValue=?, " \
                  "@f_ParamMinValue=?, " \
                  "@f_ParamMaxValue=?, " \
                  "@b_CheckParam=?, " \
                  "@l_Status=@l_Stat output, " \
                  "@s_Msg=@s_Ms output \r\n" \
                  "SELECT @l_Stat, @s_Ms\r\n"
connection = pypyodbc.connect(self.ConnectionString)
cursor = connection.cursor()
params=(453879185, 23192812, 645872, '/APL/CTRL_GZ/PID/SP', 35.0, 0, 0, True)
# params = (testerid,
#          obiektid,
#          rejpid,
#          paramname,
#          paramvalue,
#          paramminvalue,
#          parammaxvalue,
#          checkparam) """
result = cursor.execute(command, params)
pars = result.fetchall()[0]
print pars
if pars.__len__() >= 2:
    l_status = pars[0]
    s_msg = pars[1]
print "{}: {};".format(l_status, s_msg)

它运行良好到行 result = cursor.execute(command, params) - 程序正确执行。 当我尝试在行 pars = result.fetchall()[0]:

中获取结果时出现问题
u'24000', u'[24000] [Microsoft][ODBC SQL Server Driver]Invalid Cursor State'

我怎样才能摆脱这个错误?

当我的 p_Log_InsertParam_2011v1 存储过程 没有

时,我能够重现您的问题
SET NOCOUNT ON;

作为它的第一个可执行语句。当我在存储过程的开头添加它时,错误消失了。