根据同一数组中的另一个唯一值将一组值推送到数组

Question

问题背景

您好，我有以下剧组成员：

array:7 [▼
  0 => array:6 [▼
    "credit_id" => "52fe49dd9251416c750d5e9d"
    "department" => "Directing"
    "id" => 139098
    "job" => "Director"
    "name" => "Derek Cianfrance"
    "profile_path" => "/zGhozVaRDCU5Tpu026X0al2lQN3.jpg"
  ]
  1 => array:6 [▼
    "credit_id" => "52fe49dd9251416c750d5ed7"
    "department" => "Writing"
    "id" => 139098
    "job" => "Story"
    "name" => "Derek Cianfrance"
    "profile_path" => "/zGhozVaRDCU5Tpu026X0al2lQN3.jpg"
  ]
  2 => array:6 [▼
    "credit_id" => "52fe49dd9251416c750d5edd"
    "department" => "Writing"
    "id" => 132973
    "job" => "Story"
    "name" => "Ben Coccio"
    "profile_path" => null
  ]
  3 => array:6 [▼
    "credit_id" => "52fe49dd9251416c750d5ee3"
    "department" => "Writing"
    "id" => 139098
    "job" => "Screenplay"
    "name" => "Derek Cianfrance"
    "profile_path" => "/zGhozVaRDCU5Tpu026X0al2lQN3.jpg"
  ]
  4 => array:6 [▼
    "credit_id" => "52fe49dd9251416c750d5ee9"
    "department" => "Writing"
    "id" => 132973
    "job" => "Screenplay"
    "name" => "Ben Coccio"
    "profile_path" => null
  ]
  5 => array:6 [▼
    "credit_id" => "52fe49dd9251416c750d5eef"
    "department" => "Writing"
    "id" => 1076793
    "job" => "Screenplay"
    "name" => "Darius Marder"
    "profile_path" => null
  ]
  11 => array:6 [▼
    "credit_id" => "52fe49de9251416c750d5f13"
    "department" => "Camera"
    "id" => 54926
    "job" => "Director of Photography"
    "name" => "Sean Bobbitt"
    "profile_path" => null
  ]
]

如您所见，这是我通过 TMDb API 获得的学分列表。构建上述数组的第一步是过滤掉所有我不想显示的职位，我是这样做的：

$jobs = [ 'Director', 'Director of Photography', 'Cinematography', 'Cinematographer', 'Story', 'Short Story', 'Screenplay', 'Writer' ];

$crew = array_filter($tmdbApi, function ($crew) use ($jobs) {
    return array_intersect($jobs, $crew);
});

我的问题

我想弄清楚如何将上述结果更进一步并结合 jobs 其中 id 是相同的，以便最终得到这样的结果，因为示例：

array:7 [▼
  0 => array:6 [▼
    "credit_id" => "52fe49dd9251416c750d5e9d"
    "department" => "Directing"
    "id" => 139098
    "job" => "Director, Story, Screenplay"
    "name" => "Derek Cianfrance"
    "profile_path" => "/zGhozVaRDCU5Tpu026X0al2lQN3.jpg"
  ]

我也考虑过在我的逻辑中放弃这样做，而是在我的 blade 模板中这样做，但我不确定如何实现。

你会如何完成这个？

Answer 1

由于您正在尝试编辑数组元素及其大小，我相信 array_map() 或 array_filter() 不会是解决此问题的方法。

这是我能想到的...

$jobs = [
  'Director', 'Director of Photography', 'Cinematography',
  'Cinematographer', 'Story', 'Short Story', 'Screenplay', 'Writer'
];

$crew = [];

foreach($tmdbApi as $key => $member) {
  if($member['id'] == $id && in_array($member['job'], $jobs)) {
    if(!isset($crew[$key]))  {
      $crew[$key] = $member;
    } else {
      $crew_jobs = explode(', ', $crew[$key]['job']);
      if(!in_array($member['job'], $crew_jobs)) {
        $crew_jobs[] = $member['job'];
      }
      $crew[$key]['job'] = implode(', ', $crew_jobs);
    }
  }
}

希望这能回答您的问题:)

Answer 2

在这种情况下，您可以很好地使用 Laravel 的 Collection，它有很多方法可以在这种情况下为您提供帮助。

首先，将此数组（您已根据职位筛选的数组）转换为集合：

$collection = collect($crew);

其次，按 ids:

将此集合分组

$collectionById = $collection->groupBy('id');

现在，结果按 id 分组并转换为集合，其中键对应于id，值是 'matching' 结果的数组。有关它的更多信息 here。

最后，只是一个简单的脚本，它遍历每个 id 的所有结果并组合 job 字段：

$combinedJobCollection = $collectionById->map(function($item) { // get the default object, in which all fields match // all the other fields with same ID, except for 'job' $transformedItem = $item->first(); // set the 'job' field according all the (unique) job // values of this item, and implode with ', ' $transformedItem['job'] = $item->unique('job')->implode('job', ', '); /* or, keep the jobs as an array, so blade can figure out how to output these $transformedItem['job'] = $item->unique('job')->pluck('job'); */ return $transformedItem; })->values(); // values() makes sure keys are reordered (as groupBy sets the id // as the key)

此时返回此Collection：

Collection {#151 ▼ #items: array:4 [▼ 0 => array:6 [▼ "credit_id" => "52fe49dd9251416c750d5e9d" "department" => "Directing" "id" => 139098 "job" => "Director, Story, Screenplay" "name" => "Derek Cianfrance" "profile_path" => "/zGhozVaRDCU5Tpu026X0al2lQN3.jpg" ] 1 => array:6 [▼ "credit_id" => "52fe49dd9251416c750d5edd" "department" => "Writing" "id" => 132973 "job" => "Story, Screenplay" "name" => "Ben Coccio" "profile_path" => null ] 2 => array:6 [▼ "credit_id" => "52fe49dd9251416c750d5eef" "department" => "Writing" "id" => 1076793 "job" => "Screenplay" "name" => "Darius Marder" "profile_path" => null ] 3 => array:6 [▼ "credit_id" => "52fe49de9251416c750d5f13" "department" => "Camera" "id" => 54926 "job" => "Director of Photography" "name" => "Sean Bobbitt" "profile_path" => null ] ] }

注意：要将此集合用作数组，请使用：

$crew = $combinedJobCollection->toArray();

有多种方法可以实现此目的，例如：search重叠 ID 的数组，但我认为这是实现此目的的最简单方法。

祝你好运！

根据同一数组中的另一个唯一值将一组值推送到数组

Push a set of values to an array based on another unique value in the same array

php

laravel

blade

问题背景

我的问题