Django AttributeError: 'Alias' object has no attribute 'urls'
Django AttributeError: 'Alias' object has no attribute 'urls'
我刚刚为我的 Heroes 应用编写了模型：
这是我的英雄应用的 models.py 文件：
从 django.db 导入模型
# Create your models here.
class Hero(models.Model):
codename = models.CharField(max_length = 30)
profilePic = models.ImageField(blank=True) #blank makes this optional
def __str__(self):
return (self.codename)
class Stats(models.Model):
heroID = models.ForeignKey('Hero')
height = models.CharField(max_length = 10)
weight = models.CharField(max_length = 10)
STATS_CHOICES = (
('1', 'Extremely Low'),
('2', 'Very Low'),
('3', 'Low'),
('4', 'Average'),
('5', 'Good'),
('6', 'Above Average'),
('7', 'High'),
('8', 'Very High'),
('9', 'Super Human'),
('10', 'Above and Beyond'))
powers = models.CharField(max_length = 5, choices = STATS_CHOICES)
intelligence = models.CharField(max_length = 5, choices = STATS_CHOICES)
durability = models.CharField(max_length = 5, choices = STATS_CHOICES)
strength = models.CharField(max_length = 5, choices = STATS_CHOICES)
speed = models.CharField(max_length = 5, choices = STATS_CHOICES)
def __str__(self):
return (self.heroID)
class Team(models.Model):
name = models.CharField(max_length = 25)
leader = models.IntegerField
address = models.TextField
description = models.TextField
members = models.TextField
class Status(models.Model):
heroID = models.ForeignKey('Hero')
missionID = models.IntegerField
TeamID = models.IntegerField
def __str__(self):
return (self.heroID, self.missionID, self.TeamID)
class Alias(models.Model):
heroID = models.ForeignKey('Hero')
firstName = models.CharField(max_length = 25)
surname = models.CharField(max_length = 25)
formerCodeNames = models.TextField
occupation = models.CharField(max_length = 30)
address = models.TextField
citizenship = models.CharField(max_length = 40)
species = models.CharField(max_length = 40)
def __str__(self):
return (self.heroID, self.firstName, self.surname)
我在已安装的应用程序下调整了我的 settings.py 文件：
INSTALLED_APPS = [
'django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
#custom apps
'heroes',
]
然后我调整了我的 admin.py 文件：
from django.contrib import admin
# Register your models here.
from .models import Hero, Stats, Team, Status, Alias
admin.site.register(Hero, Stats)
admin.site.register(Team)
admin.site.register(Status, Alias)
在命令提示符中我输入了：python manage.py makemigrations 然后我得到了这个错误 - "AttributeError: 'Alias' object has no attribute 'urls'":
(secondproject) C:\Python34\Scripts\secondproject\heroes4Hire>python manage.py
emigrations
aceback (most recent call last):
File "manage.py", line 22, in <module>
execute_from_command_line(sys.argv)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\__init__.py", line 367, in execute_from_command_line
utility.execute()
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\__init__.py", line 359, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\base.py", line 294, in run_from_argv
self.execute(*args, **cmd_options)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\base.py", line 342, in execute
self.check()
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\base.py", line 374, in check
include_deployment_checks=include_deployment_checks,
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\base.py", line 361, in _run_checks
return checks.run_checks(**kwargs)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\checks\
istry.py", line 81, in run_checks
new_errors = check(app_configs=app_configs)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\checks\
s.py", line 14, in check_url_config
return check_resolver(resolver)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\checks\
s.py", line 24, in check_resolver
for pattern in resolver.url_patterns:
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\utils\functi
l.py", line 35, in __get__
res = instance.__dict__[self.name] = self.func(instance)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\urls\resolve
py", line 313, in url_patterns
patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\utils\functi
l.py", line 35, in __get__
res = instance.__dict__[self.name] = self.func(instance)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\urls\resolve
py", line 306, in urlconf_module
return import_module(self.urlconf_name)
File "C:\Python34\Scripts\secondproject\lib\importlib\__init__.py", line 109,
import_module
return _bootstrap._gcd_import(name[level:], package, level)
File "<frozen importlib._bootstrap>", line 2254, in _gcd_import
File "<frozen importlib._bootstrap>", line 2237, in _find_and_load
File "<frozen importlib._bootstrap>", line 2226, in _find_and_load_unlocked
File "<frozen importlib._bootstrap>", line 1200, in _load_unlocked
File "<frozen importlib._bootstrap>", line 1129, in _exec
File "<frozen importlib._bootstrap>", line 1471, in exec_module
File "<frozen importlib._bootstrap>", line 321, in _call_with_frames_removed
File "C:\Python34\Scripts\secondproject\heroes4Hire\heroes4Hire\urls.py", lin
0, in <module>
url(r'^admin/', admin.site.urls),
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\contrib\admi
ites.py", line 267, in urls
return self.get_urls(), 'admin', self.name
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\contrib\admi
ites.py", line 251, in get_urls
url(r'^%s/%s/' % (model._meta.app_label, model._meta.model_name), include(m
l_admin.urls)),
tributeError: 'Alias' object has no attribute 'urls'
这是什么意思，我该如何解决？我在 Whosebug 上看过其他类似的问题，但我不明白如何解决它。
我终于在 codebar 的聚会上得到了答案！
model.p 中的每个 class 需要在 admin.py 上单独一行。
所以答案是：
from django.contrib import admin
# Register your models here.
from .models import Hero, Stats, Team, Status, Alias
admin.site.register(Hero)
admin.site.register(Stats)
admin.site.register(Team)
admin.site.register(Status)
admin.site.register(Alias)
你应该改变
admin.site.register(Status, Alias)
至
admin.site.register(Status)
admin.site.register(Alias)
此模型应在管理中单独添加。
register函数将类的列表作为第一个参数
from django.contrib import admin
# Register your models here.
from .models import Hero, Stats, Team, Status, Alias
admin.site.register( [Hero, Stats, Team, Status, Alias] )
（tl;dr：将模型放入列表中）
遇到了同样的问题，在这里找到了解决方案，然后自己阅读了代码，并认为我会添加一些细节。
这里是寄存器函数的定义（来自django/contrib/admin/sites.py）。
def register(self, model_or_iterable, admin_class=None, **options):
...
它需要一个模型或一个可迭代对象，它做的第一件事是检查它是否有一个模型，如果有，把它放在一个列表中，然后在它上面运行主循环（第一行是'与此相关):
admin_class = admin_class or ModelAdmin
if isinstance(model_or_iterable, ModelBase):
model_or_iterable = [model_or_iterable]
for model in model_or_iterable:
...
当您将第二个模型不在列表中时，它会被传递给 admin_class 参数并被如此对待，直到最终在某处出现错误。
因此，无需多次调用此函数，您只需将所有模型放在一个列表中即可。我什至会用一个 - 该函数无论如何都会这样做，所以你只是在拯救你自己和其他人以后编辑代码时遇到这个问题。
我刚刚为我的 Heroes 应用编写了模型：
这是我的英雄应用的 models.py 文件：
从 django.db 导入模型
# Create your models here.
class Hero(models.Model):
codename = models.CharField(max_length = 30)
profilePic = models.ImageField(blank=True) #blank makes this optional
def __str__(self):
return (self.codename)
class Stats(models.Model):
heroID = models.ForeignKey('Hero')
height = models.CharField(max_length = 10)
weight = models.CharField(max_length = 10)
STATS_CHOICES = (
('1', 'Extremely Low'),
('2', 'Very Low'),
('3', 'Low'),
('4', 'Average'),
('5', 'Good'),
('6', 'Above Average'),
('7', 'High'),
('8', 'Very High'),
('9', 'Super Human'),
('10', 'Above and Beyond'))
powers = models.CharField(max_length = 5, choices = STATS_CHOICES)
intelligence = models.CharField(max_length = 5, choices = STATS_CHOICES)
durability = models.CharField(max_length = 5, choices = STATS_CHOICES)
strength = models.CharField(max_length = 5, choices = STATS_CHOICES)
speed = models.CharField(max_length = 5, choices = STATS_CHOICES)
def __str__(self):
return (self.heroID)
class Team(models.Model):
name = models.CharField(max_length = 25)
leader = models.IntegerField
address = models.TextField
description = models.TextField
members = models.TextField
class Status(models.Model):
heroID = models.ForeignKey('Hero')
missionID = models.IntegerField
TeamID = models.IntegerField
def __str__(self):
return (self.heroID, self.missionID, self.TeamID)
class Alias(models.Model):
heroID = models.ForeignKey('Hero')
firstName = models.CharField(max_length = 25)
surname = models.CharField(max_length = 25)
formerCodeNames = models.TextField
occupation = models.CharField(max_length = 30)
address = models.TextField
citizenship = models.CharField(max_length = 40)
species = models.CharField(max_length = 40)
def __str__(self):
return (self.heroID, self.firstName, self.surname)
我在已安装的应用程序下调整了我的 settings.py 文件：
INSTALLED_APPS = [
'django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
#custom apps
'heroes',
]
然后我调整了我的 admin.py 文件：
from django.contrib import admin
# Register your models here.
from .models import Hero, Stats, Team, Status, Alias
admin.site.register(Hero, Stats)
admin.site.register(Team)
admin.site.register(Status, Alias)
在命令提示符中我输入了：python manage.py makemigrations 然后我得到了这个错误 - "AttributeError: 'Alias' object has no attribute 'urls'":
(secondproject) C:\Python34\Scripts\secondproject\heroes4Hire>python manage.py
emigrations
aceback (most recent call last):
File "manage.py", line 22, in <module>
execute_from_command_line(sys.argv)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\__init__.py", line 367, in execute_from_command_line
utility.execute()
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\__init__.py", line 359, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\base.py", line 294, in run_from_argv
self.execute(*args, **cmd_options)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\base.py", line 342, in execute
self.check()
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\base.py", line 374, in check
include_deployment_checks=include_deployment_checks,
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\managem
\base.py", line 361, in _run_checks
return checks.run_checks(**kwargs)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\checks\
istry.py", line 81, in run_checks
new_errors = check(app_configs=app_configs)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\checks\
s.py", line 14, in check_url_config
return check_resolver(resolver)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\core\checks\
s.py", line 24, in check_resolver
for pattern in resolver.url_patterns:
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\utils\functi
l.py", line 35, in __get__
res = instance.__dict__[self.name] = self.func(instance)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\urls\resolve
py", line 313, in url_patterns
patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\utils\functi
l.py", line 35, in __get__
res = instance.__dict__[self.name] = self.func(instance)
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\urls\resolve
py", line 306, in urlconf_module
return import_module(self.urlconf_name)
File "C:\Python34\Scripts\secondproject\lib\importlib\__init__.py", line 109,
import_module
return _bootstrap._gcd_import(name[level:], package, level)
File "<frozen importlib._bootstrap>", line 2254, in _gcd_import
File "<frozen importlib._bootstrap>", line 2237, in _find_and_load
File "<frozen importlib._bootstrap>", line 2226, in _find_and_load_unlocked
File "<frozen importlib._bootstrap>", line 1200, in _load_unlocked
File "<frozen importlib._bootstrap>", line 1129, in _exec
File "<frozen importlib._bootstrap>", line 1471, in exec_module
File "<frozen importlib._bootstrap>", line 321, in _call_with_frames_removed
File "C:\Python34\Scripts\secondproject\heroes4Hire\heroes4Hire\urls.py", lin
0, in <module>
url(r'^admin/', admin.site.urls),
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\contrib\admi
ites.py", line 267, in urls
return self.get_urls(), 'admin', self.name
File "C:\Python34\Scripts\secondproject\lib\site-packages\django\contrib\admi
ites.py", line 251, in get_urls
url(r'^%s/%s/' % (model._meta.app_label, model._meta.model_name), include(m
l_admin.urls)),
tributeError: 'Alias' object has no attribute 'urls'
这是什么意思，我该如何解决？我在 Whosebug 上看过其他类似的问题，但我不明白如何解决它。
我终于在 codebar 的聚会上得到了答案！
model.p 中的每个 class 需要在 admin.py 上单独一行。
所以答案是：
from django.contrib import admin
# Register your models here.
from .models import Hero, Stats, Team, Status, Alias
admin.site.register(Hero)
admin.site.register(Stats)
admin.site.register(Team)
admin.site.register(Status)
admin.site.register(Alias)
你应该改变
admin.site.register(Status, Alias)
至
admin.site.register(Status)
admin.site.register(Alias)
此模型应在管理中单独添加。
register函数将类的列表作为第一个参数
from django.contrib import admin
# Register your models here.
from .models import Hero, Stats, Team, Status, Alias
admin.site.register( [Hero, Stats, Team, Status, Alias] )
（tl;dr：将模型放入列表中）
遇到了同样的问题，在这里找到了解决方案，然后自己阅读了代码，并认为我会添加一些细节。
这里是寄存器函数的定义（来自django/contrib/admin/sites.py）。
def register(self, model_or_iterable, admin_class=None, **options):
...
它需要一个模型或一个可迭代对象，它做的第一件事是检查它是否有一个模型，如果有，把它放在一个列表中，然后在它上面运行主循环（第一行是'与此相关):
admin_class = admin_class or ModelAdmin
if isinstance(model_or_iterable, ModelBase):
model_or_iterable = [model_or_iterable]
for model in model_or_iterable:
...
当您将第二个模型不在列表中时，它会被传递给 admin_class 参数并被如此对待，直到最终在某处出现错误。
因此，无需多次调用此函数，您只需将所有模型放在一个列表中即可。我什至会用一个 - 该函数无论如何都会这样做，所以你只是在拯救你自己和其他人以后编辑代码时遇到这个问题。