如何在lua中调用一个随机函数？

Question

如果if语句为真，我想调用一个随机函数怎么办？

local function move() end
local function move2() end
local function move3() end

if (statement) then
//make it choose a random function from the three which are above
end

Answer 1

您是否考虑过将这些函数放在 table 中并为要执行的函数选择随机索引？例如：

local math = require("math")

function a()
    print("a")
end

function b()
    print("b")
end

function c()
    print("c")
end

function execute_random(f_tbl)
    local random_index = math.random(1, #f_tbl) --pick random index from 1 to #f_tbl
    f_tbl[random_index]() --execute function at the random_index we've picked
end

-- prepare/fill our function table
local funcs = {a, b, c}

-- seed the pseudo-random generator and try executing random function
-- couple of tens of times
math.randomseed(os.time())
for i = 0, 20 do
    execute_random(funcs)
end

如何在lua中调用一个随机函数？

How to call a random function in lua?

lua

coronasdk