拆分字符串 space 分隔

split String by space separated

我需要用 space 分割单词 java,所以我使用了 .split 函数来实现,如下所示

String keyword = "apple mango ";
String keywords [] = keyword .split(" ");

上面的代码工作正常,但唯一的问题是我的关键字有时会包含关键字 "jack fruit""ice cream" 双引号如下所示

String keyword = "apple mango \"jack fruit\" \"ice cream\"";

在这种情况下,我需要得到 4 个词,例如 applemangojack fruit, ice cream in keywords array

谁能告诉我一些解决方案

此解决方案有效,但我确信这不是性能/资源的最佳选择。当你有超过两个单词的水果时,它也有效。欢迎编辑或优化我的代码。

public static void main(String[] args) {
        String keyword = "apple mango \"jack fruit\" \"ice cream\" \"one two three\"";
        String[] split = custom_split(keyword);
        for (String s : split) {
            System.out.println(s);
        }
    }

    private static String[] custom_split(String keyword) {
        String[] split = keyword.split(" ");
        ArrayList<String> list = new ArrayList<>();
        StringBuilder temp = new StringBuilder();
        boolean multiple = false;
        for (String s : split) {
            if (s.startsWith("\"")) {
                multiple = true;
                s = s.replaceAll("\"", "");
                temp.append(s);
                continue;
            }
            if (s.endsWith("\"")) {
                multiple = false;
                s = s.replaceAll("\"", "");
                temp.append(" ").append(s);
                list.add(temp.toString());
                temp = new StringBuilder();
                continue;
            }
            if (multiple) {
                temp.append(" ").append(s);
            } else {
                list.add(s);
            }
        }
        String[] result = new String[list.size()];
        for (int i = 0; i < list.size(); i++) {
            result[i] = list.get(i);
        }
        return result;
    }

你不能用 String.split() 做到这一点。您需要为目标标记提出一个正则表达式,并通过匹配器收集它们,如下所示:

    final Pattern token = Pattern.compile( "[^\"\s]+|\"[^\"]*\"" );

    List<String> tokens = new ArrayList<>();
    Matcher m = token.matcher( "apple mango \"jack fruit\" \"ice cream\"" );
    while( m.find() )
        tokens.add( m.group() );

我会用一个正则表达式和两个捕获组来完成,每个模式一个。我不知道任何其他方式。

    String keyword = "apple mango \"jack fruit\" \"ice cream\"";
    Pattern p = Pattern.compile("\"?(\w+\W+\w+)\"|(\w+)");      
    Matcher m = p.matcher(keyword);
    while (m.find()) {
        String word = m.group(1) == null ? m.group(2) : m.group(1);
        System.out.println(word);
    }

这将拆分引号上的字符串,然后另外用空格拆分偶数成员。

    String keyword = "apple mango \"jack fruit\" \"ice cream\"";
    String splitQuotes [] = keyword.split("\"");

    List<String> keywords = new ArrayList<>();

    for (int i = 0; i < splitQuotes.length; i++) {
        if (i % 2 == 0) {
            Collections.addAll(keywords, splitQuotes[i].split(" "));
        } else {
            keywords.add(splitQuotes[i]);
        }
    }
List<String> parts = new ArrayList<>();
String keyword = "apple mango \"jack fruit\" \"ice cream\"";

// first use a matcher to grab the quoted terms
Pattern p = Pattern.compile("\"(.*?)\"");      
Matcher m = p.matcher(keyword);
while (m.find()) {
    parts.add(m.group(1));
}

// then remove all quoted terms (quotes included)
keyword = keyword.replaceAll("\".*?\"", "")
                 .trim();

// finally split the remaining keywords on whitespace
if (keyword.replaceAll("\s", "").length() > 0) {
    Collections.addAll(parts, keyword.split("\s+"));
}

for (String part : parts) {
    System.out.println(part);
}

输出:

jack fruit
ice cream
apple
mango