从 python CGI 发送邮件 - 错误
sent mail from python CGI - Error
我正在尝试使用电子邮件输入字段从 cgi 网络控制台发送邮件,但失败并在 apache 日志中显示以下错误
Traceback (most recent call last):
File "/opt/apache-dba/cgi-bin/main.py", line 132, in <module>
mail()
File "/opt/apache-dba/cgi-bin/main.py", line 129, in mail
s.sendmail(me, you, msg.as_string())
File "/usr/lib64/python2.7/smtplib.py", line 742, in sendmail
raise SMTPRecipientsRefused(senderrs)
smtplib.SMTPRecipientsRefused: {'xxx@adp.com/': (501, '5.1.3 Bad recipient address syntax')}
但我能够 运行 相同的代码并且能够接收来自 python shell 的邮件
下面是代码,这看起来像当我 运行 来自 cgi 的代码时它试图将 mailid 从 'xxx@adp.com' 转换为 'xxx@adp.com/' 导致语法错误。
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
Emailid = xxx@gmail.com
Link='http://google.com'
def mail():
me = "GETS.INDIA.DDS.TAM@gmail.com"
you = str(Emailid)
msg = MIMEMultipart('alternative')
msg['Subject'] = "Upgrade Status Link"
msg['From'] = me
msg['To'] = you
text = '%s' % str(Link)
part1 = MIMEText(text, 'plain')
msg.attach(part1)
s = smtplib.SMTP('localhost')
s.sendmail(me, you, msg.as_string())
s.quit()
mail()
任何帮助将不胜感激,谢谢
Emailid 看起来应该是一个字符串。尝试用引号将您的测试电子邮件括起来,使其成为一个字符串。
Emailid = 'xxx@gmail.com'
我正在尝试使用电子邮件输入字段从 cgi 网络控制台发送邮件,但失败并在 apache 日志中显示以下错误
Traceback (most recent call last):
File "/opt/apache-dba/cgi-bin/main.py", line 132, in <module>
mail()
File "/opt/apache-dba/cgi-bin/main.py", line 129, in mail
s.sendmail(me, you, msg.as_string())
File "/usr/lib64/python2.7/smtplib.py", line 742, in sendmail
raise SMTPRecipientsRefused(senderrs)
smtplib.SMTPRecipientsRefused: {'xxx@adp.com/': (501, '5.1.3 Bad recipient address syntax')}
但我能够 运行 相同的代码并且能够接收来自 python shell 的邮件 下面是代码,这看起来像当我 运行 来自 cgi 的代码时它试图将 mailid 从 'xxx@adp.com' 转换为 'xxx@adp.com/' 导致语法错误。
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
Emailid = xxx@gmail.com
Link='http://google.com'
def mail():
me = "GETS.INDIA.DDS.TAM@gmail.com"
you = str(Emailid)
msg = MIMEMultipart('alternative')
msg['Subject'] = "Upgrade Status Link"
msg['From'] = me
msg['To'] = you
text = '%s' % str(Link)
part1 = MIMEText(text, 'plain')
msg.attach(part1)
s = smtplib.SMTP('localhost')
s.sendmail(me, you, msg.as_string())
s.quit()
mail()
任何帮助将不胜感激,谢谢
Emailid 看起来应该是一个字符串。尝试用引号将您的测试电子邮件括起来,使其成为一个字符串。
Emailid = 'xxx@gmail.com'